Beginners Tangent help

Question

I am new to programming and am trying really hard to understand some things but I am unclear on the trigonometry side of programming.
I know how to work out the stuff on a calculator but not in visual basic
I am trying to divide a number by inverse tan but have no idea how to do that.
This is what I have so far
Ang1 = TextBox1.Text
radians1 = Ang1 * (Math.PI / 180)
Ang1R = Math.Tan(radians1)
Ang1H = Ang1R * 1000
Ang2 = TextBox2.Text
radians2 = Ang2 * (Math.PI / 180)
Ang2R = Math.Tan(radians2)
Ang2L = Ang1H / Ang2R
RidgeAng = Ang2L / 1000
RidgeAng1 = Math.Tan(RidgeAng)
Basically you add an angle in degrees into textbox1 and textbox2 to work out an angle at which each meets. It is actually to do with working out a hip roof for architectural drafting.
The basic formula should be like this:
textbox1 = 30deg tan * 1000 = 577.35
textbox2 = 577.35 / 20deg tan = 1586.2560881221264
ridge-angle = 1586.25 / 1000 /tan-1
hip-angle = 90 - ridge-angle
Any help would be really appreciated. I am new to programming and not that good at maths so please be clear in your explanation.
Thank you.

Answer 1

Hi, thanks for the reply. Yes, I didn't show the Dims or the text box output code.
Here is the full code:
Public Class Form1
Private Sub Calculate_Click(sender As Object, e As EventArgs) Handles Calculate.Click
Dim Ang1
Dim Ang2
Dim radians1 As Double
Dim radians2 As Double
Dim Ang1R As Double
Dim Ang2R As Double
Dim Ang1H As Double
Dim Ang2L As Double
Dim RidgeAng
Dim RidgeAng1
Dim RidgeAng2
Dim HipAng
Ang1 = TextBox1.Text
radians1 = Ang1 * (Math.PI / 180)
Ang1R = Math.Tan(radians1)
Ang1H = Ang1R * 1000
Ang2 = TextBox2.Text
radians2 = Ang2 * (Math.PI / 180)
Ang2R = Math.Tan(radians2)
Ang2L = Ang1H / Ang2R
RidgeAng = 1000 / Ang2L
RidgeAng1 = Math.Atan(RidgeAng)
RidgeAng2 = Convert.ToDecimal(RidgeAng1 * (180 / Math.PI))
'Label4.Text = Ang1H
'Label5.Text = Ang2L
HipAng = 90 - RidgeAng2
RidgeAngle.Text = RidgeAng2
HipAngle.Text = HipAng
End Sub
End Class
I have also attached an image of the problem.The image is a 2D plan view of a roof. The roof is a 3D shape in reality. 2 sides of the roof are 30degrees and the other side 20degrees. I wanted to know the angle of the line (called a hip). In the image, this
angle is shown as 57.77degrees.
That was what I wanted to work out. Not sure if that makes sense to you. The way I determined the 57.77 degrees was by working out where the 30degree roof and 20 degree roof height would intersect. In this case the height is 577.35mm. For the 20degree roof
to get to that height, it would need to be at a distance of 1586.25mm perpendicular to the edge of the roof.
Does that make sense?
http://thirdistudio.com.au/roofangles-Model.jpg
It sort of makes sense.
I just meant we dont know what you mean, exactly. I looked at your picture and you are mixing horz and vertical angles so that I am not sure what you are doing and the result you are after.
Here is a vertical section through the roof showing some possible angles. We cant be sure which one you mean.
It does not matter if you have already figured out what you want now no need to hash it out.