Communication between project inside or uotside the server

Hi,
I am wondering if it is possible to communication insede deployed project. For axample i got one project how deploy the connection application chek.
It is possible to ask for the connection chek EJB to call or start another application or web page (inside the same serveur and on remote server)
thanks a lot

Basically I have a host of Unix and NT boxes with a load of different files (test results). I have a central NT server which I want all files moved onto and deployed into a specific folder structure. So I need a Java method to allow remote retrival of the data, for the NT boxes this isnt a problem.
The system will need to be able to supply the password directly to the Unix boxes without a prompt from the user. I was working on an idea of using a remote copy procedure command, but dont know if this will work properly.
If at all possible I would rather avoid having added to the client boxes as there are a large number and new systems are added often. I was hoping to have a config file, listing IP addresses and username and passwords. I know the security issues with this and am prepared to accept it.
Any help with this is greatly appreciated!

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    Public ReadOnly Property DataQueue As System.Collections.Concurrent.ConcurrentQueue(Of Byte)
    Get
    Return _DataQueue
    End Get
    End Property
    Private _Stream As NetworkStream
    Public ReadOnly Property Stream As NetworkStream
    Get
    Return _Stream
    End Get
    End Property
    Public Sub New(monitor As MonitorInfo)
    _monitor = monitor
    _DataQueue = New System.Collections.Concurrent.ConcurrentQueue(Of Byte)
    End Sub
    Private _LastReadLength As Integer
    Public ReadOnly Property LastReadLength As Integer
    Get
    Return _LastReadLength
    End Get
    End Property
    Private _Buffer(63) As Byte
    Public Sub AcceptClient(result As IAsyncResult)
    _Client = _monitor.Listener.EndAcceptTcpClient(result)
    If _Client IsNot Nothing AndAlso _Client.Connected Then
    _Stream = _Client.GetStream
    End If
    End Sub
    Public Sub AwaitData()
    _Stream.BeginRead(_Buffer, 0, _Buffer.Length, AddressOf DoReadData, Me)
    End Sub
    Private Sub DoReadData(result As IAsyncResult)
    Dim info As ConnectionInfo = CType(result.AsyncState, ConnectionInfo)
    Try
    If info.Stream IsNot Nothing AndAlso info.Stream.CanRead Then
    info._LastReadLength = info.Stream.EndRead(result)
    For Index As Integer = 0 To _LastReadLength - 1
    info._DataQueue.Enqueue(info._Buffer(Index))
    Next
    'info.SendMessage("Data Diterima " & info._LastReadLength & " Bytes")
    info.SendMessage("reply form server: " & info._LastReadLength & " Bytes")
    For Each otherInfo As ConnectionInfo In info.Monitor.Connections
    If Not otherInfo Is info Then
    otherInfo.SendMessage(System.Text.Encoding.ASCII.GetString(info._Buffer))
    End If
    Next
    info.AwaitData()
    Else
    info.Client.Close()
    End If
    Catch ex As Exception
    info._LastReadLength = -1
    End Try
    End Sub
    Private Sub SendMessage(message As String)
    If _Stream IsNot Nothing Then
    Dim messageData() As Byte = System.Text.Encoding.ASCII.GetBytes(message)
    Stream.Write(messageData, 0, messageData.Length)
    End If
    End Sub
    End Class
    'CLIENT
    Imports System.Net
    Imports System.Net.Sockets
    Public Class ClientForm
    Private _Connection As ConnectionInfo
    Private _ServerAddress As IPAddress
    Private Sub ClientForm_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load
    ValidateChildren()
    End Sub
    Private Sub ConnectButton_Checked(sender As Object, e As System.EventArgs) Handles ConnectButton.CheckedChanged
    If ConnectButton.Checked Then
    If _ServerAddress IsNot Nothing Then
    ConnectButton.Text = "Disconnect"
    ConnectButton.Image = My.Resources.StopServer
    Try
    _Connection = New ConnectionInfo(_ServerAddress, CInt(PortTextBox.Text), AddressOf InvokeAppendOutput)
    _Connection.AwaitData()
    Catch ex As Exception
    MessageBox.Show(ex.Message, "Error Connecting to Server", MessageBoxButtons.OK, MessageBoxIcon.Exclamation)
    ConnectButton.Checked = False
    End Try
    Else
    MessageBox.Show("Invlid IP Server", "Cannt Connect to Server", MessageBoxButtons.OK, MessageBoxIcon.Exclamation)
    ConnectButton.Checked = False
    End If
    Else
    ConnectButton.Text = "Connect"
    ConnectButton.Image = My.Resources.StartServer
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    _Connection = Nothing
    End If
    End Sub
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    If _Connection IsNot Nothing AndAlso _Connection.Client.Connected AndAlso _Connection.Stream IsNot Nothing Then
    Dim buffer() As Byte = System.Text.Encoding.ASCII.GetBytes(InputTextBox.Text)
    _Connection.Stream.Write(buffer, 0, buffer.Length)
    End If
    End Sub
    Private Sub ServerTextBox_Validating(sender As Object, e As System.ComponentModel.CancelEventArgs) Handles IPTextBox.Validating
    _ServerAddress = Nothing
    Dim remoteHost As IPHostEntry = Dns.GetHostEntry(IPTextBox.Text)
    If remoteHost IsNot Nothing AndAlso remoteHost.AddressList.Length > 0 Then
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    If deltaAddress.AddressFamily = AddressFamily.InterNetwork Then
    _ServerAddress = deltaAddress
    Exit For
    End If
    Next
    End If
    If _ServerAddress Is Nothing Then
    MessageBox.Show("Cannot resolve Server Address", "invalid Server", MessageBoxButtons.OK, MessageBoxIcon.Exclamation)
    IPTextBox.SelectAll()
    e.Cancel = True
    End If
    End Sub
    Private Sub PortTextBox_Validating(sender As Object, e As System.ComponentModel.CancelEventArgs) Handles PortTextBox.Validating
    Dim deltaPort As Integer
    If Not Integer.TryParse(PortTextBox.Text, deltaPort) OrElse deltaPort < 1 OrElse deltaPort > 65535 Then
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    PortTextBox.SelectAll()
    e.Cancel = True
    End If
    End Sub
    Private Sub InvokeAppendOutput(message As String)
    Dim doAppendOutput As New Action(Of String)(AddressOf AppendOutput)
    Me.Invoke(doAppendOutput, message)
    End Sub
    Private Sub AppendOutput(message As String)
    If RichTextBox1.TextLength > 0 Then
    RichTextBox1.AppendText(ControlChars.NewLine)
    End If
    RichTextBox1.AppendText(message)
    RichTextBox1.ScrollToCaret()
    End Sub
    Private Sub ButtonClear_Click(sender As Object, e As EventArgs) Handles ButtonClear.Click
    RichTextBox1.Clear()
    InputTextBox.Clear()
    End Sub
    End Class
    Public Class ConnectionInfo
    Private _AppendMethod As Action(Of String)
    Public ReadOnly Property AppendMethod As Action(Of String)
    Get
    Return _AppendMethod
    End Get
    End Property
    Private _Client As TcpClient
    Public ReadOnly Property Client As TcpClient
    Get
    Return _Client
    End Get
    End Property
    Private _Stream As NetworkStream
    Public ReadOnly Property Stream As NetworkStream
    Get
    Return _Stream
    End Get
    End Property
    Private _LastReadLength As Integer
    Public ReadOnly Property LastReadLength As Integer
    Get
    Return _LastReadLength
    End Get
    End Property
    Private _Buffer(63) As Byte
    Public Sub New(address As IPAddress, port As Integer, append As Action(Of String))
    _AppendMethod = append
    _Client = New TcpClient
    _Client.Connect(address, port)
    _Stream = _Client.GetStream
    End Sub
    Public Sub AwaitData()
    _Stream.BeginRead(_Buffer, 0, _Buffer.Length, AddressOf DoreadData, Me)
    End Sub
    Public Sub Close()
    If _Client IsNot Nothing Then _Client.Close()
    _Client = Nothing
    _Stream = Nothing
    End Sub
    Private Sub DoreadData(result As IAsyncResult)
    Dim info As ConnectionInfo = CType(result.AsyncState, ConnectionInfo)
    Try
    If info._Stream IsNot Nothing AndAlso info._Stream.CanRead Then
    info._LastReadLength = info._Stream.EndRead(result)
    If info._LastReadLength > 0 Then
    Dim message As String = System.Text.Encoding.ASCII.GetString(info._Buffer)
    info._AppendMethod(message)
    End If
    info.AwaitData()
    End If
    Catch ex As Exception
    info._LastReadLength = -1
    info._AppendMethod(ex.Message)
    End Try
    End Sub
    End Class
    //ScreenShot server
    http://prntscr[dot]com/5t1ol3
    //Screenshot client
    http://prntscr[dot]com/5t1odj
    source: code[dot]msdn[dot]microsoft[dot]com/windowsdesktop/Simple-Multi-User-TCPIP-43cc3b44

    I have a similar chat application. When the user attempts to connect, instead of sending a simple string, the client sends a serialized object(xml string) with all relevant login and session information, this includes the user's IP address. Once the server
    receives said information, depending on the type of TCP broadcast (a custom enumerated type) information from one user may be passed to a single user, or distributed to many users.
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    Option Explicit On
    Option Infer Off
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    Public Property PasswordHash As String
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    End Function
    Public Shared Function FromBinary(binary As Byte()) As DeserializationResult
    Dim xml As String = System.Text.Encoding.UTF8.GetString(binary)
    Return FromXML(xml)
    End Function
    Public Shared Function FromXML(xml As String) As DeserializationResult
    Dim DeserializationResult As New DeserializationResult
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    Try
    Dim deserializer As New Xml.Serialization.XmlSerializer(GetType(TCPBroadcast))
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    End Using
    Catch ex As Exception
    DeserializationResult.Error = True
    DeserializationResult.ErrorMessage = ex.ToString
    DeserializationResult.AttemptedXML = xml
    End Try
    Return DeserializationResult
    End Function
    Public Class DeserializationResult
    Public [Error] As Boolean
    Public ErrorMessage As String
    Public tcpBroadCast As TCPBroadcast
    Public AttemptedXML As String
    Sub New()
    End Sub
    End Class
    Public Enum TCPBroadcastType
    AdministrativeMessage
    AuthenticationFailure
    AuthenticationSuccess
    ChatBroadcast
    CredentialsRequest
    Credentials
    DisconnectedByServer
    KeepAlive
    PrivateMessage
    ServerMessage
    SystemMessage
    UnableToProcessRequest
    End Enum
    End Class
    End Namespace
    “If you want something you've never had, you need to do something you've never done.”
    Don't forget to mark
    helpful posts and answers
    ! Answer an interesting question? Write a
    new article
    about it! My Articles
    *This post does not reflect the opinion of Microsoft, or its employees.

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