Console Exception Handling. Allow another attempt for user before exiting

Question

I am trying to implement a very simple program that prompts the user for info and reads in a few numbers. If the user accidentally enters a letter instead of a number I want the user to get another chance, not just execute the exception handler and exit the program (as it does now). I'd rather have the user get stuck in an endless loop waiting for valid input versus exiting on the first invalid entry.
The code I am using is something like this:
try{
   System.out.println("Enter a number?");
   int b=System.in.read();
   char c=(char) b;
   String s=String.valueOf(c);
   p.setDummyValue(Integer.parseInt(s) ); //**Possible Exception Here
catch(NumberFormatException e) {
   System.out.println("Invalid Input");
   // *** I'd love to somehow return to the "Enter a number" line from here
catch(IOException e) {
   //IO error code here
}Q: How can I implement the ability to allow a user to correct invalid input?
Thanks

Answer 1

Something like this should work:boolean numberValid = false;
while (!numberValid) {
     try {
          System.out.println("Enter a number?");
          int b=System.in.read();
          System.in.skip(System.in.available()); // skip carriage return
          char c=(char) b;
          String s=String.valueOf(c);
          p.setDummyValue(Integer.parseInt(s));
          numberValid = true;
     } catch(NumberFormatException e) {
          System.out.println("Invalid Input");
     } catch(IOException e) {
          //IO error code here
}