Count the all null values in the given table

Question

Suppose a table has n number of rows and columns .
can any one tell the query to count the number of null values present in the table.
For example :
select * from tname:
A      B
cc    jhghf
hff      -
-       kjh
tys     -
-        gyrfg
jjgg      -
jfgh      -
-        uytg
10 rows selected..
now to count the null vales in the table we can use --->   select count(1)-count(a)+count(2)-count(b) as ncount  from tname;
                                                                                  o/p:
                                                                                          ncount
                                                                                           11
now my questions is we have n number of columns now pls tel tell me how to count the nulls present in table..?
Thanks in Advance.

Answer 1

Object[][] o;
int tot = 0;
for(int x = 0 ; x < o.length ; x++)
   tot += o[x].length;
}If it's not a jagged array, however, this would be easier:
int tot = o.length * o[0].length;