Creating SYNONYM for all tables who don't have one at once!

Question

Hello to all,
I'm trying to create synonyms for every table who's missing one at the moment. I'm trying this code:
declare
cursor cur_objects is
select obj.object_name , obj.owner
from all_objects obj
where owner = '&&SCHEMA_OWNER'
AND NOT EXISTS (SELECT *
FROM all_synonyms syn
WHERE obj.object_name = syn.table_name)
AND obj.object_type = 'TABLE'
AND obj.object_name LIKE 'CI_%';
begin
for rec_objects in cur_objects loop
begin
dbms_output.put_line(rec_objects.object_name);
execute immediate('create public synonym ' || rec_objects.object_name || ' for '
|| rec_objects.owner ||'.'||rec_objects.object_name )
exception when others then
null;
end;
end loop;
end;
I'm getting this error:
ORA-06550: line 10, column 37:
PLS-00103: Encountered the symbol "end-of-file" when expecting one of the following:
begin function package pragma procedure subtype type use
<een ID>
<een scheidingsteken-ID tussen dubbele aanhalingstekens> form
current cursor
I'm still pretty new at PL/SQL and can't get it to work. Does anyone got any tips ?
Thnx already

Answer 1

Ok now I got this error:
RA-06550: line 17, column 1:
PLS-00103: Encountered the symbol "EXCEPTION" when expecting one of the following:
* & = - + ; < / > at in is mod remainder not rem return
returning <een exponent (**)> <> or != or ~= >= <= <> and or
like LIKE2_ LIKE4_ LIKEC_ between into overlaps using ||
multiset bulk year DAY_ member SUBMULTISET_
The symbol ";" was substituted for "EXCEPTION" to continue.