Curve 8330 first time synch with data loaded into smartphone

With other smartphones, when I would perform my FIRST synch, if I did not take certain precautions (preset synch software to specific settings) I would wipe out all data on smartphone . Is this true for the Curve 8330? Are there specific settings so when I synch my phone for the first time with data I already loaded, I do not wipe it clean?

Hey TomPortua,
Welcome to the BlackBerry Support Community Forums.
The first synchronization does not erase the data on the BlackBerry Smartphone unless synchronization options are configured to "Replace all data in the target application", by default this is not selected if it is configured for Two way sync.
Have a look at this article for more information no configuring the Desktop software for Synchronization:
http://www.blackberry.com/btsc/KB23681
I hope this helps, cheers!
-HB
Come follow your BlackBerry Technical Team on twitter! @BlackBerryHelp
Be sure to click Kudos! for those who have helped you.Click Solution? for posts that have solved your issue(s)!

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DEFINE T_TIME DIMENSION TEXT
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200401
200402
200403
200404
200405
200406
200407
200408
200409
200410
200411
2004
200412
200501
200502
200503
200504
200505
200506
200507
200508
200509
200510
200511
2005
200512
DEFINE T_TIME_PARENTREL RELATION T_TIME <T_TIME T_TIME_HIERLIST>
-----------T_TIME_HIERLIST-------------
T_TIME H_TIME
200401 2004
200402 2004
200403 2004
200404 2004
200405 2004
200406 2004
200407 2004
200408 2004
200409 2004
200410 2004
200411 2004
2004 NA
200412 2004
200501 2005
200502 2005
200503 2005
200504 2005
200505 2005
200506 2005
200507 2005
200508 2005
200509 2005
200510 2005
200511 2005
2005 NA
200512 2005
DEFINE PRUEBA2_IMPORTE FORMULA DECIMAL <T_TIME>
EQ -
aggregate(this_aw!PRUEBA2_IMPORTE_STORED using this_aw!OBJ262568349 -
COUNTVAR this_aw!PRUEBA2_IMPORTE_COUNTVAR)
T_TIME PRUEBA2_IMPORTE
200401 NA
200402 NA
200403 2,00
200404 2,00
200405 NA
200406 NA
200407 NA
200408 NA
200409 NA
200410 NA
200411 NA
2004 4,00 ---> here its right!! but...
200412 NA
200501 5,00
200502 15,00
200503 NA
200504 NA
200505 NA
200506 NA
200507 NA
200508 NA
200509 NA
200510 NA
200511 NA
2005 10,00 ---> here must be 30,00 not 10,00
200512 NA
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200401 NA
200402 NA
200403 NA
200404 NA
200405 NA
200406 NA
200407 NA
200408 NA
200409 NA
200410 NA
200411 NA
2004 NA
200412 NA
200501 5,00
200502 15,00
200503 NA
200504 NA
200505 NA
200506 NA
200507 NA
200508 NA
200509 NA
200510 NA
200511 NA
2005 10,00
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AGGMAP
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CACHE NONE
END
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Regards,
Mel.

Mel,
There are several different types of "data loaded into different hierarchy levels" and the aproach to solving the issue is different depending on the needs of the application.
1. Data is loaded symmetrically at uniform mixed levels. Example would include loading data at "quarter" in historical years, but at "month" in the current year, it does /not/ include data loaded at both quarter and month within the same calendar period.
= solved by the setting of status, or in 10.2 or later with the load_status clause of the aggmap.
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= the aggregate command overwrites aggregate values based on the values of the children, this is the only repeatable thing that it can do. The recomended way to solve this problem is to create 'self' nodes in the hierarchy representing the data loaded at the aggregate level, which is then added as one of the children of the aggregate node. This enables repeatable calculation as well as auditability of the resultant value.
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200409 2004
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200506 2005
200507 2005
200508 2005
200509 2005
200510 2005
200511 2005
200512 2005
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2005 NA
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200407 NA
200408 NA
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200410 NA
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= this can currently only be solved by issuing multiple aggregate commands to aggregate the different regions with different input status, which unfortunately means that it is not compatable with compressed composites. We will likely add better support for this case in future releases.
4. Data is loaded at both an aggregate level and a detail level, but the calculation is more complicated than a simple SUM operator.
= often requires the use of ALLOCATE in order to push the data to the leaves in order to correctly calculate the aggregate values during aggregation.

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