Days of a month using Calender

Hi,
I have a requirement to get number of days for a month for the input of month and year.
Please anyone help me to know whether any API is available in java? (Can we use Calender/Date?)
-V

Can we use Calender/Date?You can set the time of a calendar to that represented by a date.

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SSAS Tabular - return number of days in given month using month's start date?

Is there a way to return the number of days in a month by providing just the month date or month start date?
We have a time table, but it is at monthly (not daily) granularity.
So I can't just count rows between start/end of month.
I need to be able to divide by the number of days in a given month and can't seem to find a way to get number of days in that given month.
Thanks!

Hi,
According to your description, you want to get the number of days in a month with the month's start date, right?
In this case, we can get the first day of next month using DateAdd function, and then use DateDiff function to calculate the number of days in this month. Here is a sample query for your reference.
WITH
MEMBER Measures.Today AS vba!Now()
member measures.FirstDayOfNextMonth as dateadd("m",1,Measures.Today)
member measures.daysnumber as datediff("d",Measures.Today,measures.FirstDayOfNextMonth)
select Measures.daysnumber on 0
from
[Adventure Works]
Reference
http://msdn.microsoft.com/en-us/library/hh510163.aspx
http://office.microsoft.com/client/helppreview14.aspx?AssetId=HV080007558&lcid=1033&NS=EXCEL%2EDEV&Version=14&tl=2&pid=CH080007543
http://office.microsoft.com/client/helppreview14.aspx?AssetId=HV080007559&lcid=1033&NS=EXCEL%2EDEV&Version=14&tl=2&pid=CH080007543
Regards,
Charlie Liao
TechNet Community Support

No of day in a month

I want to count the number of days for a month using sysdate and then multiply it with an amount. how do i do that . for eg
if my sysdate is 27th june then june being a 30 days month i need to multiply 30 with the ammount.
Ammount * 30.
if my sysdate is 27 feb then i need to count the no of days in the month that is 28 (if its a leap year then 29) and then multiply amount * 28.
How do i achive this in my formula .
Please help thanks

May be this?
select to_char(Last_day(sysdate),'DD') * amount FROM table

How to get last day of a month

using pl/sql
What i need is that all members whose birthdate is in the curren month will be included as having had their birthdate regardless of the date of the month. The code i have is:
Select me607.subscriber_id
me607.mbr_dob,
** trunc(months_between (*end of current month*,me607.mbr_dob) / 12) as age
from odw.mbr607_member_expanded me607
The asterixed line is what I need to change. If I put the end of the current month (where I put 'end of current month') then all those whose birthday month is in Feb will show as having had their birthdate. So if run today, folks whose birthdate is 26-feb-2005 will show an age of 5.
When grabbing the last day of the month using visual basic I just use the first day of the subsequent month minus 1. Any assistance is appreciated..

Hi,
This does what you requested:
Select me607.subscriber_id,     -- Don't you need a comma here?
     me607.mbr_dob,
     ROUND ( MONTHS_BETWEEN ( SYSDATE
                            , me607.mbr_dob
           / 12
from    odw.mbr607_member_expanded     me607
WHERE     TO_CHAR (me607.mbr_dob, 'MONTH') =
     TO_CHAR (SYSDATE,      'MONTH')
;If this is run sometime in February, 2010, and mbr_dob is sometime in Febrary, 2005, then the result of MONTHS_BETWEEN will be between 59 and 61. When we divide by 12 convert that to years, that difference of up to one month becomes so small that it will be lost in the rounding.
If this isn't exactly what you need, tthen post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data.
Edited by: Frank Kulash on Feb 17, 2010 1:32 PM
Added explanation.

Show data of last day of previous month against any day of current month

Hi,
I have fact table which contains data at date level (we have data for oct-2009 to april-2010). Our requirement is to show data of last day of previous month against any day of current month in obiee 11g. I am facing problem in Feb 2010 its picking data of 28-Jan-2010 instead of 31-jan-2010 and for April its picking data of 30-mar-2010 instead of 31-mar -2010.
Any suggestion ???

You're asking to filter your data set to only include rows between:
1) last day of the previous month
2) any day of the current month
This can be achieved with prompting in OBIEE Answers.
last day of previous month = TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE)) . The problem is you need to make query work within Oracle's Answer syntax.
In the prompt, select the operator type for your date dimension as 'between' and default to 'SQL Results'.
For the 'last day of previous month' , use the query:
SELECT
case when 1=0 then Time."Fiscal Date" else TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))
end
FROM ENTER_YOUR_PRESENTATION_FACT_FOLDER_HERE
For the current date, use the query:
SELECT
case when 1=0 then Time."Fiscal Date" else CURRENT_DATE
end
FROM ENTER_YOUR_PRESENTATION_FACT_FOLDER_HERE
Another option is to create a last_date_pervious_month variable in the RPD and have that as the default value in your prompt.

How to calculate the number of days until your next birthday. Only using current month, day and birth month and day.

I'm trying to calculate the number of days until your next birthday. Only using current month, day and birth month and day. I can get close but i'm way off. When i enter in the next day, the amount of days is supposed to be 364. This is where I am having problems. I know my code is way off. I just need some guidance please!
Attachments:
D5.7_1.vi ‏8 KB

I just had a little fun with the Time Record...
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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How to get the last day of a month?

HI,
I want to know how to get the last day of a month.
In my JClient form, I tried to get it by using oracle.sql.Date method, that is:
lastday=oracle.sql.Date anydate.lastDayOfMonth();
But it does not work. The result is lastday=anydate.
Why?
Stephen

You can use the Calender class...
Calendar c = Calendar.getInstance();
and then something like...
c.add(c.MONTH, 1);
int dayOfMonth = c.get(Calender.MONTH);
c.add(c.DAY_OF_MONTH, - (dayOfMonth-1) );
other usefull functions are:
System.out.println(" YEAR : " + c.get(Calendar.YEAR));
System.out.println(" MONTH : " + c.get(Calendar.MONTH));
System.out.println(" DAY_OF_MONTH : " + c.get(Calendar.DAY_OF_MONTH));
System.out.println(" DAY_OF_WEEK : " + c.get(Calendar.DAY_OF_WEEK));
System.out.println(" DAY_OF_YEAR : " + c.get(Calendar.DAY_OF_YEAR));
System.out.println(" WEEK_OF_YEAR : " + c.get(Calendar.WEEK_OF_YEAR));
System.out.println(" WEEK_OF_MONTH : " + c.get(Calendar.WEEK_OF_MONTH));
System.out.println(" DAY_OF_WEEK_IN_MONTH : " + c.get(Calendar.DAY_OF_WEEK_IN_MONTH));
System.out.println(" HOUR : " + c.get(Calendar.HOUR));
System.out.println(" AM_PM : " + c.get(Calendar.AM_PM));
System.out.println(" HOUR_OF_DAY (24-hour): " + c.get(Calendar.HOUR_OF_DAY));
System.out.println(" MINUTE : " + c.get(Calendar.MINUTE));
System.out.println(" SECOND : " + c.get(Calendar.SECOND));
System.out.println();*/

No of days in a month in Query designer

Hi
I have Calender Year/Month (0CALMONTH) in the row of query, I need to show no of days in that month, how can I do this in Query designer

Hi,
If the user requirment is to select a single month for analysis then you could possibly use a formula variable that is populated as a user exit to return the number of days in the month selected and then use this in your calculation.
This formula varible can be hidden from display in the query designer.
hope it gives you an idea.
regards,
CH

Find number of days in current month

Hi Folks ,
I needed some help in knowing the number of days in any month ... I need to develop an application which will be triggering a mail with an excel attachment at the end of every month ...after populating the excel sheet from an Oracle database ..
Kindly help...
Thx..

Thx a lot for your immediate reply .. I tried using
the calender class. But for my application .. i need
to automate this process by sending a mail every last
day of the month... but i am finding it a bit
difficult to really automate setting the current
month to the Timer class
Timer timer;
     public Reminder ( int seconds ) {
          timer = new Timer ( ) ;
timer.schedule( new RemindTask ( ), seconds*1000
000 ) ;
     }The Calendar class is still the best solution IMHO.

How do I find the start day of each month

Hi all,
Hope someone can give a a hand here I've to do a calender project for college and I'm not allowed to use any built in Java classes so fun all the way so far :-)
I've got one question that is bugging me at the moment. and that is how to find the start day for each month in a year and store them in an array.
I'm starting my week at Monday (0) and stopping at Sunday (6) and I do have a formula for discovering the first day in Jan of the given year its
((y-1900)*365 + (y-1901)/4)%7
I was just wondering how I could amend this to find the first day in Feb, March etc.
Any suggestions greatly accepted.
Thanks in advance.

Irish-Student wrote:
newark maybe I didnt make clear exactly what I want to do.
I have each day of the week starting at 0 for Monday up to 6 for Sunday I want to map what the start day of a month as a number between 0 and 6.
The formula I have discovering the first day of Jan of a given year will give you 1 i.e. Tuesday
what I need to do is find out what number between 0 and 6 the start day of each other month of a given year is.
For example the 1st of Feb is a Friday which is 4 on the weekday map.
Your suggestion of 31%7 won't work for this, sorry more than likely my fault for not being clearer in what my requirements were.
Cheers for the help so far and yep your right not being able to use the built in classes is a pain :-)
Edited by: Irish-Student on 03-Mar-2008 20:01This doesn't really change much of my first suggestion. If you can already calculate the first day of the month of January for any given year, then there's no problem figuring out the other months. Say I want to know the first day April 1, 1978. You already know how to find January 1, 1978. So find that. Then find the number of days between January 1 and April 1 (remember to account for leap years). Once you have the number of days, you can figure out how many weeks and days that is, and thus what day of the week it is.

How can I set an event to repeat on a week day rather than a numerical day of each month?

How can I set an event to repeat on a week day rather than a numerical day of each month? I see an option at the bottom of the repeat window .... but I cannot use it. Actually, when I try it freezes up my Calendar.
Lorrene Baum Davis

These scrrenshots are from Snow Leopard - I would think that Lion wouldn't be too much different.

Defining last day of previous month in ABAP

All,
I am a BW guy and hardly know ABAP. I have a requirement where I have to calculate last day of previous month and use it in the routines of the transformations.
I have decided to define the Last day of previous month in Start routine and then use the global variable in Transformations to calculate further.
The logic that i have used is outlined below.
         Define G_DATE in global declaration for further use in Transformations.
In the Routine section,
        Assign G_DATE to SY-DATUM
        G_DATE + 6(2) = '01' (Replace last to field of date with '01' to establish first day of the current month)
        G_DATE = G_DATAE - 1 (To get to last day of previous month)
My dilemma is to implement this in ABAP in Start routine of transformations. Please include the exact ABAP code that would be needed in Declarations and Routine section.
Thanks in advance.

Hi..,
Go with the function module: LAST_DAY_OF_MONTHS
So, Just determine the last month from the sy-datum and then use above function module and pick the last date of the month.
Thanks,
Naveen Inuganti.

Successive dates with last day of that month being added to succesive date

Hi ,
I have a piece of code that displays the succuessive dates from the given date to tilll date with a date interval of 30 days. My requirement goes some thing like this. since the given date is '26-nov-08' the next successive date should be the number of days in nov(30) added to '26-nov-08'. that will be around 26-dec-08. For this date it has to add the number of days in December(31) to '26-dec-08' and that turns out to be '26-jan-09'. and this must go on till date.
In the below code i have used 30 for the interval of 30 days but the interval has to the last day of the successive date's month( for dec the interval has to 31 and for january the interval has to be 31 and for february 28)
select to_date('26-nov-08', 'dd-mon-yy') + (level - 1) * 30
from dual
connect by level <= trunc((sysdate-to_date('26-nov-08', 'dd-mon-yy'))/30 )Please advice

hi ,
the query sent by you is correct and could it be in corporated for this query :
SELECT TRUNC(inst_due_date) + (LEVEL-1 ) * (ilpa_term_type),iloan_code,LOAN_AMT,FEE_AMT,
LOAN_DATE,LOAN_STATUS_ID
FROM (
SELECT inst_due_date,sm.iloan_code,LOAN_AMT,
FEE_AMT,
LOAN_DATE,
LOAN_STATUS_ID,
decode(sm.ilp_term_type, 26 ,14,24,15,12,(select to_number(to_char(last_day(inst_due_date),'dd')) from dual)) as ilpa_term_type
FROM ST_IL_SCHEDULE sc,ST_IL_MASTER sm
WHERE sc.iloan_code = sm.iloan_code
AND sc.inst_num = (SELECT MAX(inst_num) FROM ST_IL_SCHEDULE b WHERE b.iloan_code = sc.iloan_code)
AND sc.iloan_code =123456789)
CONNECT BY LEVEL <= TRUNC((TRUNC(SYSDATE)-TRUNC(inst_due_date))/(ilpa_term_type) )
Here we are using the decode concept if ilp_term_type = 26 then 14 but we need to implement the code of adding the number of days to that month in place of this code :
select to_number(to_char(last_day(inst_due_date),'dd')) from dual:
Please advice

Display a metric differently only on last day of the month.

Have a Daily transaction fact where unit cost of product is stored at a day/part num /business unit level.
When we drag and drop date column and unit cost in the report like below we will have
Date      cost
Sep29     $10
sep30     $12
Oct1       $12
Oct2       $14
..........ans so on
The source sustem program runs on last day of the month around 8pm for setting up cost to reflect on 1st of every month
But the nighly OBI load ( Runs at 2am every day) when incrementally updating Sep30 data picks up $12 from the erp and populates in OBI.
But actually speaking, on Sep30 the cost was $10.
There is no way of running the ERP program to run afer OBI load. Hence we need an expression in the RPD (not answers) saying
when last day of the month (any month) the standard cost must be a previous day value.All other days the same value should be returned.
Is this possible without impacting report performance ?
So, when we drag and drop date and cost value the above report should change as
Date        Cost
sep29     $10
sep30     $10
Oct1       $12
Oct2       $14
Oct30     $12.5
Oct31     $12.5
Nov1      $13.5

You can achieve the above requirement for current month alone with below steps:
The solution requires to have a union report
First part of the report will have Date and Cost fields with a report level date filter, Date NOT IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))
Second part of the report will have Date and Cost fields with a report level date filter Date IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))In the second part of the report,
Change the column formula for Date to display only Current_Date
Change the column formula for Cost field with FILTER(Cost USING Date = Current_Date-1)
Pls mark if correct/helpful.

Current day and no of days in current month

Hi all,
can anbody tell me which object is used for current day and no of days in current month.

Hi,
USe /OSP/GET_DAYS_IN_MONTH Function Module, just give Date you will get No. Of days in that Month.
Use SY-DATUM for current date.
Ex:
Data: dt type SY-DATUM.
dt = SY-DATUM.
so you get current date in dt.
Thanks
Reddy

Days of a month using Calender

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