Delete or discard an outbound container programmatically

Is It possible to delete or discard an outbound container programmatically?
My problem is when the Synchronization process fails and I try to sync again, the information is sent twice in two different outbound cointers. What I want to do is always delete all the containers before i proceed with the synchronization process in order to avoid the duplicity.
Edited by: Gerardo Silva on Jul 21, 2010 8:16 PM

Hello Rohith,
Thank you for your response. My application is an AWT-based application, I'm using Generic Synchronization and it runs in handheld devices. My MI version is 7.00 SP14
The problem occurs when I try to sync my device and the device loses the network connection in middle of processing.
When I sync again, the container created in the first synchronization and the new one created in the second synchronization are sent to SAP causing the duplicity.
As I have already mentioned the closest solution that I have found so far is to verify the existence of previous containers. If there is a pending one I avoid the creation of new containers
if(!InboundProcessorRegistry.getInstance().isAlreadyInOutboundQueue(R3_METHOD_GET_PICKING_INFO,VisibilityType.SEPARATED))
OutboundContainer out = outfactory.createOutboundContainer(VisibilityType.SEPARATED,METHOD_NAME,OutboundContainer.TYPE_REQUEST);
out.close();
It covers my need but I´m just wondering If there is other solution.
I hope this clarifies my question
Best Regards

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