Design confusion

Question

hi, I've been writing this program for a while now and its starting to get a bit confusing. In one class I have three functions - one for retrieving an integer, one for retrieving a string and another for retrieving a coordinate from a file but I don't know how I should throw the Exceptions:
   public int getInteger(String content, int fromIndex) throws Exception {
      int integer = 0;
      int index1 = content.indexOf('(', fromIndex),
          index2 = content.indexOf(')', fromIndex);
      if(index1 > 0 && index2 > 0) {
         try {
            integer = Integer.parseInt(content.substring(index1+1, index2));
         } catch(NumberFormatException e) {
            throw new NumberFormatException();
      } else { throw new IndexException(); }
      return integer;
   }this extracts the first integer in brackets (int) from a string but I want to put this method in a try block evertime I call it and catch the exceptions that occur. My two questions are:
can you throw an integer (like in c++) with java?
and
will the NumberFormatException be thrown even if I don't catch it and then throw it because you can call the parseInt method without placing it in a try block.

Answer 1

the IndexException was just to identify what exception occurred - its just an empy class that extends Exception. that why I was asking if i could just throw an integer value like in c++:
// exceptions
#include <iostream>
using namespace std;
int main () {
  try
    throw 20;
  catch (int e)
    cout << "An exception occurred. Exception Nr. " << e << endl;
  return 0;
}I don't know if it is forbidden to post c++ code in a java forum but i've done it anyway.
thats from the c++ language tutorial:
http://www.cplusplus.com/doc/tutorial/exceptions.html
I basically want to know wheter the number between the brackets was an invalid integer or if the string contained the brackets in the first place.
what were you meaning about overdoing the exceptions? what other way could I do it.