Display columns as rows from non-unique key table

Question

Hi OTN/Users, I hope you can assist me
Given a table:
create table t (a varchar2(30), b int, c date );
with this data within:
insert into t values ( a1, 40, to_date( '01-Dec-2012'));
insert into t values ( a1, 50, to_date( '01-Dec-2012'));
insert into t values ( a1, 60, to_date( '01-Dec-2012'));
insert into t values ( b1, 10, to_date( '01-Dec-2012'));
insert into t values ( b1, 20, to_date( '01-Dec-2012'));
insert into t values ( b1, 30, to_date( '01-Dec-2012'));
insert into t values ( c1, 60, to_date( '01-Dec-2012'));
insert into t values ( c1, 70, to_date( '01-Dec-2012'));
insert into t values ( c1, 80, to_date( '01-Dec-2012'));
- I want to output the columns for each of 'a' as a single row e.g:
a1 40 50 60 01-Dec-2012
b1 10 20 30 01-Dec-2012
I've almost got it right, but the 'a' col repeats 4 times for each row of output:
a1 40
a1 50
a1 60
a1 01-Dec-2012
-I want to supress repeat output of the first column 'a' but display the rest in a straight line.
I've tried various things (Pivot, Rollup etc), but the fact i'm keying on a table with non unique rows has complicated things perhaps.
Any help would be much appreciated

Answer 1

Hi,
Pre-11g this is how you would do it :[11.2] Pri @ Bepripd1 > !cat t.sql
with t(a,b,c) as (
     select  'a1', 40, to_date( '01-Dec-2012') from dual union all
     select  'a1', 50, to_date( '01-Dec-2012') from dual union all
     select  'a1', 60, to_date( '01-Dec-2012') from dual union all
     select  'b1', 10, to_date( '01-Dec-2012') from dual union all
     select  'b1', 20, to_date( '01-Dec-2012') from dual union all
     select  'b1', 30, to_date( '01-Dec-2012') from dual union all
     select  'c1', 60, to_date( '01-Dec-2012') from dual union all
     select  'c1', 70, to_date( '01-Dec-2012') from dual union all
     select  'c1', 80, to_date( '01-Dec-2012') from dual
------ end of sample data ------
select
     a
     ,max(decode(n,1,b,null)) q1
     ,max(decode(n,2,b,null)) q2
     ,max(decode(n,3,b,null)) q3
     ,c
from (
     select a, b, c, row_number() over (partition by a order by b) n
     from t
group by a,c
order by a,c
[11.2] Pri @ Bepripd1 > @t
A          Q1         Q2         Q3 C
a1         40         50         60 01/12/2012 00:00:00
b1         10         20         30 01/12/2012 00:00:00
c1         60         70         80 01/12/2012 00:00:00------
From 11g onward, you would :[11.2] Pri @ Bepripd1 > !cat t.sql
with t(a,b,c) as (
     select  'a1', 40, to_date( '01-Dec-2012') from dual union all
     select  'a1', 50, to_date( '01-Dec-2012') from dual union all
     select  'a1', 60, to_date( '01-Dec-2012') from dual union all
     select  'b1', 10, to_date( '01-Dec-2012') from dual union all
     select  'b1', 20, to_date( '01-Dec-2012') from dual union all
     select  'b1', 30, to_date( '01-Dec-2012') from dual union all
     select  'c1', 60, to_date( '01-Dec-2012') from dual union all
     select  'c1', 70, to_date( '01-Dec-2012') from dual union all
     select  'c1', 80, to_date( '01-Dec-2012') from dual
------ end of sample data ------
select a,q1,q2,q3,c
from (
     select a, b, c, row_number() over (partition by a order by b) n
     from t
pivot (
     max(b)
     for n in (
          1 as q1
          ,2 as q2
          ,3 as q3
order by a,c
[11.2] Pri @ Bepripd1 > @t
A          Q1         Q2         Q3 C
a1         40         50         60 01/12/2012 00:00:00
b1         10         20         30 01/12/2012 00:00:00
c1         60         70         80 01/12/2012 00:00:00Edited by: Nicosa on Nov 9, 2012 2:42 PM