Does FOR i IN 1..10 Uses Cursor?

Question

Hi,
Yesterday i was conducting an interview and was asking questions related to cursor. I asked the candidate to explain about Implicit cursor.
He gave me an example like this.
for i in 1..10
loop
end loop; At a first look it felt he was wrong. Because oracle creates a Cursor only for SQL statements. But then after the interview i started to think how oracle processes this? How is 1..10 is processed. What memory does it use?
Not sure if this is a silly question ;)

Answer 1

user2361373 wrote:
So 1..N IS not a cursor But this also needs memory to Fetch the results based on 1..N.Incorrect - there is no fetch. There is an implicit loop variable that is defined (which would be a 2 or 4 byte number in most languages - and usually needs an explicit variable definition).
This variable is incremented (the step clause in some programming language FOR loop statement). A condition is added to check whether another iteration is required, prior to incrementing the variable.
So in simple (and ugly) pseudo code, it looks something as follows:
define loop_var number := loop_start_counter;
:loop_start_label
if loop_var < loop_stop_counter {
  <loop body>
  loop_var++;
  goto :loop_start_label
}So it is really not a complex processing structure that the compiler creates.