Duplicate check in a Java functionality

Question

Hi,
I am writing a small integration piece to to retrive the testcases from TestCase Management tool in java, in which i have the following scenarios:-
1)     I have testcase which is “failed”, that time I am checking whether there is any defect which is already exists in the Defect management tool for the failed testcase using the testcase name , because the testcase name and the defect name are same in our case. If not I am logging the new defect. This is fine.
2)     In another case, I have testcase which is “Passed” at the first time, for that also I am checking the whether there are any duplicate defect is present in the Defect management tool , eventhough I am not going to log any defect.
This I am doing because, I don’t know whether the testcase is “Pass” or “Fail” in the first attempt or not. Hence I am doing this mandatory check , to see whether the duplicate defect exists or not for both “pass” and “fail” testcase. I know that it is wrong to check the duplicate existence of the defect for the “pass” testcase. But there is no option I have. Is there any way we can ignore calling duplicate existence of the defect method if the testcase is “passed”? I want your guys opinion on this. Thanks in advance.

Answer 1

Thanks Young & JVerd.
This is a small piece of code I have build :-
        private int NOT_TESTED = 0;
     private int PASSED_1 = 0;
     private int PASSED_2 = 0;
     private int FAILED =0;
     private String testStatus = "pass"; // will be fetched dynamically
     private void execute(){
          if(testStatus.equalsIgnoreCase("fail")){
               //FAILED--;
               FAILED = FAILED + 1;
               System.out.println("the failed value is:"+FAILED);
          }else if(testStatus.equalsIgnoreCase("pass")){// first attempt
               PASSED_1 = PASSED_1 + 1;
               System.out.println("the Passed_1 value is:"+PASSED_1);
               if(PASSED_1 == 1){
                    System.out.println("Passed in the first attempt, hence no need to create a defect");
          }else if(testStatus.equalsIgnoreCase("pass") && FAILED ==1){// second attempt
               PASSED_2 =  PASSED_2+1;
               System.out.println("the Passed_2 value is:"+PASSED_2);
               if(PASSED_2 ==1){
                    System.out.println("Passed in the second attempt, create a defect");
                    // logic to create a new defect
          }else {
               System.out.println("The test not tested");
     }Here the testStatus will be eitheir "pass" or "fail", it wont give the details whether it is "pass" or "fail" in the first attempt (when you test the testcase at first(initially)). If that is the case when the Passed_2 condition which is failed at the first attemp and passed at the second attempt will be invoked?
if(testStatus.equalsIgnoreCase("pass") && FAILED ==1){// second attempt
PASSED_1 = PASSED_1 + 1;
               System.out.println("the Passed_1 value is:"+PASSED_1);
               if(PASSED_1 == 1){
                    System.out.println("Passed in the first attempt, hence no need to create a defect");
}This logic won't invoked at all, as we are not able find from the "testStatus" variable whether it is pass or fail at the second attempt. Hence for the testStatus which is "pass", always the first "pass" condition will get invoked.
Similarly for the "fail" as well.
Please tell me where i am going wrong? thanks in advance.