Edit properties link with SPMenuField in SPGridView

Question

Hi,
I've a new questionfor my webPart that display search result in spgridview
Do you know a method to propose in a SPMenuField on a SPGridView the link "edit properties"?
We have this line to retrieve the edit form:
string.Format("{0}{1}?ID={2}", item.Web.Url, item.ParentList.Forms[PAGETYPE.PAGE_EDITFORM].ServerRelativeUrl, item.ID);
here is my menu entry
MenuItemTemplate viewProperties = new MenuItemTemplate("Edit properties", "/_layouts/images/editDocument.gif");
viewProperties.ClientOnClickNavigateUrl = "";
//entry.ClientOnClickScript = "your javascript here";
menuTpl.Controls.Add(viewProperties);
I don't know what write in ClientOnClickNavigateUrl to go to the edit form related on each Item.
How can i get the list for each item?
thanks for your help

Answer 1

Hello,
Try to use "ClientOnClickNavigateUrl " and pass your URL here.
string itemUrl = string.Format("{0}/{1}?ID={2}", web.Url, list.Forms[PAGETYPE.PAGE_DISPLAYFORM].Url, itemID);
MenuItemTemplate editCustomer =
new MenuItemTemplate("Edit", "/images/edit.gif");
editCustomer.ClientOnClickNavigateUrl = itemUrl;
customerMenu.Add(editCustomer);
Refer this:
http://msdn.microsoft.com/en-us/library/microsoft.sharepoint.webcontrols.menuitemtemplate.clientonclickscript.aspx
Hemendra:Yesterday is just a memory,Tomorrow we may never see
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