Error - SP2-0103: Nothing in SQL buffer to run - With only one user

I receive this error when we login to the sqlplus tool using - sqlplus /nolog command - sql prompt. This error is specific to one of the users in the Solaris[5.10] unix box. In the other users we do not receive this message.
Workarounds tried -
1. Verfied the glogin.sql under $ORACLE_HOME/sqlplus/admin for any additional "/" characters as suggested by metalink
2. Tried to clear the buffer.
Please anyone help me on this issue.

Sounds like a local login.sql exists for that user and that results in the error.
Refer to http://www.jlcomp.demon.co.uk/faq/glogin.html for details.

Similar Messages

SP2-0103: Nothing in SQL buffer to run.

Hi All,
When i execute the script it throws the following error msg.
SP2-0103: Nothing in SQL buffer to run.
Thanks in advance!

Please past here below what you tried.
SQL> /
SP2-0103: Nothing in SQL buffer to run.
SQL> l
SP2-0223: No lines in SQL buffer.
SQL> Nicolas.

Error "Nothing in SQL buffer to run"

Hi All,
I am facing an error while running sql script (names.sql) " Nothing in SQL buffer to run" .
The sql file contains insert and update statements.
I don't understand why it is giving that error. i tried changing the directory where the file is kept , even then the problem exist.
Kindly suggest me .

Hi,
I am facing an error while running sql script (names.sql) " Nothing in SQL buffer to run" .
The sql file contains insert and update statements.Can You share with us what is the first line in your sql file which you are calling.
I hope its not '/' in the first line.
I have come across a problem where I had / in the first line following the sql commands. That gave me the same error which you are facing.
Twinkle

Why, when I open Firefox 4, do I keep having Firefox 3 pop up continually and having the error message "A copy of Firefox is already open. Only one copy of Firefox can be open at a time." ?

Every time that I try to use Firefox 4, Firefox 3 pops up on the Dock and tries to start up. I get the error message "A copy of Firefox is already open. Only one copy of Firefox can be open at a time." I click OK and the message goes away. Then it happens again. And again. It doesn't stop until I quit Firefox 4. I've tried creating a new profile (and deleting my old one) and deleting the .parentlock and the profile.ini file, but nothing works. Help me please!

See:
* https://support.mozilla.com/kb/Firefox+is+already+running+but+is+not+responding

How does one install a express sql server to run with Visual Web Developer 2008?

I successfully installed .NET framework v 3.5 and VWD 2008 on a new Vista laptop. When I want to add a Sql Server database to a website, errors tell me to install SS 2005 Express. MSDN SS 2005 Express download tells me I MUST first install .NET framework v 2.0 before SS 2005. When I try to install framework v 2.0, I'm sent to v. 3.5 and no way to download SS 2005.
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Momark,
Do you still need help with this?
Thank you!
Ed Price, Power BI & SQL Server Customer Program Manager (Blog,
Small Basic,
Wiki Ninjas,
Wiki)
Answer an interesting question?
Create a wiki article about it!

SQL Server 2012 Undetected Deadlock in a table with only one row

We have migrated our SQL 2000 Enterprise Database to SQL 2012 Enterprise few days ago.
This is our main database, so most of the applications access it.
The day after the migration, when users started to run tasks, the database access started to experiment a total failure.
That is, all processes in the SQL 2k12 database were in lock with each other. This is a commom case of deadlock, but the Database Engine was unable to detect it.
After some research, we found that the applications were trying to access a very simple table with only one row. This table has a number that is restarted every day and is used to number all the transactions made against the system. So, client
applications start a new transaction, get the current number, increment it by one and commit the transaction.
The only solution we found was to kill all user processes in SQL Server every time this situation occurs (no more than 5 minutes when all clients are accessing the database).
No client application was changed in this migration and this process was working very well for the last 10 years.
The problem is that SQL 2k12 is unable to handle this situation compared to SQL 2k.
It seems to occurs with other tables too, but as this is an "entry table" the problem occurs with it first.
I have searched internet and some suggest some workarounds like using table hints to completely lock the table at the begining of the transaction, but it can't be used to other tables.
Does anyone have heard this to be a problem with SQL 2k12? Is there any fixes to make SQL 2k12 as good as SQL 2k?

First off re: "Unfortunatelly, this can't be used in production environment as exclusive table lock would serialize the accesses to tables and there will be other tables that will suffer with this problem."
This is incorrect.
Using a table to generate sequence numbers like this is a bad idea exactly because the access must be serialized. Since you can't switch to a SEQUENCE object, which is the correct solution, the _entire goal_ of this exercise to find a way to properly
serialize access to this table. Using exclusive locking will not be necessary for all the tables; just for the single-row table used for generating sequence values with a cursor.
I converted the sample program to VB.NET:
Public Class Form1
Private mbCancel As Boolean = False
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim soConn As ADODB.Connection
Dim soRst As ADODB.Recordset
Dim sdData As Date
Dim slValue As Long
Dim slDelay As Long
'create database vbtest
'go
' CREATE TABLE [dbo].[ControlNumTest](
' [UltData] [datetime] NOT NULL,
' [UltNum] [int] NOT NULL,
' CONSTRAINT [PK_CorreioNumTeste] PRIMARY KEY CLUSTERED
' [UltData] Asc
' )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON, FILLFACTOR = 80) ON [PRIMARY]
' ) ON [PRIMARY]
mbCancel = False
Do
' Configure the Connection object
soConn = New ADODB.Connection
With soConn
.ConnectionString = "Provider=SQLNCLI11;Initial Catalog=vbtest;Data Source=localhost;trusted_connection=yes"
.IsolationLevel = ADODB.IsolationLevelEnum.adXactCursorStability
.Mode = ADODB.ConnectModeEnum.adModeReadWrite
.CursorLocation = ADODB.CursorLocationEnum.adUseServer
.Open()
End With
' Start a new transaction
Call soConn.BeginTrans()
' Configure the RecordSet object
soRst = New ADODB.Recordset
With soRst
.ActiveConnection = soConn
.CursorLocation = ADODB.CursorLocationEnum.adUseServer
.CursorType = ADODB.CursorTypeEnum.adOpenForwardOnly
.LockType = ADODB.LockTypeEnum.adLockPessimistic
.Open("SELECT * FROM dbo.ControlNumTest")
End With
With soRst
sdData = .Fields!UltData.Value ' Read the last Date (LOCK INFO 1: See comments bello
slValue = .Fields!UltNum.Value ' Read the last Number
If sdData <> Date.Now.Date Then ' Date has changed?
sdData = Date.Now.Date
slValue = 1 ' Restart number
End If
.Fields!UltData.Value = sdData ' Update data
.Fields!UltNum.Value = slValue + 1 ' Next number
End With
Call soRst.Update()
Call soRst.Close()
' Ends the transaction
Call soConn.CommitTrans()
Call soConn.Close()
soRst = Nothing
soConn = Nothing
txtUltNum.Text = slValue + 1 ' Display the last number
Application.DoEvents()
slDelay = Int(((Rnd * 250) + 100) / 100) * 100
System.Threading.Thread.Sleep(slDelay)
Loop While mbCancel = False
If mbCancel = True Then
Call MsgBox("The test was canceled")
End If
Exit Sub
End Sub
Private Sub Button2_Click(sender As Object, e As EventArgs) Handles Button2.Click
mbCancel = True
End Sub
End Class
And created the table
CREATE TABLE [dbo].[ControlNumTest](
[UltData] [datetime] NOT NULL,
[UltNum] [int] NOT NULL,
CONSTRAINT [PK_CorreioNumTeste] PRIMARY KEY CLUSTERED
[UltData] Asc
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = on, FILLFACTOR = 80) ON [PRIMARY]
) ON [PRIMARY]
go insert into ControlNumTest values (cast(getdate()as date),1)
Then ran 3 copies of the program and generated the deadlock:
<deadlock>
<victim-list>
<victimProcess id="processf27b1498" />
</victim-list>
<process-list>
<process id="processf27b1498" taskpriority="0" logused="0" waitresource="KEY: 35:72057594039042048 (a01df6b954ad)" waittime="1970" ownerId="3181" transactionname="implicit_transaction" lasttranstarted="2014-02-14T15:49:31.263" XDES="0xf04da3a8" lockMode="X" schedulerid="4" kpid="9700" status="suspended" spid="51" sbid="0" ecid="0" priority="0" trancount="2" lastbatchstarted="2014-02-14T15:49:31.267" lastbatchcompleted="2014-02-14T15:49:31.267" lastattention="1900-01-01T00:00:00.267" clientapp="vbt" hostname="DBROWNE2" hostpid="21152" loginname="NORTHAMERICA\dbrowne" isolationlevel="read committed (2)" xactid="3181" currentdb="35" lockTimeout="4294967295" clientoption1="671088672" clientoption2="128058">
<executionStack>
<frame procname="adhoc" line="1" stmtstart="80" sqlhandle="0x020000008376181f3ad0ea908fe9d8593f2e3ced9882f5c90000000000000000000000000000000000000000">
UPDATE [dbo].[ControlNumTest] SET [UltData]=@Param000004,[UltNum]=@Param000005 </frame>
<frame procname="unknown" line="1" sqlhandle="0x0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000">
unknown </frame>
</executionStack>
<inputbuf>
(@Param000004 datetime,@Param000005 int)UPDATE [dbo].[ControlNumTest] SET [UltData]=@Param000004,[UltNum]=@Param000005 </inputbuf>
</process>
<process id="processf6ac9498" taskpriority="0" logused="10000" waitresource="KEY: 35:72057594039042048 (a01df6b954ad)" waittime="1971" schedulerid="5" kpid="30516" status="suspended" spid="55" sbid="0" ecid="0" priority="0" trancount="1" lastbatchstarted="2014-02-14T15:49:31.267" lastbatchcompleted="2014-02-14T15:49:31.267" lastattention="1900-01-01T00:00:00.267" clientapp="vbt" hostname="DBROWNE2" hostpid="27852" loginname="NORTHAMERICA\dbrowne" isolationlevel="read committed (2)" xactid="3182" currentdb="35" lockTimeout="4294967295" clientoption1="671156256" clientoption2="128058">
<executionStack>
<frame procname="adhoc" line="1" sqlhandle="0x020000003c6309232ab0edbe0a7790a816a09c4c5ac6f43c0000000000000000000000000000000000000000">
FETCH API_CURSOR0000000000000001 </frame>
<frame procname="unknown" line="1" sqlhandle="0x0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000">
unknown </frame>
</executionStack>
<inputbuf>
FETCH API_CURSOR0000000000000001 </inputbuf>
</process>
</process-list>
<resource-list>
<keylock hobtid="72057594039042048" dbid="35" objectname="vbtest.dbo.ControlNumTest" indexname="PK_CorreioNumTeste" id="lockff6e6c80" mode="U" associatedObjectId="72057594039042048">
<owner-list>
<owner id="processf6ac9498" mode="S" />
<owner id="processf6ac9498" mode="U" requestType="wait" />
</owner-list>
<waiter-list>
<waiter id="processf27b1498" mode="X" requestType="convert" />
</waiter-list>
</keylock>
<keylock hobtid="72057594039042048" dbid="35" objectname="vbtest.dbo.ControlNumTest" indexname="PK_CorreioNumTeste" id="lockff6e6c80" mode="U" associatedObjectId="72057594039042048">
<owner-list>
<owner id="processf27b1498" mode="U" />
<owner id="processf27b1498" mode="U" />
<owner id="processf27b1498" mode="X" requestType="convert" />
</owner-list>
<waiter-list>
<waiter id="processf6ac9498" mode="U" requestType="wait" />
</waiter-list>
</keylock>
</resource-list>
</deadlock>
It's the S lock that comes from the cursor read that's the villian here. U locks are compatible with S locks, so one session gets a U lock and another gets an S lock. But then the session with an S needs a U, and the session with a U needs an
X. Deadlock.
I'm not sure what kind of locks were taken by this cursor code on SQL 2000, but on SQL 2012, this code is absolutely broken and should deadlock.
The right way to fix this code is to add (UPDLOCK,SERIALIZABLE) to the cursor
.Open("SELECT * FROM dbo.ControlNumTest with (updlock,serializable)")
So each session reads the table with a restrictive lock, and you don't mix S, U and X locks in this transaction. This resolves the deadlock, but requires a code change.
I tried several things that didn't require a code, which did not resolve the deadlock;
1) setting ALLOW_ROW_LOCKS=OFF ALLOW_PAGE_LOCKS=OFF
2) SERIALIZABLE isolation level
3) Switching OleDB providers from SQLOLEDB to SQLNCLI11
Then I replaced the table with a view containing a lock hint:
CREATE TABLE [dbo].[ControlNumTest_t](
[UltData] [datetime] NOT NULL,
[UltNum] [int] NOT NULL,
CONSTRAINT [PK_CorreioNumTeste] PRIMARY KEY CLUSTERED
[UltData] Asc
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = on, FILLFACTOR = 80) ON [PRIMARY]
) ON [PRIMARY]
go
create view ControlNumTest as
select * from ControlNumTest_t with (tablockx)
Which, at least in my limited testing, resovlved the deadlock without any client code change.
David
David http://blogs.msdn.com/b/dbrowne/

When I try and launch Firefox, I get this error message A copy of Firefox is already open. Only one copy of Firefox can be open at a time." and have tried all of the trouble shooting tips, can you help?

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See [[Firefox is already running but is not responding]], the image shown in that article is the Windows equivalent of the error message that you are receiving, but the information relates to the Mac.

HT4527 an iphone can be synced with only one itunes library at a time error on same pc

an iphone can be synced with only one itunes library at a time error on same pc why?

Damaged library... See Empty/corrupt library after upgrade/crash.
tt2

Why does the Error: 500 SC_INTERNAL_SERVER_ERROR appear when multiple users access my JSPs but does not occur when only one user accesses my JSPs?

When multiple users run my JSP application, why do some users get an Error: 500 SC_INTERNAL_SERVER_ERROR for certain JSP pages with the error message No such file or directory. The JSP listed on the Error 500 page varies and is not always the same. When only one user runs my JSP application, the problem does not occur?
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Enterprise Ultra 250
iAS 6 SP 3

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HT1349 Win 7 64 bit: iTunes won't install, get error code 2324 or installer says I am not logged on as administrator: only one user and it is an administrator user.

Win 7 64 bit: iTunes won't install, get error code 2324 or installer says I am not logged on as administrator: only one user and it is an administrator user.

Hey there k8ei,
Thank you for using Apple Support Communities
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General installation troubleshooting
1. Empty your Temp directory and restart
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3. Install the latest version of iTunes
Additional troubleshooting
After performing each of the steps below, you will need to completely remove iTunes and related components and then install iTunes again to determine whether the issue is resolved.
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SQL query to retrieve families with only one generation from a family db

Hi,
I need to write an SQL query that would select families with only one generation ((which means a person - or a married couple - with kids) or (a person - or a married couple - with parents but no kids)) from a database containing families. The simplified db structure is:
person:
id - int, primary key
siblings:
id
parent_id
kid_id
marriage
id:
husband_id
wife_id
Could anyone please help me? I dont really have any idea how to accomplish that...

Hi,
Welcome to the forum!
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WITH got_tree AS
 SELECT CONNECT_BY_ROOT s.parent_id AS root_id
 , LEVEL AS lvl
 FROM siblings s
 LEFT OUTER JOIN marriage m ON s.parent_id IN ( m.husband_id
 , m.wife_id
 START WITH parent_id NOT IN ( SELECT kid_id
 FROM siblings
 CONNECT BY s.parent_id IN ( PRIOR m.husband_id
 , PRIOR m.wife_id
 , PRIOR kid_id
SELECT root_id
FROM got_tree
GROUP BY root_id
HAVING MAX (lvl) <= 2
;This will get a list of parents who may or may not have children, but who do not have either parents or grandchildren.
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The details of how to do that depend on the details of your tables. If you'd like help, then post a little sample data (CREATE TABLE and INSERT statements for all tables) and the results you want from that data.
Edited by: Frank Kulash on Oct 14, 2009 4:05 PM
I'd need sample data in order to test this, of course.

Error trying to get LiveCycle ES up and running with JBoss/SQL Server

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Error on Mac- A copy of firefox is already open. only one copy of firefox can be open at a time.

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SQL Developer Migration Workbench - Migrate only one Database?

Hallo!
We want to use Oracle SQL Developer Migration Workbench Early Adopter for migrate some Databases from SQL 2000 to Oracle 10g R2 (on XP SP2 SQL Developer 1.1.2.25.79).
The first Database we can migrate to Oracle. The Loader files in OMW are better!
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Thanks.
Michael

Michael,
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Regards
Sue

Since Firefox updated, when I try to click on a link in my Outlook email, I get the error message, A copy of Firefox is already open. Only one copy of Firefox c

I'm on a Mac desktop.

You may be having problems in shutting down Firefox properly for some reason.
What is the exact message you receive ?
You may need to look for and kill any Firefox or plugin container processes that are still running. See [["Firefox is already running but is not responding" error message - How to fix it]]
If the problem continues a screen shot of the message may help
* see [[How do I create a screenshot of my problem?]].

Error - SP2-0103: Nothing in SQL buffer to run - With only one user

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