Executable Jar Trouble

Hello everyone,
I am creating an executable jar with this command:
jar cmf CarmaFrame.mf CarmaNew.jar *.*
The contents of the manifest file (CarmaFrame.mf ) are:
Manifest-Version: 1.0
Class-Path: j.jar
Main-Class: CarmaFrame.class
This creates an executable jar in the directory that contains all of the files. It executes fine when double clicked in windows xp.
If I move the newly created jar file to my desktop and try to double click it, I get this error:
could not find the main class. program will exit.
None of my java files are using packages. Any ideas on why I am having this problem?
BTW, the j.jar file is a dependent jar file that does show it is in the CarmaNew.jar file when using the command:
jar tf CarmaNew.jar
Thanks,
Brandon

Packaging a jar within an executable jar:
http://forum.java.sun.com/thread.jsp?forum=22&thread=405160&tstart=0
http://forum.java.sun.com/thread.jsp?forum=22&thread=505248&tstart=0&trange=15
http://forum.java.sun.com/thread.jsp?forum=4&thread=432114&tstart=0

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Roosh wrote:
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problem solved.
for windows to open executable .jar files upon double-click there should be a file association such as:
"C:\progs\j2sdk1.4.1_01\bin\java.exe" -jar %1
right?
WRONG!!!
beloved windows often has folder names with white-space (such on the desktop):
C:\Documents and Settings\... the above association will NOT always work properly because of the %1, that doesn't like filenames with spaces. the correct way of making the association is:
"C:\progs\j2sdk1.4.1_01\bin\java.exe" -jar "%1"
now, if you find this post and it saved you from trouble, please drop a line in this thread.
will be cheerful to know that at least someone benefited from my wasted time... ;-)

Question about Executable JAR Files

Is it possible to make an executable JAR file that has all of the *.class files, all of the *.jar archives used, etc. packaged into one file that doesn't need these external files within the same directory? I've been having a ton of trouble finding the answer to this. (If it's blatantly obvious, please forgive me.)

Hello,
I went through the same thing recently. Here is a piece of the build file I use:
<project name="MyProj" basedir="." default="main">
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There are, however, many good reasons to not do this. Some were already mentioned, another is in the case of update external libraries, you might not want to rebuild your whole project, replacing a jar may be easier.
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though the application works normally
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Thank you very much for your quick reply and really hope you can help me a little more
it's so frustrating
I do not really know about the relative path but here is my xml file
<?xml version="1.0" encoding="UTF-8" ?>
<project default="jar">

<target name="jar">

<mkdir dir="ant"/>
<mkdir dir="work"/>
     <mkdir dir="ant/myFiles"/

<javac
debug="yes"
destdir="ant"
source="1.6"
target="1.6">

<src path="src"/>
</javac>
     <copy todir="ant/myFiles"><fileset dir="src/myFiles"></fileset></copy>

<jar
               jarfile="work/BookOfChanges.jar"
basedir="ant"
>

<manifest>

<attribute name="Main-Class" value="iChing.Main"/>
</manifest>
</jar>
</target>
</project>

I dont see the point of using Ant Build compared to executable Jars?

I always think that to complete a project you successfully build it. And i thought that building is done automatically if you create an executable JAR? So what is ANT for?
Arent Executables is the same as building your project?

paulcw wrote:
They are all unnecessary for a single person doing small projects (although often still necessary).I assume you meant "(although often still useful)".
And furthermore you may find that the vast majority of your time programming professionally isn't the programming, but just managing these other aspects.It is a good day for me when that is not the case ;-)
There should be a class in university: "industrial practices". It would have little or no CS theory but all the stuff that you learn the first year on the job (often painfully).The company I work in really likes to hire young developers, which often means that they come right from school (gladly, we have some good IT-centric schools in the area). They usually get some introduction in some of these aspects in school (usually mostly version control, bug tracking and a little bit of automated builds). But even if they heard about them, used them for a simple project and get the general idea, they still don't believe them to be necessary until they see what a pain in the back it can be not to have all that in a medium-sized project.

Adding a jar to the classpath of an executable jar (mixing -jar and -cp)

Hello,
frankly I hesitated over posting this to "New to Java"; my apologies (but also, eternal gratefulness) if there is an ultra-simple answer I have overlooked...
I integrate a black-box app (I'm not supposed to have the source) that comes packaged as an executable jar (with a Manifest.MF that specifies the main class and a bunch of dependent jars), along with a few dependent jars and a startup script. Long story short, the application code supports adding jars in the classpath, but I can't find a painless way to add a jar in its "classpath".
The app's "vendor" (another department of my customer company) has a slow turnaround on support requests, so while waiting for their suggestion as to how exactly to integrate custom jars, I'm trying to find a solution at the pure Java level.
The startup script features a "just run the jar" launch line:
java -jar startup.jarI tried tweaking this line to add a custom jar in the classpath
java -cp mycustomclasses.jar -jar startup.jarBut that didn't seem to work ( NoClassDefFound at the point where the extension class is supposed to be loaded).
I tried various combination of order, -cp/-classpath, using the CLASSPATH environment variable,... and eventually gave up and devised a manual launch line, which obviously worked:
java -cp startup.jar;dependency1.jar;dependency2.jar;mycustomclasses.jar fully.qualified.name.of.StartupClassI resent this approach though, which not only makes me have to know the main class of the app, but also forces me to specify all the dependencies explicitly (the whole content of the Manifest's class-path entry).
I'm surprised there isn't another approach: really, can't I mix -jar and -cp options?
- [url http://download.oracle.com/javase/6/docs/technotes/tools/windows/classpath.html]This document (apparently a bible on the CLASSPATH), pointed out by a repited forum member recently, does not document the -jar option.
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Thanks in advance, and best regards,
J.
Edited by: jduprez on Dec 7, 2010 11:35 PM
Ahem, the "Java application launcher" page bundled with the JDK doc (http://download.oracle.com/javase/6/docs/technotes/tools/windows/java.html) specifies that +When you use [the -jar] option, the JAR file is the source of all user classes, and other user class path settings are ignored+
So this behavior is deliberate indeed... my chances diminish to find a way around other than specifying the full classpath and main class...

I would have thought that the main-class attribute of the JAR you name in the -jar option is the one that is executed.Then I still have the burden of copying that from the initial startup.jar's manifest. Slightly less annoying than copying the whole Class-path entry, but it's an impediment to integrating it as a "black-box".
The 'cascading' behavior is implicit in the specification
I know at least one regular in addition to me that would issue some irony about putting those terms together :o)
Anyway, thank you for confirming the original issue, and merci beaucoup for your handy "wrapper" trick.
I'll revisit the post markers once I've actually tried it.
Best regards,
Jérôme

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According to the Jar Guide (http://java.sun.com/j2se/1.4.2/docs/guide/jar/jarGuide.html)
Executable Jar Files
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--olaf

Executable JAR file: Could not find the main class.

Hello,
I have a problem with making an executable JAR file.
I have written a JAVA program that consists of five different classes of which User.java is the main class and I have saved a text document with Main-Class: User and a blank line after that.
If I try:
jar cmf MainClass.txt User.jar User.class Beheerder.class Operator.class Manager.class MaakVisueelSchema.class
it makes a executable jar file which actually works! :)
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I can run MaakVisueelSchema with java MaakVisueelSchema.
So I tried to make an executable JAR that consists only of MaakVisueelSchema, the same way as I did for User:
Main-Class: MaakVisueelSchema
jar cmf MainClass.txt MaakVisueelSchema.jar MaakVisueelSchema.class
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Bye!

Yes,
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package structure:
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Please don't cross post, and read this
http://forum.java.sun.com/thread.jsp?forum=31&thread=271751
I've answered the question in the New To Java thread.

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Thanks, i will try soon.
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Executable Jar Trouble

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