File sometimes saves as unicode, sometimes as ANSI problem
Hi all,
I'm having an issue whereby a .vi I've created to save string data sometimes saves the .txt file as ANSI and sometimes as Unicode. Unfortunately the unicode appears to be Chinese characters when opened in notepad. When I open the same file in notepad++ the data is there but in unicode format. I'd like to try and understand why this is happening and fix it. Any advice would be appreciated. I've included the .vi, ansi output example and a unicode output example.
Brief description of the vi functionality:
The .vi simply saves the input string to the filename (and path) supplied in Log File Path. It checks conditions for file existing, path exisiting and creates any missing pieces (folders, files). Then it opens the file for writing, sets 'append' and writes to the files. Lastly it closes the file.
I can not figure out what is causing it to sometimes save as unicode and sometimes as ansi. Please let me know if there is anything further I can provide.
Cheers,
Alex
Alexander H. | Software Developer | CLAD
Attachments:
Unicode.txt 274 KB
Log.vi 16 KB
Unicode.txt 274 KB
alexhunt wrote:
Hi all,
I can not figure out what is causing it to sometimes save as Unicode and sometimes as ANSI. Please let me know if there is anything further I can provide.
Hi, alex,
The file seems to be saved correctly and its not saved as Unicode. The file opened as Unicode.
Do simple experiment:
1. Start Notepad:
2. Type 'AAAA BBB CCC DDDDD':
3. Save it. As you can see in hex viewer, my file is correct:
4. Now open this file in notepad, you will be surprised:
This is true for XP, not sure how it works with Windows 7.
Try to open your file in that way:
Andrey.
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JOptionPane.showMessageDialog(this,"Please enter the file name","Error",JOptionPane.ERROR_MESSAGE);
return(false);
private void outputToFile() throws IOException
// Initial output
textArea.append("File name = " + fileName_out + "\n");
// Test if data exists
if (data != null)
fileOutput.println(fileName_in.getName() +"\t"+ slope+"\t"+intb+"\t"+corr+"\t"+r_sqrt);
textArea.append("File output complete\n\n");
else
textArea.append("No data\n\n");
// End by closing file
initialcomp();
fileOutput.close();
private void initialcomp()
slope=0.0;
intb=0.0;
corr=0.0;
r_sqrt=0.0;
sumx=0.0; sumy=0.0; multixy=0.0; square_x_sum=0.0; square_y_sum=0.0;
for(int i=0;i<data.length;i++)
for(int j=0;j<data[i].length;j++)
data[i][j]=null;
/* MAIN METHOD */
public static void main(String[] args) throws IOException
// Create instance of class FileChooser
FileReduction1 newFile = new FileReduction1("File Reduction Program");
// Make window vissible
newFile.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
newFile.setSize(500,400);
newFile.setVisible(true);
Sorry about the long lines.
As you can see, all input files saved in array called files, however when OpenFile1() function is called, it take input (fileName_in) as a single file not an array. I'm assuming this causes the exception.
When there's muptiple inputs, program should take each file from getFileName() to outputToFile() sequentially.
Does anybody have an idea to solve this?
Thanks a lot!!you naming convention is confussing. you should follows Java naming convention..you have a getXXX but decalred the return type as "void"...get usully means to return something...
your code is doing too much..and hard to follows..
1. get the selected files
for each selected file
process the file and return the result
write out the result.
/** close the precious resource */
public void closeResource(Reader in){
if (in != null){
try{ in.close(); }
catch (Exception e){}
/** get the total number of line in a file */
public int getLineCount(File file) throws IOException{
BufferedReader in = null;
int lineCount = 0;
try{
in = new BufferedReader(new FileReader(file));
while ((in.readLine() != null)
lineCount++;
return lineCount;
finally{ closeResource (in); }
/** read the file */
public void processFile(File inFile, File outFile) throws IOException{
BufferedReader in = null;
StringBuffer result = new StringBuffer();
try{
in = new BufferedReader(new FileReader(inFile));
String line = null;
while ((in.readLine() != null){
.. do something with the line
result.append(....);
writeToFile(outFile, result.toString());
finally{ closeResource (in); }
public void writeToFile(File outFile, String result) throws IOException{
PrintWriter out = null;
try{
out = new PrintWriter(new FileWriter(outFile, true)); // true for appending to the end of the file
out.println(result);
finally{ if (out != null){ try{ out.close(); } catch (Exception e){} } }
} -
When I receive an attachment to an email, and I click it and select "Download", I get the "Enter name of file to save to..." dialog box (because I already set the option to "Always ask me where to save files." But the file display always defaults to a "List". At least recently. I don't recall it always doing that. In any case, I want it to default to a "Details" display, in ascending order, as I can then find things sooo much faster that way. (I often use the "Date Modified" tab to bring to the top the most recent version of a file.) I know that I can go to the "View Menu" icon and select "Details", but each time I go into a sub folder while in this dialog box, I have to do that all over again and it wastes a lot of time and attention.
I did some internet searches but didn't find a way to fix this.Thanks for reaching out, glennr.
The dialog box you are describing is controlled by Windows, not Firefox, so unfortunately Firefox cannot change what you see by default.
I think your best bet would be to ask on the [http://answers.microsoft.com/en-us/windows/forum/windows_xp?auth=1 Windows support site]. -
When savind a PDF file, it saves multiple of the same document, why? Are there settings to adjust or what am I doing wrong?
This might help - I'm not sure:
Go to System Preferences (under the Apple logo in the menu bar). Click "General" and check "Always close windows when quitting an application."
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