"Find all occurences of" issue

Question

Hi experts,
I have an issue and I need some help.
I have one internal table for equipments and it's one column contains status values as:
COL1
AVLB
ESTO PIAC
PIAC
Now, on the selection screen, I have a select option for equipment status.
So, suppose, if user enters values AVLB and ESTO is select option, then out of these 3 entries only entry 1 and 2 should come.
Third entry should not come as it is neither AVLB nor PIAC.
For this, I thought of using
    FIND ALL OCCURRENCES OF <what to give in here> IN TABLE i_main
    RESULTS results.
    I can not hard code any status as it will be determined by select option and select option could have multiple entries.
How do I filter out the table entries based upon the select option values.
I can not use
delete i_main where status not in s_stat. (as this status column is a concatenation of various equipment status values)
Please help me on the same.

Answer 1

Hi,
Try this way. It works.
REPORT ztest_program.
DATA: BEGIN OF it_data OCCURS 0,
        text TYPE char15,
      END OF it_data.
SELECT-OPTIONS:s_text FOR it_data-text.
*"START-OF-SELECTION.
START-OF-SELECTION.
  "Populating data
  it_data-text = 'AVLB'.
  APPEND it_data.
  CLEAR  it_data.
  it_data-text = 'ESTO PIAC'.
  APPEND it_data.
  CLEAR  it_data.
  it_data-text = 'PIAC'.
  APPEND it_data.
  CLEAR  it_data.
  "If you give select options AVLB and ESTO*, It works as you expected.
  LOOP AT it_data WHERE text IN s_text.
    WRITE:/ it_data-text.
  ENDLOOP.
  "If you give select options AVLB and ESTO, It works as you expected.
  LOOP AT it_data.
    LOOP AT s_text.
      IF it_data-text CS s_text-low.
        WRITE:/ it_data-text.
      ENDIF.
    ENDLOOP.
  ENDLOOP.
Thanks
Venkat.O