Find command with file size

Question

Hello again,
With my find command I'm trying to get my output to include the file size as it would show in Finder. I believe it's called the "physical" size. Am I going in the right direction with this code or is there a better way?
find /Users/username/Library -name "foo" -prune -maxdepth 3 -exec du -hs {} ;
Thanks again for your input,
Rick

Answer 1

If going down the awk route, might try a slightly different approach
find /Users/username/Library
-name "foo"
-prune
-maxdepth 3
-ls | awk '{print $2 "
" $NF;}'
The -ls avoids invoking a subprocess for every file just so the du command can be called.
The down side is that you do not get benefit of the *du -h* option to humanize the values.
Another approach that would invoke du fewer times would be to put xargs in the pipeline
find /Users/username/Library
-name "foo"
-prune
-maxdepth 3
-print0 | xargs -0 du -hs | awk '{print $1 "
" $2;}'
xargs will bundle up a group of files for each du command to process in one invocation.
The -print0 and -0 will make sure that spaces in file paths do not cause problems for the du command.
Oh yea, if you are going to also be performing a bunch of find commands together, you could do all of those commands in a single pipeline
( find /path1 -name ... -print0;
find /path2 -name ... -print0;
find /path3 -name ... -print0
) | xargs -0 du -hs | awk '{print $1 "
" $2;}'
Message was edited by: BobHarris