Finding id,max(salary) in oracle 10g

Question

Select * from one:
ID SALARY
10 1000
20 2000
30 3200
Select * from two:
ID SALARY
10     1000
20     2000
40     4000
10     3000
20     4000
30     3000
When i try to find ID,MAX(SALARY) from these two tables, i am getting this output:
Select id,max(salary)
from
(select * from one
union
select * from two)
group by id
order by max(salary) desc;
OUTPUT:
ID MAX(SALARY)
20     4000
40     4000
30     3200
10     3000
I want OUTPUT to be like this:
ID MAX(SALARY)
20     4000
40     4000

Answer 1

Another way...
SQL> ed
Wrote file afiedt.buf
  1  with one as (select 10 as ID, 1000 as SALARY from dual union all
  2               select 20, 2000 from dual union all
  3               select 30, 3200 from dual
  4              )
  5      ,two as (select 10 as id, 1000 as salary from dual union all
  6               select 20, 2000 from dual union all
  7               select 40, 4000 from dual union all
  8               select 10, 3000 from dual union all
  9               select 20, 4000 from dual union all
10               select 30, 3000 from dual)
11  --
12  -- end of test data
13  --
14  select id, max(salary) from one group by id having max(salary) in (select max(salary) from (select salary from one union select salary from two))
15  union
16* select id, max(salary) from two group by id having max(salary) in (select max(salary) from (select salary from one union select salary from two))
SQL> /
        ID MAX(SALARY)
        20        4000
        40        4000