Finding value for a specific condition

Question

Hi All,
I have a several Employee Numbers in my Database Table. Each Employee is having different set of Profile Numbers.
For eg. the Table Emp_Profile contains the following
Emp No ProfileNo Salary Red_Amount
1000     11     1200     430
1000     12     100     55
1000     13     120     7
1000     14     430     8
1000     15     300     40
1000     43     200     20
1000     56     100     232
1010     11     1000     300
1010     14     110     700
1010     19     200     500
1010     12     410     545
1010     13     300     54
If the Employee contains 19,45,67,89,99,24 as ProfileNo then For Each Employee reduce the Salary value for 11 ProfileNo by the Corresponding Red_Amount
Ie the Output Should be
For
EmpNo Salary
1000 1200
1010 500 (as it has 19 ProfileNo)
Please help me in doing this task.
Regards,
Gita

Answer 1

I used simple case.
And I used searched case.
create table empTable(EmpNo,ProfileNo,Salary,Red_Amount) as
select 1000,11,1200,430 from dual union
select 1000,12, 100, 55 from dual union
select 1000,13, 120,  7 from dual union
select 1000,14, 430,  8 from dual union
select 1000,15, 300, 40 from dual union
select 1000,43, 200, 20 from dual union
select 1000,56, 100,232 from dual union
select 1010,11,1000,300 from dual union
select 1010,14, 110,700 from dual union
select 1010,19, 200,500 from dual union
select 1010,12, 410,545 from dual union
select 1010,13, 300, 54 from dual;
select EmpNo,
case max(case when ProfileNo in(19,45,67,89,99,24)
              then 1 else 0 end)
when 1 then max(decode(ProfileNo,19,Red_Amount))
else max(Salary) end as Salary
  from empTable
group by EmpNo;
EmpNo  Salary
1000    1200
1010     500