Follow-up to my previous lameness

Question

ok, so sorry about that last post.
here's a legitimate question:
I have multiple blanks spaces between some of my non-whitespace
characters, so i might have
table = "111 222 333 444 555 666";
the way the "\\s" regular expression parses, I get a new entry in my array
for, i presume, everytime it encounters 2 spaces in a row. It splits around
the first space, adding the space character that comes right after it.
i am new to regular expressions. How can i get an array back with JUST
the words that are seperated, and none of the whitespace?
thanks

Answer 1

Its amazing how such a simple regex can cause so much
confusion (how many times has this been asked in the
forum?).
Sometimes the easiest solution is the best. This is
eactly what the StringTokenizer was written for. Its
simple, Once you know regex, this is much simpler than ST.
its efficientDo you have any evidence to suggest that ST's efficiency is significantly beter than regex's here?
and you don't have to learn a
new programming language to use it.Regex is a good thing to know though, and it applies outside of Java too. Assuming we're going to learn it at some point ayway, why not start now, with a relatively simple usage?