Generic classes and the catch block

Is there a reason why the catch block doesn't work with generic classes?

JLS 8.1.2:
<quote>
It is a compile-time error if a generic class is a direct or indirect subclass of Throwable.
</quote>
<quote>
This restriction is needed since the catch mechanism of the Java virtual machine works only with non-generic classes.
</quote>
I guess they didn't feel a need to tinker with the JVM definition to achieve that.
Too slow!
Message was edited by:
DrLaszloJamf

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I have three bean classes:
abstract public class Payment {
// common fields and their get/set methods
public final class AU_Payment
extends Payment {
// extra fields and their get/set methods
public final class US_Payment
extends Payment {
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I hope this all makes sense,
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ok, I'm assuming that you just forgot to paste in that AU_PaymentDB implements PaymentDB :-)
parameterize AU_PaymentDB as follows:
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gavas_java_nov26_exception wrote:
If i use System.exit(0) in the try block or catch block will finally block will be executed?
try
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System.exit(0);
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I have a simple Java project in Eclipse environment. The project has it's class path,
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The project runs perfect in the Eclipse.
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Okay, so, here I am designing the basic framework for a game. I'm going along quite wonderfully, when my hopes and dreams are suddenly shattered by a problem I had overlooked while in my planning phases. Here's my basic problem... consider the following code:
class MapTile
public abstract class MapTile{
}class EnvPiece
public class EnvPiece extends MapTile{
public void aRandomMethod();
}class PutTogether
public class PutTogether{
MapTile foo = new Tile();
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MapTile doesn't have aRnadomMethod. The compiler only knows that foo is a reference to a MapTile. It doesn't know that you happened to point it at a Tile (by which I assume you meant EvnPiece, or else EnvPiece should be changed to Tile for your post to make any sense).
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Generic classes and the catch block

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