Getting the current path of the file in a JavaBean

Question

Hello,
I'm using a JavaBean with a jsp code.
The JavaBean :
    public String  ValidateUser(String user,String pass)
          String Name = user;
          String Pass = pass;
          String  ReturnValue = "NOT OK";
        try
             Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
             Connection con=
                            DriverManager.getConnection("jdbc:odbc:Driver={Microsoft Access Driver (*.mdb)};DBQ=D:\\DB1.mdb;}");
                        Statement stmt=con.createStatement();
              ResultSet rs=stmt.executeQuery("select count(*) from users where username = '"
                      + Name + "' and password ='" +Pass +"'");
            while(rs.next())
                        if (rs.getInt(1) > 0 )
                            ReturnValue = "OK";
        catch(Exception e)
             StringWriter sw = new StringWriter();
            e.printStackTrace(new PrintWriter(sw));
            String stacktrace = sw.toString();
            ReturnValue = stacktrace;
        return ReturnValue;
    } Instead of using "DBQ=D:\\DB1.mdb;",
I want to get the path of the .class file i use in the jsp for example :
"D:\Program Files\Apache Software Foundation\Tomcat 6.0\webapps\DIMA\WEB-INF\classes\dalpkg".
This is where the .class file located.
Now I want to change this path to : "D:\Program Files\Apache Software Foundation\Tomcat 6.0\webapps\DIMA\WEB-INF\DBS\";
How can i do this?
Using System.getProperty("user.dir");
Gave me the Tomcat 6.0 home.
Thanks in advance guys.

Answer 1

Place it in the classpath, then you can use ClassLoader#getResource().