Group by and take the Max year Record

Question

Hi,
I have the data as below:
A     B     C     D     E
1     A     ACC     AAA     2008
1     A     BCC     BBB     2007
1     A     CCC     CCC     2009
2     B     ATT     TTT     2004
2     B     BYY     YYY     2009
2     B     CZZ     ZZZ     2006
Here I have to eliminate duplicates using A,B and take the record with max(E)
So output should be:
A     B     C     D     E
1     A     CCC     CCC     2009
2     B     BYY     YYY     2009
Please help me how i can do this.
Thanks in advance
Mahesh

Answer 1

Slightly shorter:
SQL> with t as (
  2   select 1 a, 'A' b, 'ACC' c, 'AAA' d, '2008' e from dual union all
  3   select 1, 'A', 'BCC', 'BBB', '2007' from dual union all
  4   select 1, 'A', 'CCC', 'CCC', '2009' from dual union all
  5   select 2, 'B', 'ATT', 'TTT', '2004' from dual union all
  6   select 2, 'B', 'BYY', 'YYY', '2009' from dual union all
  7   select 2, 'B', 'CZZ', 'ZZZ', '2006 ' from dual
  8  )
  9  --
10  --
11  select a,
12         max(b) keep (dense_rank last order by e) b,
13         max(c) keep (dense_rank last order by e) c,
14         max(d) keep (dense_rank last order by e) d,
15         max(e) e
16    from t
17  group by a
18  /
         A B C   D   E
         1 A CCC CCC 2009
         2 B BYY YYY 2009
2 rijen zijn geselecteerd.Regards,
Rob.