I need to show grouped id and only the max order value for each unique id

Question

select distinct 
Table1.id,
Table1.id +' - '+ Table1.VisitNumber +' : '+ Table1.Priority as UidVisitKey,
Table1.VisitNumber,
DATEDIFF(d, [dob],[Visite_dte])/365.25 as Age_On_Visit,
Table1.Priority,
Table1.OrderOfVisit,
Table1.OrderOfVisit + ' - ' + Table1.Notes AS VisitNote, 
Table1.Visitor_FName,
Table1.Visitor_SName,
Table2.dob,
Table2.sex,
Table1.Visit_dte,
into #Temp1
FROM         Table1 INNER JOIN
            Table2 ON Table1.id = Table2.id
WHERE Table1.LeaveDate IS NOT NULL 
and Table1.LeaveDate  between DATEADD(mm,-1,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)) 
and DATEADD(ms,-3,DATEADD(mm,0,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0))) 
select #Temp1.id, max(#Temp1.[OrderOfVisit]), #Temp1.VisitNote 
from #Temp1
group by #Temp1.id, #Temp1.OrderOfVisit, #Temp1.[VisitNote]
ORDER BY #Temp1.id
drop table #Temp1
---I need to show grouped id and only the max OrderOfVisit for each unique id, and the VisitNote for each OrderOfVisit
----------------need help-------------

Answer 1

Sounds like this
select distinct
Table1.id,
Table1.id +' - '+ Table1.VisitNumber +' : '+ Table1.Priority as UidVisitKey,
Table1.VisitNumber,
DATEDIFF(d, [dob],[Visite_dte])/365.25 as Age_On_Visit,
Table1.Priority,
Table1.OrderOfVisit,
Table1.OrderOfVisit + ' - ' + Table1.Notes AS VisitNote,
Table1.Visitor_FName,
Table1.Visitor_SName,
Table2.dob,
Table2.sex,
Table1.Visit_dte,
into #Temp1
FROM Table1 INNER JOIN
Table2 ON Table1.id = Table2.id
WHERE Table1.LeaveDate IS NOT NULL
and Table1.LeaveDate between DATEADD(mm,-1,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0))
and DATEADD(ms,-3,DATEADD(mm,0,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)))
select id,OrderOfVisit,VisitNote
from
select #Temp1.id, #Temp1.[OrderOfVisit], #Temp1.VisitNote,ROW_NUMBER() OVER (PARTITION BY #Temp1.id ORDER BY #Temp1.[OrderOfVisit] DESC) AS Seq
from #Temp1
)t
WHERE Seq = 1
ORDER BY id
drop table #Temp1
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