Hello, I am trying to insert a variable into php statement.

Hello, I am trying to insert a variable into this statement.
Variable name is $stable
<?php echo 'includes/ $stable .php ';?>

The above concatenation is my preferred method but the easiest to read is to use double quotes and curly braces:
<?php echo "includes/{$stable}.php"; ?>
There is a slight performance hit this way but on a small project it shouldn't make any difference.

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import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
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public class register extends HttpServlet {
public void doGet(HttpServletRequest request,
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}Message was edited by:
Altered_Carbon
Message was edited by:
Altered_Carbon
I also realise that this is a more MYSQL titled problem, but those forums look rubbish <_<

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phone 212 928 9581
fax 212 928 9582
159-00 Riverside Drive West #5H-70
NY, NY 10032
www.wordofmouthpros.com
"dbohea" <[email protected]> wrote in
message
news:e7e3p7$mb2$[email protected]..
> Hi.
>
> I am trying to insert a variable in place of a newly
defined property to
> be
> added to a poroperty list.
>
> This would normally add a new a new property to a
poroperty list :
>
> Database [#needtogetvariablehere] = typedPassword
>
> -- 'Database' is the property list,
'needtogetvariablehere' is the new
> poperty
> and 'typedPassword' is the new property's value -
thisall works fine.
>
> I'd like to generate new property names dynamically
using an editable text
> box. How do I replace the new property name '
nedtogetvariablehere' with
> a
> variable?
>
> I'm sure I've got to put some rounded brackets in
somewhere but everything
> I
> try spits out a syntax error.
>
> eg:
>
> myVariable = "blablabla"
>
> Database [#(myVariable)] = typedPassword
>
>
> Any ideas?
>
> Thanks.
>

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Hello, I am trying to insert a variable into php statement.

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