Help: "GROUP BY" with a "MAX"

Question

Let me try to explain this one and thank you in advance for your help
tblA : PK_SID, Name, Status
tblB :PK_ID(AUTONUMBER), SID, Date
Tables are in a one to many. With SID being the common field. I am trying to write a select statement that will group data from tblA and show the MAX(last) date of that item from tblB
Example
TblA
PK_SID Name Status
1 Laptop Good
2 Monitor Excellent
3 Desktop Good
4 Printer Moderate
5 Phone Good
6 Router Excellent
7 Switch Good
tblB
PK_ID     SID     DATE
001 3     08/01/07
003 6 07/15/07
004     3 08/10/07
002 1 06/15/07
010 2 05/01/07
015 4     04/08/07
016 4 08/02/07
009 6 02/03/07
OUTPUT SHOULD BE
PK_SID Name Status      LASTDATE
1     Laptop Good      06/15/07
2     Monitor Excellent     05/01/07
3     Desktop Good     08/10/07
4 Printer Moderate 08/02/07
5 Phone Good          
6 Router Excellent 07/15/07
7 Switch Good          
So essentially I have grouped all my items from tblA and included the last date they were used
including those that were not used

Answer 1

SQL> create table tbla
  2  as
  3  select 1 pk_sid, 'Laptop' name, 'Good' status from dual union all
  4  select 2, 'Monitor', 'Excellent' from dual union all
  5  select 3, 'Desktop', 'Good' from dual union all
  6  select 4, 'Printer', 'Moderate' from dual union all
  7  select 5, 'Phone', 'Good' from dual union all
  8  select 6, 'Router', 'Excellent' from dual union all
  9  select 7, 'Switch', 'Good' from dual
10  /
Tabel is aangemaakt.
SQL> create table tblb
  2  as
  3  select '001' pk_id, 3 sid, date '2007-08-01' bdate from dual union all
  4  select '003', 6, date '2007-07-15' from dual union all
  5  select '004', 3, date '2007-08-10' from dual union all
  6  select '002', 1, date '2007-06-15' from dual union all
  7  select '010', 2, date '2007-05-01' from dual union all
  8  select '015', 4, date '2007-04-08' from dual union all
  9  select '016', 4, date '2007-08-02' from dual union all
10  select '009', 6, date '2007-02-03' from dual
11  /
Tabel is aangemaakt.
SQL> select a.pk_sid
  2       , a.name
  3       , a.status
  4       , max(b.bdate)
  5    from tbla a
  6       , tblb b
  7   where a.pk_sid = b.sid (+)
  8   group by a.pk_sid
  9       , a.name
10       , a.status
11   order by a.pk_sid
12  /
    PK_SID NAME    STATUS    MAX(B.BDATE)
         1 Laptop  Good      15-06-2007 00:00:00
         2 Monitor Excellent 01-05-2007 00:00:00
         3 Desktop Good      10-08-2007 00:00:00
         4 Printer Moderate  02-08-2007 00:00:00
         5 Phone   Good
         6 Router  Excellent 15-07-2007 00:00:00
         7 Switch  Good
7 rijen zijn geselecteerd.Regards,
Rob.