Help , initial question solved , just stuck on the last step , I seek help

Question

Hi All,
I have a string : 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
Now I want each alphabet in a single row , giving me 26 different rows.
I want to achieve this :
1) without using connect by clause.
2) with using connect by clause
my connect by clause query is working fine in oracle 10G(my friends database) but not in oracle 9i
here it is:
select substr(a.string,rownum,1)
from
(select 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' string from dual )a
connect by rownum <= length(a.string)
PS : I want queries for oracle 9i only
Regards
Rahul
Edited by: Mac_Freak_Rahul on Sep 19, 2010 6:21 AM
Edited by: Mac_Freak_Rahul on Sep 19, 2010 8:10 AM
Edited by: Mac_Freak_Rahul on Sep 19, 2010 8:27 AM

Answer 1

In 9i CONNECT BY LEVEL can't be in main query. It must be in an inline view. But there is no need for that many inline view levels like in ManishB's example:
SQL> select substr(a.string,rownum,1)
  2  from
  3  (select 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' string from dual )a
  4  connect by rownum <= length(a.string)
  5  /
S
A
SQL> select  *
  2    from  (
  3           select  substr('ABCDEFGHIJKLMNOPQRSTUVWXYZ',level,1) letter
  4             from  dual
  5             connect by level <= length('ABCDEFGHIJKLMNOPQRSTUVWXYZ')
  6          )
  7  /
L
A
B
C
D
E
F
G
H
I
J
K
L
L
M
N
O
P
Q
R
S
T
U
V
L
W
X
Y
Z
26 rows selected.
SQL>  And if you always need 26 letters you can change
connect by level <= length('ABCDEFGHIJKLMNOPQRSTUVWXYZ')to
connect by level <= 26Other method could be:
select  substr('ABCDEFGHIJKLMNOPQRSTUVWXYZ',rownum,1) letter
  from  all_objects
  where rownum <= 26
/But it relies on all_objects having at least 26 rows.
SY.