Just stuck on the final step

Question

somebody asked me to extract the alternate alphabets from the string. Now the thing is I have extracted the alternate alphabets but I am getting a space between them , Could somebody provide me a better solution or trim the spaces in my outermost query.
Output I am getting : a c e g i k m o q s u w y
Desired Output : acegikmoqsuwy
select max(sys_connect_by_path(b.letter,' '))
from
(select a.letter , rownum curr , rownum-1 prev
from
(select rownum count,SUBSTR('ABCDEFGHIJKLMNOPQRSTUVWXYZ',rownum,1) letter
from All_Objects
where rownum <= LENGTH('ABCDEFGHIJKLMNOPQRSTUVWXYZ')) a
where mod(a.count,2)=1) b
start with b.CURR = 1
connect by prior b.curr = b.prev
Regards
Rahul

Answer 1

SQL> select REPLACE(max(sys_connect_by_path(b.letter,'.')),'.')
  2  from
  3  (select a.letter , rownum curr , rownum-1 prev
  4  from
  5  (select rownum count,SUBSTR('ABCDEFGHIJKLMNOPQRSTUVWXYZ',rownum,1) letter
  6  from All_Objects
  7  where rownum <= LENGTH('ABCDEFGHIJKLMNOPQRSTUVWXYZ')) a
  8  where mod(a.count,2)=1) b
  9  start with b.CURR = 1
10  connect by prior b.curr = b.prev;
REPLACE(MAX(SYS_CONNECT_BY_PATH(B.LETTER,'.')),'.')
ACEGIKMOQSUWY
select REPLACE(max(sys_connect_by_path(b.letter,' ')),' ')
from
(select a.letter , rownum curr , rownum-1 prev
from
(select rownum count,SUBSTR('ABCDEFGHIJKLMNOPQRSTUVWXYZ',rownum,1) letter
from All_Objects
where rownum <= LENGTH('ABCDEFGHIJKLMNOPQRSTUVWXYZ')) a
where mod(a.count,2)=1) b
start with b.CURR = 1
connect by prior b.curr = b.prevEdited by: Saubhik on Sep 20, 2010 1:42 AM