Help on understanding about gtk+

From the research of me, I found out that the gtk is dependencies on Pango,Glib,Atk, libiconv and gcc.
Can we install the Gtk without all this package libraries?
Why?
Thanks for help.

Similar Messages

Need help to understand about cluster

Hi,
I am a SQL developer, and need a little help to understand what clusters are. I never came across to create any cluster. Can someone plz help me with simple example, what is cluster and in which situation we create cluster?
Thanks
Shantanu

>
I am a SQL developer, and need a little help to understand what clusters are. I never came across to create any cluster. Can someone plz help me with simple example, what is cluster and in which situation we create cluster?
>
A cluster is used to store data from more than table together. The data would typically share the primary key. For example the scott DEPT and EMP table data is related based on the DEPTNO value so DEPTNO could be the cluster key.
If you created a cluster and then created copies of those tables in the cluster (e.g. myDEPT and myEMP) Oracle would store the dept and emp data for the same DEPTNO value together, even in the same block.
Then when you query dept and emp data using DEPTNO it will be faster to retrieve the DEPT and EMP data for that department since it is colocated in the same blocks.
The drawbacks are that when you only want data from one of the tables (e.g. emp) Oracle has to skip over the DEPT data since some of it will be in the same blocks that the EMP data is in.
So clusters and clustered tables are most useful when you always query multiple cluster tables using the cluster key. For some other operations they can be very inefficient.
See the Admin Guide for an example using the DEPT and EMP tables
http://docs.oracle.com/cd/E11882_01/server.112/e25494/clustrs003.htm#ADMIN11747

Need help to understand INSTALL command based on GPspec 2.1.1

Hi Friends..
Sorry before, i couldn't understand some commands based on GPSpec 2.1.1, i'm pretty new in this field..
So, i need your help to help me understand about the commands..
Firstly, i want to know what exactly the DATA that referred by INSTALL Command..
here's outlined in the GPSpec 2.1.1 for INSTALL Command (Chapter 9)..
CLA = '80' or '84'
INS = 'E6'              //INSTALL
P1   = 'xx'               //Reference control parameter P1
P2   = '00'               //Reference control parameter P2
Lc   = 'xx'                //Length of data field
Data 'xxxx'           //Install data (and MAC if present)
Le   = '00'What exactly the data referred?.
I thought the data which referred can be Applets, Packages, CAP files..
So, how to know the LC and Sequence bytes of the Applets/ Packages/ CAP files..
i found this LINK..
In the website i read an example of INSTALL Command..
Here's an example mentioned in the link above..
INSTALL FOR LOAD
84 E6 02 00 2B 10 A0 00 00 00 18 50 00 00 00 00 00 00 52 41 44 50 00 00 0E EF 0C C6 02 00 00 C8 02 00 00 C7 02 00 00 00 2A 8B 3A 01 3C 8E FD A4 (00)
00, 90 00 [Normal ending of the command.] Sorry, i'm still not understand about it..
Please help me regarding this..
Sorry, perhaps this question sounds silly..
Thanks in advance..

Hi,
As a hint, you want to use INSTALL for install and make selectable. You can have a look at the APDU that GPShell sends through for the final install command (hint: it will be a part of the load command). You can also execute install_for_load, load and install_for_install in GPShell to see these commands. The GP card spec is a little confusing for the INSTALL command so tracing GPShell may help you understand it.
Cheers,
Shane

Need help in understanding why so many gets and I/O

Hi there,
I have a sql file somewhat similar in structure to below:
delete from table emp;-- changed to Truncate table emp;
delete from table dept;--changed to Truncate table dept;
insert into emp values() select a,b,c from temp_emp,temp_dept where temp_emp.id=temp_dept.emp_id
update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);
commit --only at the end
the above file takes about 9-10 hrs to complete its operation. and
the values from v$sql for the statement
update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);
are as below:
SHARABLE_MEM PERSISTENT_MEM RUNTIME_MEM SORTS LOADED_VERSIONS OPEN_VERSIONS USERS_OPENING FETCHES EXECUTIONS PX_SERVERS_EXECUTIONS END_OF_FETCH_COUNT USERS_EXECUTING LOADS FIRST_LOAD_TIME INVALIDATIONS PARSE_CALLS DISK_READS DIRECT_WRITES BUFFER_GETS APPLICATION_WAIT_TIME CONCURRENCY_WAIT_TIME CLUSTER_WAIT_TIME USER_IO_WAIT_TIME PLSQL_EXEC_TIME JAVA_EXEC_TIME ROWS_PROCESSED COMMAND_TYPE OPTIMIZER_MODE OPTIMIZER_COST OPTIMIZER_ENV OPTIMIZER_ENV_HASH_VALUE PARSING_USER_ID PARSING_SCHEMA_ID PARSING_SCHEMA_NAME KEPT_VERSIONS ADDRESS TYPE_CHK_HEAP HASH_VALUE OLD_HASH_VALUE PLAN_HASH_VALUE CHILD_NUMBER SERVICE SERVICE_HASH MODULE MODULE_HASH ACTION ACTION_HASH SERIALIZABLE_ABORTS OUTLINE_CATEGORY CPU_TIME ELAPSED_TIME OUTLINE_SID CHILD_ADDRESS SQLTYPE REMOTE OBJECT_STATUS LITERAL_HASH_VALUE LAST_LOAD_TIME IS_OBSOLETE CHILD_LATCH SQL_PROFILE PROGRAM_ID PROGRAM_LINE# EXACT_MATCHING_SIGNATURE FORCE_MATCHING_SIGNATURE LAST_ACTIVE_TIME BIND_DATA TYPECHECK_MEM
18965 8760 7880 0 1 0 0 0 2 0 2 0 2 2011-05-10/21:16:44 1 2 163270378 0 164295929 0 509739 0 3215857850 0 0 20142 6 ALL_ROWS 656 E289FB89A4E49800CE001000AEF9E3E2CFFA331056414155519421105555551545555558591555449665851D5511058555155511152552455580588055A1454A8E0950402000002000000000010000100050000002002080007D000000000002C06566001010000080830F400000E032330000000001404A8E09504646262040262320030020003020A000A5A000 4279923421 50 50 APPS 0 00000003CBE5EF50 00 1866523305 816672812 1937724149 0 SYS$USERS 0 01@</my.sql -2038272289 -265190056 0 9468268067 10420092918 00000003E8593000 6 N VALID 0 2011-05-11/10:23:45 N 5 0 0 1.57848E+19 1.57848E+19 5/12/2011 4:39 0
1) how do i re-write this legacy script? and what should be done to improve performance?
2) Should i use PL/sql to re-write it?
3) Also help in understanding why a simple update statement is doing so many buffer gets and reading , Is this Read consistency Trap as i'm not committing anywhere in between or it is actually doing so much of work.
(assume dept table has cols emp_name and emp_id also)

update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);I guess that these are masked table names ? Nobody would have emp_name in a dept table.
Can you re-format the output, using "code" tags ( [ or { }
Hemant K Chitale
Edited by: Hemant K Chitale on May 12, 2011 12:44 PM

Help me please about export file is .wmv

help me please about export file is .wmv from final cut pro
It have black side at right and left in clip when export finished
I have flip4mac program in my mac
How do I edit.

Let me help getting your question back to something we might understand.
- You are exporting your video AS .wmv
and
- when you export it, there are black bars left and right of the image.
How do you fix?
Ok - what was the format of the video prior to your exporting it? When you edited it in FCP, what were the sequence settings? That will help get the right settings for flip4mac.
CaptM

Can you please help to understand how the firefox decides on the Expires date for a cached javascript file ( my server did not set any Expire header, but firebox set it down).

# Question
Can you please help to understand how the firefox decides on the Expires date for a cached javascript file ( my server did not set any Expire header, but firebox set it down). I tried to understand but different javascript file gets different Expires date value when it is being cached. Please help me as I tried lot and could not get proper answer for this. Thanks in Advance.

Try posting at the Web Development / Standards Evangelism forum at MozillaZine. The helpers over there are more knowledgeable about web page development issues with Firefox. <br />
http://forums.mozillazine.org/viewforum.php?f=25 <br />
You'll need to register and login to be able to post in that forum.

PCI cards, Airport cards...help me understand what is what and why?

Help me understand this wireless network "card" hardware stuff.
I have a dual 867 MHz G4 that I want to set up for networking with a PC so that both machines can access the internet (via DSL).
As far as I know, my Mac does not have an airport card of any kind. I'm planning to buy a Lynksys WRT 54G2 wireless router. Do I need to also install an airport card, or PCI card in my G4 to make this all happen? And, if so, what is recommended that will work with my G4?
The guys at the Apple store are telling me that all I need is a wireless router, and don't have to install anything extra, but what I'm reading on these various networking threads, is that just the G4 and a wireless router will not do the trick. After reading lots of threads here, it's sounding like I have to jump through hoops to set up a usable, working network. The Apple guy says that this is easy and basic. I'm thinking that THEY are thinking in terms of a newer machine, maybe? They're all young guys who probably think that nothing goes back farther than the iMac.
One thing the Apple guys were pushing is Airport Extreme, but at $180, I somehow thing I can get there for much less than that.
To make a long story short (hah...too late for that), what exactly do I need as far as a card, router, etc., and where do I get the right stuff (links would be helpful) to set up a Mac/PC network using my old decrepit G4?

Hi-
Networking Macs and PCs
Setup a Home Network
Create a small Ethernet network
MacWireless
Check the above links, and you will be better educated in the basics and requirements of various networks.
The easiest, and least hardware intensive is the Ethernet network. Also, Ethernet is fast.
A note about Airport; you machine only accepts standard 802.11b Airport cards. In a word, very slow.
Airport Extreme, or 802.11g, is much faster, and 802.11n is the fastest available. To get 802.11g or 802.11n in your machine will require a PCI adapter.

Can anyone help me understand how font sizes work in Mail?

Hi
I am used to writing and sending emails in Arial 10 (on my PC using Outlook) - it seems like a professional sort of size to send to people.
So I have set the Mail Preferences Fonts to Arial 10 for the message font
But when I receive emails, the font is so small I can barely read it. I have a new 24" iMac and just cannot get to grips with keeping font sizes at a reasonable level between applications. And I though Mac was supposed to be joined up....
As I write the text of this posting, the font is a good size to read (although still looks blurred - see my other postings) - it is in Arial which I want.... But I cannot get Mail to wrk in the same way.
I do not want to change the font size to the email messages to a bigger font size, as I want my outgoing messages to be received in font size 10.
Please help me understand how this is all supposed to work in MAC? It was all so easy on a PC!

No, it is one of several unfathomable shortcomings in Mail that you are unable to set a minimum text viewing size. I too have 24in iMac and I have to enlarge each incoming message manually using Cmd+ and this is frankly Stone Age stuff, especially when dealing with hundreds of emails every day. Another very poor alternative is to use Ctrl and the scroll wheel to zoom in but your head will soon be spinning as the screen moves around.
FWIW, I am also dismayed that Apple has disabled the Contextual Menu in 3 of the 4 mail address fields. There must be some obscure justification for limiting CM copy and paste to just the Subject field but I just think it's risible.
And why can't I save a message I have just written to a place of my choosing? Instead I must save it to the Drafts folder or send it first and then Save As from the Sent mailbox. Is this someone's idea of fun?
I could go on about Mail's shortcomings but that's enough ranting for now...
Simon

Help required understanding steps of Transfer Workflow:WS01000014

Hi All,
Please help me understand the steps of this workflow..i have already gone thru some explaination about this workflow from this [link|http://www.sapfans.com/forums/viewtopic.php?f=11&t=292192&start=0&st=0&sk=t&sd=a] but getting confused with few steps.
Correct me if i am wrong ..the workflow is triggered when a new position is created?(to which employee is going to be transffered?)
In step1:check target postion..of who? and then what happens?
step on user and role is confusing too
there are two specify postion in two departments..what are the two postions for ? 1 fro employee and one for his new manager/hr admin?
pls advice
thanks in advance

Hello,
The workflow is triggered when an instance of object ORGCHEARM
issues the event CREATED - ie there has been an organizational change.
Step 1 is condition "Check Target Position" :
( Designation.Root <> 'P'     and
Designation.Object Type <> ''     and
Designation.Object ID   <>     00000000
) or
( Designation.Root = 'P'     and
Designation.Object Type = 'S'     and
Designation.Object ID   <>     00000000
If true then continue, if false: Specify Agent.
Specify Agent branches according to type of
Agent Specification. The condition is:
Designation.User Name <> ''
In both cases task TS01000118 (Specify Position in New Department)
is called. If the condition was true then it's called with as agent
the contents of ORGCHEARM.ACROSSBORDERUSER; if not true then
the role AC0000168 is used to determine the superior(s) of the
"object type affected" and they are used as the agents (ie they receive the workitem).
Hope this helps.
regards,
Rick Bakker
Hanabi Technology

Can anyone help me understand "Continue Statements"?

Hi,
I was wondering if anyone could help me understand continue statements. I've been studying the java tutorials this weekend but can not get my head around the following explanation: (My thoughts are at the end of this message and it might be easiest to read them first!)
"The continue statement skips the current iteration of a for, while , or do-while loop. The unlabeled form skips to the end of the innermost loop's body and evaluates the boolean expression that controls the loop. The following program, ContinueDemo , steps through a String, counting the occurences of the letter "p". If the current character is not a p, the continue statement skips the rest of the loop and proceeds to the next character. If it is a "p", the program increments the letter count.
{code}class ContinueDemo {
public static void main(String[] args) {
String searchMe = "peter piper picked a peck of pickled peppers";
int max = searchMe.length();
int numPs = 0;
for (int i = 0; i < max; i++) {
//interested only in p's
if (searchMe.charAt(i) != 'p')
continue;
//process p's
numPs++;
System.out.println("Found " + numPs + " p's in the string.");
}{code}
Here is the output of this program:
Found 9 p's in the string.
To see this effect more clearly, try removing the continue statement and recompiling. When you run the program again, the count will be wrong, saying that it found 35 p's instead of 9.
A labeled continue statement skips the current iteration of an outer loop marked with the given label. The following example program, ContinueWithLabelDemo, uses nested loops to search for a substring within another string. Two nested loops are required: one to iterate over the substring and one to iterate over the string being searched. The following program, ContinueWithLabelDemo, uses the labeled form of continue to skip an iteration in the outer loop.
{code}class ContinueWithLabelDemo {
public static void main(String[] args) {
String searchMe = "Look for a substring in me";
String substring = "sub";
boolean foundIt = false;
int max = searchMe.length() - substring.length();
test:
for (int i = 0; i <= max; i++) {
int n = substring.length();
int j = i;
int k = 0;
while (n-- != 0) {
if (searchMe.charAt(j++)
!= substring.charAt(k++)) {
continue test;
foundIt = true;
break test;
System.out.println(foundIt ? "Found it" :
"Didn't find it");
}{code}
Here is the output from this program.
Found it"
Here are Woodie's thoughts........................................
1) With the first program I don't understand how the program counts the number of "p's". Like for example how it stores the number of "p's". Shouldn't it say:
if (searchMe.charAt(i) = 'p') then store it in some sort of containers??? 2) With the second program, I don't understand the test section. For example: Why does it have --? why does it have != after while and why does it have != after if?
while (n-- != 0)
                if (searchMe.charAt(j++) != substring.charAt(k++))
                    continue test;
            foundIt = true;
                 break test;Edited by: woodie_woodpeck on Nov 23, 2008 3:29 AM

Woodie, I think they're just silly "theoretical" examples... ergo don't worry too much not understanding them, coz they don't actually make a lot of sense... as you've allready pointed out there are other "more normal" control structures which achieve the same thing, and which in this case (in my humble opinion) would make for clearer, more concise, more maintainable code.
All you need to know about continue is "it means go back to the top of the loop"... If you're not comfortable using "continue" then don't.
There's more than one way to do it.
public static void main(String[] args) {
    try {
      final String s = "peter piper picked a peck of pickled peppers";
      int count = 0;
      for ( char c : s.toStringArray() ) {
        if (c=='p') count++;
      System.out.println("There are "+count+ " p's in '"+s+"'");
    } catch (Exception e) {
      e.printStackTrace();
}Having said all that... I did use continue in anger the other day... I was reading Geometries from a shape file... the reader was throwing an ArrayIndexOutOfBoundsException given an "empty Feature" (ie a feature with the geospatial presence)... All I did was catch the exception and continue trying to read the new feature... the alternative would have been to rewrite the control logic of the whole reader loop... quick, simple effective... but I don't routinely build continue statements into new code... just a matter of personal taste.
Cheers. Keith.

I don;t understand about Rsum

hi all
i don't understand about running functions....
when we have to go for running functions... so far i did not use running functions;
please any one tell me about running functions... i searched about running functions but i am not that much clear on it
Tell me few words about RSUM,..
Thanks

You get more detail in the Help
Just for your information:
This function calculates a running sum based on records encountered so far. The sum for the first row is equal to the numeric expression for the first row. The sum for the second row is calculated by taking the sum of the first two rows of data. The sum for the third row is calculated by taking the sum of the first three rows of data, and so on.
Syntax:
RSUM (n_expression)
Where:
n_expression
Any expression that evaluates to a numerical value.
Example:
The following example shows a query that uses the RSUM function and the query results.
select month, revenue, RSUM(revenue) as RUNNING_SUM from sales_subject_area
MONTH REVENUE RUNNING_SUM
JAN 100.00 100.00
FEB 200.00 300.00
MAR 100.0 400.00
APRIL 100.00 500.00
MAY 300.00 800.00
JUNE 400.00 1200.00
Hope its clear now :)

Error Posting IDOC: need help in understanding the following error

Hi ALL
Can you please, help me understand the following error encountered while the message was trying to post a IDOC.
where SAP_050 is the RFC destination created to post IDOCs
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
- 
- <SAP:Error xmlns:SAP="http://sap.com/xi/XI/Message/30" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" SOAP:mustUnderstand="">
<SAP:Category>XIAdapter</SAP:Category>
<SAP:Code area="IDOC_ADAPTER">ATTRIBUTE_IDOC_RUNTIME</SAP:Code>
<SAP:P1>FM NLS_GET_LANGU_CP_TAB: Could not determine code page with SAP_050 Operation successfully executed FM NLS_GET_LANGU_CP_TAB</SAP:P1>
<SAP:P2 />
<SAP:P3 />
<SAP:P4 />
<SAP:AdditionalText />
<SAP:ApplicationFaultMessage namespace="" />
<SAP:Stack>Error: FM NLS_GET_LANGU_CP_TAB: Could not determine code page with SAP_050 Operation successfully executed FM NLS_GET_LANGU_CP_TAB</SAP:Stack>
<SAP:Retry>M</SAP:Retry>
</SAP:Error>
Your help is greatly appreciated.............Thank you!

Hi Patrick,
Check the authorizations assigned to the user which you used in the RFC destinations, If there is no enough authorizations then it is not possible to post the idocs.
Also Refer this Note 747322
Regards,
Prakash

E-Rows = NULL and A-Rows=42M? Need help in understanding why.

Hi,
Oracle Standard Edition 11.2.0.3.0 CPU Oct 2012 running on Windows 2008 R2 x64. I am using Oracle 10g syntax for WITH clause as the query will also run on Oracle 10gR2. I do not have a Oracle 10gR2 environment at hand to comment if this behaves the same.
Following query is beyond me. It takes around 2 minutes to return the "computed" result set of 66 rows.
SQL> WITH dat AS
2          (SELECT 723677 vid,
3                  243668 fid,
4                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
5                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
6             FROM DUAL
7           UNION ALL
8           SELECT 721850,
9                  243668,
10                  TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
11                  TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
12             FROM DUAL
13           UNION ALL
14           SELECT 723738,
15                  243668,
16                  TO_DATE ('16.03.2013', 'dd.mm.yyyy'),
17                  TO_DATE (' 04.04.2013', 'dd.mm.yyyy')
18             FROM DUAL)
19      SELECT /*+ GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
20        FROM dat
21 CONNECT BY LEVEL <= maxdt - mindt + 1
22 order by fid, vid, dtshow;
66 rows selected.
SQL>
SQL> SELECT * FROM TABLE (DBMS_XPLAN.display_cursor (NULL, NULL, 'ALLSTATS LAST'));
PLAN_TABLE_OUTPUT
SQL_ID 9c4vma4mds6zk, child number 0
WITH dat AS         (SELECT 723677 vid,                 243668 fid,
            TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt            FROM DUAL
UNION ALL          SELECT 721850,                 243668,
   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),                 TO_DATE ('
22.03.2013', 'dd.mm.yyyy')            FROM DUAL          UNION ALL
    SELECT 723738,                 243668,                 TO_DATE
('16.03.2013', 'dd.mm.yyyy'),                 TO_DATE (' 04.04.2013',
'dd.mm.yyyy')            FROM DUAL)     SELECT /*+
GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
    FROM dat CONNECT BY LEVEL <= maxdt - mindt + 1 order by fid, vid,
dtshow
Plan hash value: 1865145249
| Id | Operation                              | Name | Starts | E-Rows | A-Rows |   A-Time   | OMem | 1Mem | Used-Mem |
|   0 | SELECT STATEMENT                       |      |      1 |        |     66 |00:01:54.64 |       |       |          |
|   1 | SORT UNIQUE                           |      |      1 |      3 |     66 |00:01:54.64 | 6144 | 6144 | 6144 (0)|
|   2 |   CONNECT BY WITHOUT FILTERING (UNIQUE)|      |      1 |        |     42M|00:01:04.00 |       |       |          |
|   3 |    VIEW                                |      |      1 |      3 |      3 |00:00:00.01 |       |       |          |
|   4 |     UNION-ALL                          |      |      1 |        |      3 |00:00:00.01 |       |       |          |
|   5 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   6 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   7 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
--------------------------------------------------------------------------------------------------------------------------If I take out one of the UNION queries, the query returns in under 1 second.
SQL> WITH dat AS
2          (SELECT 723677 vid,
3                  243668 fid,
4                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
5                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
6             FROM DUAL
7           UNION ALL
8           SELECT 721850,
9                  243668,
10                  TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
11                  TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
12             FROM DUAL)
13      SELECT /*+ GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
14        FROM dat
15 CONNECT BY LEVEL <= maxdt - mindt + 1
16 order by fid, vid, dtshow;
46 rows selected.
SQL>
SQL> SELECT * FROM TABLE (DBMS_XPLAN.display_cursor (NULL, NULL, 'ALLSTATS LAST'));
PLAN_TABLE_OUTPUT
SQL_ID 1d2f62uy0521p, child number 0
WITH dat AS         (SELECT 723677 vid,                 243668 fid,
            TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt            FROM DUAL
UNION ALL          SELECT 721850,                 243668,
   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),                 TO_DATE ('
22.03.2013', 'dd.mm.yyyy')            FROM DUAL)     SELECT /*+
GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
    FROM dat CONNECT BY LEVEL <= maxdt - mindt + 1 order by fid, vid,
dtshow
Plan hash value: 2232696677
| Id | Operation                              | Name | Starts | E-Rows | A-Rows |   A-Time   | OMem | 1Mem | Used-Mem |
|   0 | SELECT STATEMENT                       |      |      1 |        |     46 |00:00:00.01 |       |       |          |
|   1 | SORT UNIQUE                           |      |      1 |      2 |     46 |00:00:00.01 | 4096 | 4096 | 4096 (0)|
|   2 |   CONNECT BY WITHOUT FILTERING (UNIQUE)|      |      1 |        |     90 |00:00:00.01 |       |       |          |
|   3 |    VIEW                                |      |      1 |      2 |      2 |00:00:00.01 |       |       |          |
|   4 |     UNION-ALL                          |      |      1 |        |      2 |00:00:00.01 |       |       |          |
|   5 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   6 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
26 rows selected.What I cannot understand is why the E-Rows is NULL for "CONNECT BY WITHOUT FILTERING (UNIQUE)" step and A-Rows shoots up to 42M for first case. The behaviour is the same for any number of UNION queries above two.
Can anyone please help me understand this and aid in tuning this accordingly? Also, I would be happy to know if there are better ways to generate the missing date range.
Regards,
Satish

May be, this?
WITH dat AS
            (SELECT 723677 vid,
                    243668 fid,
                    TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
                    TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
               FROM DUAL
             UNION ALL
             SELECT 721850,
                    243668,
                   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
                   TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
              FROM DUAL
            UNION ALL
            SELECT 723738,
                   243668,
                   TO_DATE ('16.03.2013', 'dd.mm.yyyy'),
                   TO_DATE (' 04.04.2013', 'dd.mm.yyyy')
              FROM DUAL)
       SELECT vid, fid, mindt - 1 + LEVEL dtshow
         FROM dat
CONNECT BY LEVEL <= maxdt - mindt + 1
      and prior vid = vid
      and prior fid = fid
      and prior sys_guid() is not null
order by fid, vid, dtshow;
66 rows selected.
Elapsed: 00:00:00.03

Can you help me understand the use of the word POSITION in TR and CFM?

Hi,
I am trying to have a view of typical BI reports in TR and TM/CFM so through my research I came to the following link:.
http://help.sap.com/saphelp_nw2004s/helpdata/en/62/08193c38f98e1ce10000000a11405a/frameset.htm
My problem on this link and other postings on this site seem to be the same. Can you help me understand the use of the word POSITIONS in these context:
1. Our client has asked for financial transaction reports in BW, such as position of Borrowings, Investments and Hedge Operations (TM data).
2. I have a requirement on, some reports related to Money Market (Fixed Term Deposits, Deposits at Notice) something on FSCM-Treasury and Risk Manager. These reports will be similar to that of Loans, i.e. Position statement, flow statement, etc.
3. The set of position values for a single position or a limited amount of positions can be reported by transactions TPM12 and TPM13 in R3.
4. 0CFM_C10 (Financial Positions Cube)
Do you have some simple report outputs to help clarify how the word POSITION is used in such environments?
Thanks
Edited by: AmandaBaah on Feb 15, 2010 4:39 PM

If I future buy 10 shares in company at £1 per share - at the end of the day my potential value is £10
The next day the shares drop tp £0.9 per share - I have a negative position - my shares are only worth £9
I haven;t bought them yet - but I have a negative position - ie if things stayed as they are - I am going to realise (ie end up with) a loss
Now you can use this for loans and foreign exchange banks as well...

Duplicate partitions, need help to understand and fix.

So I was looking for a USB that I plugged in and went into /media/usbhd-sdb4/miles and realized all its contents was from my home directory.
So I created a random file in my home directory to see if it would also update /media/usbhd-sdb4/miles , and it did.
Can someone help me understand what is happening?
Also if I can fuse sdb4 and sdb2 as one, and partition it as my home directory without losing its contents?
Below is some information that I think would be helpful.
Thank you.
[miles]> cd /media/usbhd-sdb4/
[usbhd-sdb4]> ls -l
total 20
drwx------ 2 root root 16384 May 28 14:16 lost+found
drwx------ 76 miles users 4096 Oct 15 00:42 miles
[usbhd-sdb4]> cd miles
[miles]> pwd
/media/usbhd-sdb4/miles
[miles]>
lsblk
NAME MAJ:MIN RM SIZE RO TYPE MOUNTPOINT
sda 8:0 0 465.8G 0 disk
├─sda1 8:1 0 19.5G 0 part
└─sda2 8:2 0 446.2G 0 part
sdb 8:16 0 465.8G 0 disk
├─sdb1 8:17 0 102M 0 part /media/usbhd-sdb1
├─sdb2 8:18 0 258.9M 0 part [SWAP]
├─sdb3 8:19 0 14.7G 0 part /
└─sdb4 8:20 0 450.8G 0 part /media/usbhd-sdb4
sr0 11:0 1 1024M 0 rom

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