Help Please: Split Function or any other SQL server possible way?

Hi SQL gurus,
I need to thank you ahead of time for even reading this post as I am a newb to SQL server. Below is a field in a database that has a delimiter of "|" and I need to break up that value every time the "|" appears.
Value In Database:
Item - Felt Strip | Type - General Purpose | Material - Wool Felt | Backing Type - Plain | Thickness - 1/4" | Width - 1" | Length - 12" | Grade - F5 | Color - Off White | Density (Lbs./Sq. Yd.) - 3 | Min. Temp. Rating (Deg. F) - -80 | Max.
Temp. (F) - 200 | Vibration Absorption - Medium | Abrasion Resistance - Good | Durometer - 20 to 30 Shore A | Tensile Strength (PSI) - 400 | Hardness - Medium | Application - For Dust Shields, Bumpers, Pads, Wipers
Value I need to report:
Item
Type
Material
Backing Type
Thickness
Felt Strip
General Purpose
Wood Felt
Plain
1/4"
Is this possible with a little SQL magic? Thank you again.
Edwin Lopera

Hi Olaf,
Why do you add ItemPos +7 and then TypePos +9? And is it always going to be 7 and 9? Thank you
SELECT SUBSTRING(val, ItemPos + 7, TypePos - ItemPos - 9) as [Item]
,SUBSTRING(val, TypePos + 7, MatPos - TypePos - 9) as [Type]
Edwin Lopera

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Hi Amr,
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Can we achieve like functionality with any other way

Hi experts,
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Is there any MS Sql Server connector available for Flex Air.?

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ODBC function SQLDriverConnect() crashes with SQL Server 2008 R2

When calling the SQLDriverConnect() function from a 64-bit process and selecting a system DSN with a SQL Server Native Client 10.0 ODBC driver with SQL Server 2008 R2 SP3, then this call crashes here:
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int _tmain(int argc, _TCHAR* argv[])
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ret = SQLAllocHandle(SQL_HANDLE_DBC, hEnv, &hDbc);
assert(ret == SQL_SUCCESS || ret == SQL_SUCCESS_WITH_INFO);
SQLTCHAR szConnection[2048];
SQLSMALLINT cbChars;
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else
fprintf(stdout, "Success\r\n");
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The stdafx.h contains the following includes:
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#include <stdio.h>
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Sofiya Li
TechNet Community Support

Help with copying SP List data to SQL Server

I need to read some data from a SP list and copy it to a table in SQL Server.
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way they say it should (such as OData connection in SSIS). Maybe it's version issues.
Does anyone have a solid step-by step to do this? I am not a C# developer...

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https://msdn.microsoft.com/en-us/library/ms233812.aspx
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Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
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Jerry Guo
TechNet Community Support

Split TempDb in SharePoint 2010 Sql Server DB

Hi ,
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By the time of we have the largest content database is 260 in size and SQL Server has a 2-core processor.
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Kinldy suiggest hopw to split TempDb.
Hasan Jamal Siddiqui(MCTS,MCPD,ITIL@V3),Sharepoint and EPM Consultant,TCS
|
| Twitter

Hi Shanky,
We are not facing any issue,But we had take Micorosft RaaS services,Microsoft Consutlatan suggest thet we should break oure TempDb
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http://technet.microsoft.com/en-us/library/ms175527(v=SQL.105).aspx
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STATUS
SharePoint administrators will work on the action plan.
Downtime required for to apply this action plan? YES
Hasan Jamal Siddiqui(MCTS,MCPD,ITIL@V3),Sharepoint and EPM Consultant,TCS
|
| Twitter

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Need help with Thin JDBC connecting Oracle to SQL server.

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Quattro,
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Yes, you can do that. For testing purposes you can also create simple files (with mkfile) and add these to ASM. That way you could also experiment with deleting files and see what happens in ASM
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Dear All,
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/u01/app/oracle/product/11.2.0/dbhome_1/network/admin/listener.ora
LISTENER =
(DESCRIPTION_LIST =
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(DESCRIPTION_LIST =
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(SID_LIST =
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      (PROGRAM_NAME=/u01/gateway/bin/dg4msql)
/u01/app/oracle/product/11.2.0/dbhome_1/network/admin/tnsnames.ora
LISTENER_ORCL =
(ADDRESS = (PROTOCOL = TCP)(HOST = db.abc.com.tw)(PORT = 1522))
ORCL =
(DESCRIPTION =
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dg4msql =
(DESCRIPTION=
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/u01/gateway/dg4msql/admin/initdg4msql.ora
HS_FDS_CONNECT_INFO=[192.168.0.1]:1433//XIETEST
# alternate connect format is hostname/serverinstance/databasename
HS_FDS_TRACE_LEVEL=255
HS_FDS_RECOVERY_ACCOUNT=RECOVER
HS_FDS_RECOVERY_PWD=RECOVER
dblink was created using statement below.
CREATE DATABASE LINK "xyz.abc.COM.TW"
CONNECT TO SA IDENTIFIED BY
USING 'dg4msql';
Couple more things, that I have done to check the work above.
[oracle@db admin]$ ping 192.168.0.1
PING 192.168.0.1 (192.168.0.1) 56(84) bytes of data.
64 bytes from 192.168.0.1: icmp_seq=1 ttl=61 time=7.61 ms
64 bytes from 192.168.0.1: icmp_seq=2 ttl=61 time=7.41 ms
^C
--- 192.168.0.1 ping statistics ---
2 packets transmitted, 2 received, 0% packet loss, time 1818ms
rtt min/avg/max/mdev = 7.417/7.516/7.615/0.099 ms
[oracle@db admin]$ tnsping dg4msql
TNS Ping Utility for Linux: Version 11.2.0.1.0 - Production on 11-SEP-2013 10:53:11
Copyright (c) 1997, 2009, Oracle. All rights reserved.
Used parameter files:
/u01/app/oracle/product/11.2.0/dbhome_1/network/admin/sqlnet.ora
Used TNSNAMES adapter to resolve the alias
Attempting to contact (DESCRIPTION= (ADDRESS=(PROTOCOL=TCP) (HOST=localhost)(PORT = 1521)) (CONNECT_DATA=(SID=dg4msql)) (HS=OK))
OK (0 msec)
[oracle@db admin]$ lsnrctl status mssql
LSNRCTL for Linux: Version 11.2.0.1.0 - Production on 11-SEP-2013 10:54:23
Copyright (c) 1991, 2009, Oracle. All rights reserved.
Connecting to (DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(HOST=localhost)(PORT=1521)))
STATUS of the LISTENER
Alias                     mssql
Version                   TNSLSNR for Linux: Version 11.2.0.1.0 - Production
Start Date                11-SEP-2013 10:09:46
Uptime                    0 days 0 hr. 44 min. 37 sec
Trace Level               off
Security                  ON: Local OS Authentication
SNMP                      OFF
Listener Parameter File   /u01/app/oracle/product/11.2.0/dbhome_1/network/admin/listener.ora
Listener Log File         /u01/app/oracle/diag/tnslsnr/db/mssql/alert/log.xml
Listening Endpoints Summary...
(DESCRIPTION=(ADDRESS=(PROTOCOL=tcp)(HOST=127.0.0.1)(PORT=1521)))
Services Summary...
Service "dg4msql" has 1 instance(s).
Instance "dg4msql", status UNKNOWN, has 1 handler(s) for this service...
The command completed successfully
Obviously, I would like to get this setup to work, but I also have couple other questions regarding this setup.
1. When installing the gateway, it asks to run the root.sh script. the root.sh script as for the following.
Enter the full pathname of the local bin directory: [/usr/local/bin]:
The file "dbhome" already exists in /usr/local/bin. Overwrite it? (y/n)
[n]: n
The file "oraenv" already exists in /usr/local/bin. Overwrite it? (y/n)
[n]: n
The file "coraenv" already exists in /usr/local/bin. Overwrite it? (y/n)
[n]: n
is the above answer correct?
Thanks for reading.

Dear Klaus,
I did start a new SQL*PLUS session
The output of /u01/gateway/bin/dg4msql is
[oracle@db log]$ /u01/gateway/bin/dg4msql
Oracle Corporation --- WEDNESDAY SEP 11 2013 14:45:06.604
Heterogeneous Agent Release 11.2.0.1.0 - 64bit Production Built with
   Oracle Database Gateway for MSSQL
The output of env is
HOSTNAME=db.abc.com.tw
SHELL=/bin/bash
TERM=xterm
HISTSIZE=1000
ORACLE_UNQNAME=orcl
TMPDIR=/tmp
QTDIR=/usr/lib64/qt-3.3
QTINC=/usr/lib64/qt-3.3/include
USER=oracle
LD_LIBRARY_PATH=/u01/app/oracle/product/11.2.0/dbhome_1/lib:/lib:/usr/lib
LS_COLORS=rs=0:di=01;34:ln=01;36:mh=00:pi=40;33:so=01;35:do=01;35:bd=40;33;01:cd=40;33;01:or=40;31;01:mi=01;05;37;41:su=37;41:sg=30;43:ca=30;41:tw=30;42:ow=34;42:st=37;44:ex=01;32:*.tar=01;31:*.tgz=01;31:*.arj=01;31:*.taz=01;31:*.lzh=01;31:*.lzma=01;31:*.tlz=01;31:*.txz=01;31:*.zip=01;31:*.z=01;31:*.Z=01;31:*.dz=01;31:*.gz=01;31:*.lz=01;31:*.xz=01;31:*.bz2=01;31:*.tbz=01;31:*.tbz2=01;31:*.bz=01;31:*.tz=01;31:*.deb=01;31:*.rpm=01;31:*.jar=01;31:*.rar=01;31:*.ace=01;31:*.zoo=01;31:*.cpio=01;31:*.7z=01;31:*.rz=01;31:*.jpg=01;35:*.jpeg=01;35:*.gif=01;35:*.bmp=01;35:*.pbm=01;35:*.pgm=01;35:*.ppm=01;35:*.tga=01;35:*.xbm=01;35:*.xpm=01;35:*.tif=01;35:*.tiff=01;35:*.png=01;35:*.svg=01;35:*.svgz=01;35:*.mng=01;35:*.pcx=01;35:*.mov=01;35:*.mpg=01;35:*.mpeg=01;35:*.m2v=01;35:*.mkv=01;35:*.ogm=01;35:*.mp4=01;35:*.m4v=01;35:*.mp4v=01;35:*.vob=01;35:*.qt=01;35:*.nuv=01;35:*.wmv=01;35:*.asf=01;35:*.rm=01;35:*.rmvb=01;35:*.flc=01;35:*.avi=01;35:*.fli=01;35:*.flv=01;35:*.gl=01;35:*.dl=01;35:*.xcf=01;35:*.xwd=01;35:*.yuv=01;35:*.cgm=01;35:*.emf=01;35:*.axv=01;35:*.anx=01;35:*.ogv=01;35:*.ogx=01;35:*.aac=01;36:*.au=01;36:*.flac=01;36:*.mid=01;36:*.midi=01;36:*.mka=01;36:*.mp3=01;36:*.mpc=01;36:*.ogg=01;36:*.ra=01;36:*.wav=01;36:*.axa=01;36:*.oga=01;36:*.spx=01;36:*.xspf=01;36:
ORACLE_SID=orcl
ORACLE_BASE=/u01/app/oracle
ORACLE_HOSTNAME=db.abc.com.tw
MAIL=/var/spool/mail/oracle
PATH=/u01/app/oracle/product/11.2.0/dbhome_1/bin:/usr/sbin:/usr/lib64/qt-3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/home/oracle/bin
PWD=/home/oracle
LANG=en_US.UTF-8
SSH_ASKPASS=/usr/libexec/openssh/gnome-ssh-askpass
HISTCONTROL=ignoredups
SHLVL=1
HOME=/home/oracle
TMP=/tmp
LOGNAME=oracle
QTLIB=/usr/lib64/qt-3.3/lib
CVS_RSH=ssh
CLASSPATH=/u01/app/oracle/product/11.2.0/dbhome_1/jlib:/u01/app/oracle/product/11.2.0/dbhome_1/rdbms/jlib
LESSOPEN=|/usr/bin/lesspipe.sh %s
ORACLE_HOME=/u01/app/oracle/product/11.2.0/dbhome_1
G_BROKEN_FILENAMES=1
_=/bin/env

"zip" Terminal command no help fixing corrupt zip file; any other workarounds?

I downloaded a ".zip" file containing some files that I need to access.
When I double-click on it, I get the "Unable to unarchive 'xyz.zip' into '[foldername].' ( Error 1 - Operation not permitted )" message, which many people report when they try to open a corrupt zip file.
I also tried opening the file with "StuffIt Expander," "Archive Utility," and "The Unarchiver," as well as some specialty zip-compression programs, but none were successful.
I then installed the very useful "Archive.qlgenerator" plugin (http://homepage.mac.com/xdd/software/archive/) which allowed me to at least see inside the zip file using OSX's "QuickLook" feature. Lo and behold, all the files that were supposed to be in the zip file are indeed in there, as they should be. The problem is not that the zip file is empty, the problem is that it has become corrupted somehow.
So, what I need to do is either "fix" the corrupted zip file, or alternately find some way to extract the needed files using brute force.
Following tips given on various forums, I tried using OSX's "zip" command in terminal (http://homepage.mac.com/kelleherk/iblog/C1901548470/E731143104/index.html and http://hintsforums.macworld.com/showthread.php?t=132146). I was able to use it properly, but unfortunately neither the "-F" nor the "-FF" commands were of any helping in "fixing" the zip file. The "-F" command incorrectly said that the zip file was empty and that there was nothing to fix; the stronger "-FF" command came back with
Could not find:
xzy.z01
Hit c      (change path to where this split file is)
    s      (skip this split)
    q      (abort archive - quit)
    e      (end this archive - no more splits)
    z      (look for .zip split - the last split)
or ENTER (try reading this split again):
...but none of the options produced any result. Pressing "z" gave me
Could not find or open
xyz.zip
...which means that even "-FF" could not get past whatever problem had corrupted the file.
So: is there any built-in way for Mac OSX to fix or extract the contents of a zip file corrupted like this?
Alternately, is there any third-party shareware or freeware that will do the trick?
(I don't want to have to spend big $$$ on a commercial program since all I need to do is open a single zip file. And there is no way to contact the zip file's original creator, so I can't download an uncorrupted version.)
Any help would be greatly appreciated.

Mark:
When I try your first suggestion in Terminal ("unzip -t /path/to/file"), I get this message:
Archive: /xyz.zip
End-of-central-directory signature not found. Either this file is not
a zipfile, or it constitutes one disk of a multi-part archive. In the
latter case the central directory and zipfile comment will be found on
the last disk(s) of this archive.
unzip: cannot find zipfile directory in one of /xyz.zip or
        /xyz.zip.zip, and cannot find /xyz.zip.ZIP, period.
When I try your second suggestion ("unzip -l /path/to/file"), I get the exact same error message. (And yes, I am fixing "/path/to/file" to be the correct path to the actual file).
And no, it is not really part of a multi-part archive. (Or at least it wasn't supposed to be; only one zip file is available, and there was only supposed to one.) Perhaps the zip was mis-encoded in the first place, so that the person who created it accidentally did something wrong which the unzip applications are interpreting as this file being part of a multi-part archive; but even so, all I have is this one file, so I need to fix it as is, or extract its contents as is, since I have no way to contact the original creator to do it right this time.

Help Please: Split Function or any other SQL server possible way?

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