Hide a row or column for characteristic value # in Query Designer
Hi gurus,
I would if we could hide a result row / column if one of the characteristic value is #. The requirement is actually to remove the meaningless row / column from the whole result set. For example, I have a char Material Group in the column. Since not every Material is assigned to a Material Group, I will get the following layout:
Material_Group A
Material_Group B
Material_Group C
Is it possible to define in query designer so that the column with # will automatically not be displayed?
Thanks,
Meng
Hi Meng,
I guess we have the same users..
But there is one thing that is going to make a non sense on the report: if you do not display the "#" for material group, then the total of your query by material group will not be the summation of what is displayed on the screen...and if the user explort the information in Excel (pretty sure they will do so), you will have some calls that your query does not balance....
Based on that assumption, tell the users to assign a material group to the materials, so that this unassigned column disappears. You could even give them a control report listing all the parts that do not have a material group
If this is a standard business rule not to have a material group for all parts, then, what you could do is to change the text for empty rows for Material group, then the "#" will disappear and wil be under the text description you defined.
But keep in mind that your data is made of materials which do not have a material group in their definition, noraml or not ?
PY
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Dear Sir/Madam,
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Attachments:
Backswing compensation.csv 10 KB
Backswing comnpensation2.vi 109 KBYour VI makes absolutely no sense to me, but maybe I don't understand what you are trying to do.
You seem to have dynamic data with 6 signals and 48 points/channel. Now you reshape this into an array of dynamic data with 4x13 elements from which you slice out one row or column, resp. "delete from array" is NOT the correct tool to do this, use "Index array" with one index unwired to get a row or column as 1D array.
So you end up with two 1D arrays of dynamic data that you search for DBL. It is difficult to understand how you want to search for an array element that corresponds to a scalar DBL value of 0.1. Your array elements are NOT DBLs but dynamic data, each containing many signals!
There are two elements on all your data that are "3", the rest are zero. You will never find anything that is 0.1.
Maybe you can convert your original dynamic data to a 2D array with "rows are signals" using "convert from dynamic data", then operate on the 2D array.
Coato wrote:
So ultimately, when i enter a row value of 0.5 and a column value of 0.3, my output will be 1.688.
Sorry, Please explain.
Please make a VI containing a simple 2D aray as diagram constant that contains e.g. 5x5 typical values. Let us know what kind of result you expect from your algorithm..
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Hi,
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Whole row coloured corresponding to characteristic value
hello friends,
We have a requirement where our client want to see all the data to be displayed RED corresponding to a particular characteristic value
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Pls suggest.
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If u r working with a worbook then u can write a macro.
Ex:
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for j = 1 to worksheet(" A").usedrange.rows.count
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import mx.collections.ArrayCollection;
[Bindable]
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Rows to column for huge number of records
my database version is 10gr2
i want to transfer the rows to column .....i have seen the examples for small no of records but how can it be done if there are more the 1000 records in a table ...???
here is the sample data that i would like to change it to column
SQL> /
NE RAISED CLEARED RTTS_NO RING
10100000-1LU 22-FEB-2011 22:01:04/28-FEB-20 22-FEB-2011 22:12:27/28-FEB-20 SR-10/ ER-16/ CR-25/ CR-29/ CR-26/ RIDM-1/ NER5/ CR-31/ RiC600-1
11 01:25:22/ 11 02:40:06/
10100000-2LU 01-FEB-2011 12:15:58/06-FEB-20 05-FEB-2011 10:05:48/06-FEB-20 RIMESH/ RiC342-1/ 101/10R#10/ RiC558-1/ RiC608-1
11 07:00:53/18-FEB-2011 22:04: 11 10:49:18/18-FEB-2011 22:15:
56/19-FEB-2011 10:36:12/19-FEB 17/19-FEB-2011 10:41:35/19-FEB
-2011 11:03:13/19-FEB-2011 11: -2011 11:08:18/19-FEB-2011 11:
16:14/28-FEB-2011 01:25:22/ 21:35/28-FEB-2011 02:40:13/
10100000-3LU 19-FEB-2011 20:18:31/22-FEB-20 19-FEB-2011 20:19:32/22-FEB-20 INR-1/ ISR-1
11 21:37:32/22-FEB-2011 22:01: 11 21:48:06/22-FEB-2011 22:12:
35/22-FEB-2011 22:20:03/28-FEB 05/22-FEB-2011 22:25:14/28-FEB
-2011 01:25:23/ -2011 02:40:20/
10100000/10MU 06-FEB-2011 07:00:23/19-FEB-20 06-FEB-2011 10:47:13/19-FEB-20 101/IR#10
11 11:01:50/19-FEB-2011 11:17: 11 11:07:33/19-FEB-2011 11:21:
58/28-FEB-2011 02:39:11/01-FEB 30/28-FEB-2011 04:10:56/05-FEB
-2011 12:16:21/18-FEB-2011 22: -2011 10:06:10/18-FEB-2011 22:
03:27/ 13:50/
10100000/11MU 01-FEB-2011 08:48:45/22-FEB-20 02-FEB-2011 13:15:17/22-FEB-20 1456129/ 101IR11 RIMESH
11 21:59:28/22-FEB-2011 22:21: 11 22:08:49/22-FEB-2011 22:24:
52/01-FEB-2011 08:35:46/ 27/01-FEB-2011 08:38:42/
10100000/12MU 22-FEB-2011 21:35:34/22-FEB-20 22-FEB-2011 21:45:00/22-FEB-20 101IR12 KuSMW4-1
11 22:00:04/22-FEB-2011 22:21: 11 22:08:21/22-FEB-2011 22:22:
23/28-FEB-2011 02:39:53/ 26/28-FEB-2011 02:41:07/
10100000/13MU 22-FEB-2011 21:35:54/22-FEB-20 22-FEB-2011 21:42:58/22-FEB-20 LD MESH
11 22:21:55/22-FEB-2011 22:00: 11 22:24:52/22-FEB-2011 22:10:could you do something like this?
with t as (select '10100000-1LU' NE, '22-FEB-2011 22:01:04/28-FEB-2011 01:25:22/' raised , '22-FEB-2011 22:12:27/28-FEB-2011 02:40:06/' cleared from dual union
select '10100000-2LU', '01-FEB-2011 12:15:58/06-FEB-2011 07:00:53/18-FEB-2011 22:04:56/19-FEB-2011 10:36:12/19-FEB-2011 11:03:13/19-FEB-2011 11:16:14/28-FEB-2011 01:25:22/',
'05-FEB-2011 10:05:48/06-FEB-2011 10:49:18/18-FEB-2011 22:15:17/19-FEB-2011 10:41:35/19-FEB-2011 11:08:18/19-FEB-2011 11:21:35/28-FEB-2011 02:40:13/' from dual
select * from(
select NE, regexp_substr( raised,'[^/]+',1,1) raised, regexp_substr( cleared,'[^/]+',1,1) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,2) , regexp_substr( cleared,'[^/]+',1,2) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,3) , regexp_substr( cleared,'[^/]+',1,3) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,4) , regexp_substr( cleared,'[^/]+',1,4) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,5) , regexp_substr( cleared,'[^/]+',1,5) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,6) , regexp_substr( cleared,'[^/]+',1,6) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,7) , regexp_substr( cleared,'[^/]+',1,7) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,8) , regexp_substr( cleared,'[^/]+',1,8) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,9) , regexp_substr( cleared,'[^/]+',1,9) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,10) , regexp_substr( cleared,'[^/]+',1,10) cleared from t
union
select NE, regexp_substr( raised,'[^/]+',1,11) , regexp_substr( cleared,'[^/]+',1,11) cleared from t
where nvl(raised,cleared) is not null
order by ne
NE RAISED CLEARED
10100000-1LU 28-FEB-2011 01:25:22 28-FEB-2011 02:40:06
10100000-1LU 22-FEB-2011 22:01:04 22-FEB-2011 22:12:27
10100000-2LU 28-FEB-2011 01:25:22 28-FEB-2011 02:40:13
10100000-2LU 19-FEB-2011 10:36:12 19-FEB-2011 10:41:35
10100000-2LU 19-FEB-2011 11:03:13 19-FEB-2011 11:08:18
10100000-2LU 19-FEB-2011 11:16:14 19-FEB-2011 11:21:35
10100000-2LU 06-FEB-2011 07:00:53 06-FEB-2011 10:49:18
10100000-2LU 01-FEB-2011 12:15:58 05-FEB-2011 10:05:48
10100000-2LU 18-FEB-2011 22:04:56 18-FEB-2011 22:15:17you should be able to do it without all those unions using a connect by but I can't quite get it to work
the following doesn't work but maybe someone can answer.
select NE, regexp_substr( raised,'[^/]+',1,level) raised, regexp_substr( cleared,'[^/]+',1,level) cleared from t
connect by prior NE = NE and regexp_substr( raised,'[^/]+',1,level) = prior regexp_substr( raised,'[^/]+',1,level + 1)Edited by: pollywog on Mar 29, 2011 9:38 AM
here it is with the model clause which gets rid of all the unions.
WITH t
AS (SELECT '10100000-1LU' NE,
'22-FEB-2011 22:01:04/28-FEB-2011 01:25:22/' raised,
'22-FEB-2011 22:12:27/28-FEB-2011 02:40:06/' cleared
FROM DUAL
UNION
SELECT '10100000-2LU',
'01-FEB-2011 12:15:58/06-FEB-2011 07:00:53/18-FEB-2011 22:04:56/19-FEB-2011 10:36:12/19-FEB-2011 11:03:13/19-FEB-2011 11:16:14/28-FEB-2011 01:25:22/',
'05-FEB-2011 10:05:48/06-FEB-2011 10:49:18/18-FEB-2011 22:15:17/19-FEB-2011 10:41:35/19-FEB-2011 11:08:18/19-FEB-2011 11:21:35/28-FEB-2011 02:40:13/'
FROM DUAL)
SELECT *
FROM (SELECT NE, raised, cleared
FROM t
MODEL RETURN UPDATED ROWS
PARTITION BY (NE)
DIMENSION BY (0 d)
MEASURES (raised, cleared)
RULES
ITERATE (1000) UNTIL raised[ITERATION_NUMBER] IS NULL
(raised [ITERATION_NUMBER + 1] =
REGEXP_SUBSTR (raised[0],
'[^/]+',
1,
ITERATION_NUMBER + 1),
cleared [ITERATION_NUMBER + 1] =
REGEXP_SUBSTR (cleared[0],
'[^/]+',
1,
ITERATION_NUMBER + 1)))
WHERE raised IS NOT NULL
ORDER BY NEEdited by: pollywog on Mar 29, 2011 10:34 AM -
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I sell my books and design tees on my site. I'm trying to set up a new page for a new site.
For some reason I can't get my products in a row and column fashion.
I have a attachment file so you can see what I actually mean. thanks to all that will give advice.Use a table for your product catalog.
Nancy O.
Alt-Web Design & Publishing
Web | Graphics | Print | Media Specialists
www.alt-web.com/
www.twitter.com/altweb
www.alt-web.blogspot.com
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