How access control exception is removed

Question

Pls suggest me how to overcome with this problem .
I have only this simple code=============>>
public MyRemoteServer() {
try {
MyRemote c = new MyRemoteImpl();
if (System.getSecurityManager() == null) {
System.setSecurityManager(new RMISecurityManager());
Registry r=LocateRegistry.createRegistry(1099);
Naming.rebind("rmi://192.168.0.60:1099/CalculatorService", c);
System.out.println("Server is now running ,waiting for client's stimlus");
} catch (Exception e) {
System.out.println("Trouble: " + e);
e.printStackTrace();
and i got the following exception :============>>
java.security.AccessControlException: access denied (java.net.SocketPermission 192.168.0.60:1099 connect,resolve)
     at java.security.AccessControlContext.checkPermission(AccessControlContext.java:269)
     at java.security.AccessController.checkPermission(AccessController.java:401)
     at java.lang.SecurityManager.checkPermission(SecurityManager.java:524)Trouble: java.security.AccessControlException: access denied (java.net.SocketPermission 192.168.0.60:1099 connect,resolve)
     at java.lang.SecurityManager.checkConnect(SecurityManager.java:1026)
     at java.net.Socket.connect(Socket.java:446)
     at java.net.Socket.connect(Socket.java:402)
     at java.net.Socket.<init>(Socket.java:309)
     at java.net.Socket.<init>(Socket.java:124)
     at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:22)
     at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:128)
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:562)
     at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:185)
     at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:171)
     at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:313)
     at sun.rmi.registry.RegistryImpl_Stub.rebind(Unknown Source)
     at java.rmi.Naming.rebind(Naming.java:160)
     at com.myrmi.server.MyRemoteServer.<init>(MyRemoteServer.java:22)
     at com.myrmi.server.MyRemoteServer.main(MyRemoteServer.java:32)
what things sud i do.
how to set code base ???
pls help

Answer 1

Thanx Fedrik
I got it. Thanx a lot for ur co -operation.
The summary is that we dont need to specify any security manager
or code base at server side.
at client side we'll provide the security manager and codepase property
like
System.setProperty("java.security.policy","C:/myrmi.policy");
System.setProperty("java.rmi.server.codebase", "http://192.168.0.11:8080/rmiclientclasses/");
but the restriction( or drawback) is that we can only specify the url of http server.
the policy file is like this --->
grant
permission java.net.SocketPermission "*:1024-65535","connect,accept,listen,resolve";
permission java.security.AllPermission;
once again thanx Fedrik
Regards
Manish Agarwal
[email protected]
[email protected]