Access Security Exception

Question

Hello,
I have written an applet and when I upload the applet to the website and open the browser I get an access control exception error.
Platform: MacOS X
I.E: 5.1.2
Error:
java.security.AccessControlException: access deinied (java.lang.RuntimePermission writeFileDescriptor)
What can I do about this problem?
Thanks!

Answer 1

You are trying to access a file on the local PC, you can't do this with an applet. If you are actually trying to refer to a file on the Server, make sure you are not using File objects. Refer to them as URL objects. Obvisouly I am guessing without knowing what your code looks like or what your are trying to get the applet to do.
Being it says FileDescriptor in your error try using the Url object as I did below:
     private URL theUrl;
     private Color backColor;
     private String sztemp;
     public void init()
          //????Maybe Make a thread and move all to start???
          //Set All Values to defaults
          filename = "counter.dat";
          fullURL = getCodeBase() + filename;
          displaytype = "text";
          value = 0;
          digits = 5;
          backColor = new Color(255,255,255);
          //Get AppletParameters that were set
          // Create the URL for Counter file
          try{
               theUrl = new URL(fullURL);
          } catch( MalformedURLException e)
               System.out.println("Bad URL: " + theUrl );
then
          try {
               connect = this.theUrl.openConnection();
               connect.connect();
          } catch ( IOException e ) {
               System.out.println("IO Error: " + e.getMessage() );
and to use the Input Stream
               DataInputStream stream = new DataInputStream( new BufferedInputStream(connection.getInputStream() ) );
As far as the output stream, I need answer to my posting.
Hope that helped.