How do I transmit an RTP stream using only a datasource?

I've been following this tutorial: http://members.jcom.home.ne.jp/3117216601/jmf2guide/RTPPresenting.html
And I have clients that can send me RTP audio streams, which are received in the update method.
Now, update generates a NewReceiveStreamEvent. Which has a datasource that I can play.
But what I want to do. Is have send the DataSource back to that client. (The ip address is unknown... but that shouldn't matter, as RTP is two-way).
I want to send the DataSource back to the client, because later, we will be routing different clients, and who they can talk to and such. But I want to start with the basics.

captfoss wrote:
DerNalia wrote:
But what I want to do. Is have send the DataSource back to that client. (The ip address is unknown... but that shouldn't matter, as RTP is two-way).RTP isn't two-way, RTP is one way... RTCP is two-way. The data transport is duplex, the QOS/control messages are duplex...
So you do need to know the IP address of the client in order to send anything to him...
I want to send the DataSource back to the client, because later, we will be routing different clients, and who they can talk to and such. But I want to start with the basics.You should just be able to turn around and give the DataSource that's receiving the RTP stream to an RTPManager and broadcast it back out... assuming you're not transcoding it out of its RTP format or anything.I don't have the IP address. So is this even possible without switching to RTCP? if so if you an example, that would be awesome. Also an example of two way communication with RTCP would be awesome too.
Does RTCP used the same sort of structure that RTP does? like is there a DataSource that could be merged with other datasources, and sent back to where one of the datasources came frome?

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