How to calculate the Percentage differencebased on two values
Not sure how to do this.
Just want to calculate the % difference of two values (seem to have a problem when one value is zero)
Here is the current output
49 Apr 2
64 Aug 1
55 Feb 0
Here is the output I would like to see
49 Apr 2 4.08%
64 Aug 1 1.56%
55 Feb 0 0.00%
Here is the current SQL
Select TO_CHAR (RCA_CLOSE_DATE, 'Month') "Month",
SUM (CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) "BI&D - CBAT No of Adj",
Count(1) as "Count of Adjustments"
from TW_BILL_ADJ_DATA
where (RCA_CLOSE_DATE between nvl (:P8_DATE_FROM,FORM_RECEIVED)
and nvl (:P8_DATE_TO, FORM_RECEIVED))
group by TO_CHAR (RCA_CLOSE_DATE, 'Month')
You can try something like this one:
Select TO_CHAR (RCA_CLOSE_DATE, 'Month') "Month",
SUM (CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) "BI&D - CBAT No of Adj",
Count(1) as "Count of Adjustments",
round(count(1)/SUM(CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) * 100,2) || '%' percent
from TW_BILL_ADJ_DATA
where (RCA_CLOSE_DATE between nvl (:P8_DATE_FROM,FORM_RECEIVED)
and nvl (:P8_DATE_TO, FORM_RECEIVED))
group by TO_CHAR (RCA_CLOSE_DATE, 'Month')
CODE NOT TESTED !!!
Best Regards
Krystian Zieja / mob
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SQL> create table test222 as select * from all_objects;
Table created.
SQL> delete from test22 where rownum<=100;
delete from test22 where rownum<=100
ERROR at line 1:
ORA-00942: table or view does not exist
SQL> delete from test222 where rownum<=100;
100 rows deleted.
SQL> analyze table test222 compute statistics;
Table analyzed.
SQL> create or replace procedure show_space
2 ( p_segname in varchar2,
3 p_owner in varchar2 default user,
4 p_type in varchar2 default 'TABLE',
5 p_partition in varchar2 default NULL )
6 -- this procedure uses authid current user so it can query DBA_*
7 -- views using privileges from a ROLE and so it can be installed
8 -- once per database, instead of once per user that wanted to use it
9 authid current_user
10 as
11 l_free_blks number;
12 l_total_blocks number;
13 l_total_bytes number;
14 l_unused_blocks number;
15 l_unused_bytes number;
16 l_LastUsedExtFileId number;
17 l_LastUsedExtBlockId number;
18 l_LAST_USED_BLOCK number;
19 l_segment_space_mgmt varchar2(255);
20 l_unformatted_blocks number;
21 l_unformatted_bytes number;
22 l_fs1_blocks number; l_fs1_bytes number;
23 l_fs2_blocks number; l_fs2_bytes number;
24 l_fs3_blocks number; l_fs3_bytes number;
25 l_fs4_blocks number; l_fs4_bytes number;
26 l_full_blocks number; l_full_bytes number;
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28 -- inline procedure to print out numbers nicely formatted
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32 begin
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46 from dba_segments seg, dba_tablespaces ts
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48 and (:p_partition is null or
49 seg.partition_name = :p_partition)
50 and seg.owner = :p_owner
51 and seg.tablespace_name = ts.tablespace_name'
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99 unused_blocks => l_unused_blocks,
100 unused_bytes => l_unused_bytes,
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102 LAST_USED_EXTENT_BLOCK_ID => l_LastUsedExtBlockId,
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104
105 p( 'Total Blocks', l_total_blocks );
106 p( 'Total Bytes', l_total_bytes );
107 p( 'Total MBytes', trunc(l_total_bytes/1024/1024) );
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110 p( 'Last Used Ext FileId', l_LastUsedExtFileId );
111 p( 'Last Used Ext BlockId', l_LastUsedExtBlockId );
112 p( 'Last Used Block', l_LAST_USED_BLOCK );
113 end;
114
115 /
Procedure created.
SQL> desc show_space
PROCEDURE show_space
Argument Name Type In/Out Default?
P_SEGNAME VARCHAR2 IN
P_OWNER VARCHAR2 IN DEFAULT
P_TYPE VARCHAR2 IN DEFAULT
P_PARTITION VARCHAR2 IN DEFAULT
SQL> set serveroutput on
SQL> exec show_space('TEST222','SCOTT');
BEGIN show_space('TEST222','SCOTT'); END;
ERROR at line 1:
ORA-00942: table or view does not exist
ORA-06512: at "SCOTT.SHOW_SPACE", line 44
ORA-06512: at line 1
SQL> conn / as sysdba
Connected.
SQL> grant sysdba to scott;
Grant succeeded.
SQL> conn scott/tiger as sysdba
Connected.
SQL> exec show_space('TEST222','SCOTT');
BEGIN show_space('TEST222','SCOTT'); END;
ERROR at line 1:
ORA-06550: line 1, column 7:
PLS-00201: identifier 'SHOW_SPACE' must be declared
ORA-06550: line 1, column 7:
PL/SQL: Statement ignored
SQL> exec scott.show_space('TEST222','SCOTT');
PL/SQL procedure successfully completed.
SQL> set serveroutput on
SQL> exec scott.show_space('TEST222','SCOTT');
Unformatted Blocks ..................... 0
FS1 Blocks (0-25) ..................... 0
FS2 Blocks (25-50) ..................... 1
FS3 Blocks (50-75) ..................... 0
FS4 Blocks (75-100)..................... 1
Full Blocks ..................... 807
Total Blocks............................ 896
Total Bytes............................. 7,340,032
Total MBytes............................ 7
Unused Blocks........................... 65
Unused Bytes............................ 532,480
Last Used Ext FileId.................... 4
Last Used Ext BlockId................... 1,289
Last Used Block......................... 63
PL/SQL procedure successfully completed.
SQL>http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:5350053031470
I use this to find the space allocations.
Just read your post again,this is not going to show you the percentage of the free/used space. This is going to be the number of blocks which are free/used. For the growth trend, you can look at (in 10g) Oracle EM. It has added now,Segment Growth Trend report which can show you for each object,comparing to the allocated space to the object,how much space is being used by it.
HTH
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spo2 akusisi data with filter lpf hpf smoot nilai max min ir merah.vi 249 KBHi rai,
I would appreciate it as kind of respect for forum participants if you would clean up your VI before uploading it (or images of its block diagram)…
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My program image can be seen below predicament ?
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You should post this into the LabVIEW forum rather than Real-Time since this isn't a Real-Time application. Your post will see more replies in the LabVIEW forum.
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Reference:
Custom Code and Assembly References in Expressions in Report Designer (SSRS)
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SwarupFor a complete discussion of storage requirements for different datatypes see the Oracle 8i Concepts manual.
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The following is from the Concepts manual Chapter 12 (Copyright by Oracle)
Built-In Datatypes 12-9
Internal Numeric Format
Oracle stores numeric data in variable-length format. Each value is stored in
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negative.
Zero and positive and negative infinity (only generated on import from Version 5
Oracle databases) are stored using unique representations. Zero and negative
infinity each require one byte; positive infinity requires two bytes.
null
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