How to calculate the Percentage differencebased on two values

Not sure how to do this.
Just want to calculate the % difference of two values (seem to have a problem when one value is zero)
Here is the current output
49 Apr 2
64 Aug 1
55 Feb 0
Here is the output I would like to see
49 Apr 2 4.08%
64 Aug 1 1.56%
55 Feb 0 0.00%
Here is the current SQL
Select TO_CHAR (RCA_CLOSE_DATE, 'Month') "Month",
SUM (CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) "BI&D - CBAT No of Adj",
Count(1) as "Count of Adjustments"
from TW_BILL_ADJ_DATA
where (RCA_CLOSE_DATE between nvl (:P8_DATE_FROM,FORM_RECEIVED)
and nvl (:P8_DATE_TO, FORM_RECEIVED))
group by TO_CHAR (RCA_CLOSE_DATE, 'Month')

You can try something like this one:
Select TO_CHAR (RCA_CLOSE_DATE, 'Month') "Month",
SUM (CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) "BI&D - CBAT No of Adj",
Count(1) as "Count of Adjustments",
round(count(1)/SUM(CASE WHEN RCA_CODE = 'BI&D' THEN 1 ELSE 0 END) * 100,2) || '%' percent
from TW_BILL_ADJ_DATA
where (RCA_CLOSE_DATE between nvl (:P8_DATE_FROM,FORM_RECEIVED)
and nvl (:P8_DATE_TO, FORM_RECEIVED))
group by TO_CHAR (RCA_CLOSE_DATE, 'Month')
CODE NOT TESTED !!!
Best Regards
Krystian Zieja / mob

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    numbers include the sign in their length.
    Taking this into account, the column size in bytes for a particular numeric data
    value NUMBER ( p), where p is the precision of a given value, can be calculated
    using the following formula:
    ROUND((length( p)+ s)/2))+1
    where s equals zero if the number is positive and s equals 1 if the number is
    negative.
    Zero and positive and negative infinity (only generated on import from Version 5
    Oracle databases) are stored using unique representations. Zero and negative
    infinity each require one byte; positive infinity requires two bytes.
    null

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