How to do random selection?

Hi I have a flash player which reads from an xml playlist. It works fine but it plays the songs according to the order in the playlist. I want it to continously shuffle to select randomly. This is the script: I added the ones with stars to create the sfuffle but it does not work. Any ideas what it should be?
<script type="text/javascript">
   var so = new SWFObject("playerMultiple.swf", "mymovie", "192", "95", "7", "#FFFFFF");
   so.addVariable("overColor","#660000")
   so.addVariable("autoPlay","no")
   so.addVariable("playlistPath","playlist.xml")
   *so.addVariable("shuffle", "True")*
*so.addVariable('repeat','list')*
   so.write("flashPlayer");
</script>

Georgie wrote:
Hi I have a flash player which reads from an xml playlist. It works fine but it plays the songs according to the order in the playlist. I want it to continously shuffle to select randomly. This is the script: I added the ones with stars to create the sfuffle but it does not work. Any ideas what it should be?
<script type="text/javascript">
var so = new SWFObject("playerMultiple.swf", "mymovie", "192", "95", "7", "#FFFFFF");
so.addVariable("overColor","#660000")
so.addVariable("autoPlay","no")
so.addVariable("playlistPath","playlist.xml")
*so.addVariable("shuffle", "True")*
*so.addVariable('repeat','list')*
so.write("flashPlayer");
</script>
1) This is a java forum, not a javascript forum.
2) We don't know anything at all about playerMultiple.swf, its API, its variables or parameters, or anything else about it. You should consult the documentation for what you're using.

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I synced two of my email accounts via gmail's POP3 thing. But now my iphone's gmail inbox shows a random selection of emails (not most recent ones that are in my inbox). How can I make my iphone inbox match what I see when I log on using a PC?

I synced two of my email accounts via gmail's POP3 capabilities. But now my iphone's gmail inbox only shows a random selection of emails (i.e. right now it is May 31, 2013 but the emails in my inbox are a couple from Nov 12, a few from Oct 12, and then some way older than that and so on.When I log into my gmail from a computer, I see all my emails in the logical, standard order. How can I make my iphone inbox match what I see when I log on using a PC?

If you're trying to decide between using POP and IMAP, we encourage you to use IMAP.
Unlike POP, IMAP offers two-way communication between your web Gmail and your email client. This means when you log in to Gmail using a web browser, actions you perform on email clients and mobile devices (ex: putting mail in a 'work' folder) will instantly and automatically appear in Gmail (ex: it will already have a 'work' label on that email the next time you sign in).
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That is from the page that you linked- does highlighted part of message ring a bell?

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multiline<TD width="50%"><NOBR>
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Thanks a lot for VU#. Also i got an idea about how to randomly select a link:
Private Sub RSWVBAPage_afterPlay()
Dim objReg As New RegExp
Dim objMatchCol As MatchCollection
Dim objMatch As Match
Dim objSubMatch As SubMatches
Dim doc As String
Dim str As String
Dim rNumb As Integer
RSWApp.GetHtml doc
With objReg
.Global = True
.IgnoreCase = True
'the kind of urls have the following special pattern
.Pattern = "pageid=34,([\d]{5})"
End With
Set objMatchCol = objReg.execute(doc)
Randomize
rNumb = objMatchCol.Count * Rnd
If objMatchCol.Count >= 1 Then
If rNumb = objMatchCol.Count Then
rNumb = objMatchCol.Count - 1
End If
End If
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Set objSubMatch = objMatch.SubMatches
str = objSubMatch.Item(0)
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RSWApp.WriteToLog str
Set objMatchCol = Nothing
Set objMatch = Nothing
End Sub

Ipod nano - how do you get rid of auto random select for playlist songs

theres some strange icon that appears and for some reason selects random songs not the order i want the songs to play. help??
no idea how to fix this. it works fine on itunes, on my ipod nano it just seems to do random select on all playlists.
ipod nano Windows XP

iPod Settings > Shuffle to Off.

How to efficiently get hold of N randomly selected keys out of X?

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Edited by: MagnusE on Aug 7, 2009 10:21 AM

Hi Magnus,
you can go the other way round:
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You can use this method for it:
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Best regards,
Robert
Edited by: robvarga on Aug 7, 2009 11:55 AM
Added some more ideas and method implementation.

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Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
create table s_test(sub_building_id number not null,building_id number ,invalid varchar2(1),sequence_no number);
insert into b_test values (1000,'N');
insert into b_test values(2000,'N');
insert into b_test values(3000,'N');
commit;
insert into s_test values(1,1000,'N',90);
insert into s_test values(2,1000,'N',91);
insert into s_test values(3,1000,'N',92);
insert into s_test values(4,1000,'Y',93);
insert into s_test values(5,NULL,'N',NULL);
insert into s_test values(1,2000,'N',94);
insert into s_test values(2,2000,'N',95);
insert into s_test values(3,2000,'N',96);
insert into s_test values(4,2000,'N',97);
insert into s_test values(5,2000,'N',98);
insert into s_test values(6,NULL,'N',NULL);
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);
commit;The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID      SUB_BUILDING_ID     SEQUENCE_NO
1000              N     1                     90
1000             N     2                     91
1000             N     3                     92
2000             N     1                     94
2000             N     2                     95
2000             N     3                     96
2000             N     4                     97
2000             N     5                     98
3000             N     10                      99
3000             N     11                     100Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query)
The results would be like
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000               N     1                      90
2000               N     1                      94
3000               N     11                     1002)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
The results will be:
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000             N     1                       90
1000             N     2                       90
1000             N     3                       90
2000             N     1                       94
2000              N     2                       94
2000             N     3                       94
2000             N     4                       94
2000             N     5                       94
3000             N     10                       99
3000             N     11                       99Many thanks!
Edited by: Krithi on 08-Nov-2012 08:48
Edited by: Krithi on 08-Nov-2012 08:55

Krithi wrote:
Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
Thanks for posting the CREATE TABLE and INSERT statements, and your existing query; that's very helpful.
The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID      SUB_BUILDING_ID     SEQUENCE_NO
1000              N     1                     90
1000             N     2                     91
1000             N     3                     92
2000             N     1                     94
2000             N     2                     95
2000             N     3                     96
2000             N     4                     97
2000             N     5                     98
3000             N     10                      99
3000             N     11                     100
When I run your query, I get NULL for sequence_no on the last 2 rows, where building_id=3000. The numbers 99 and 100 don't seem to occur in either table. Did you post the worng sample data and/or results?
>
Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query) Here's one way:
WITH       got_r_num AS
     SELECT sub_building_id
     ,     building_id
     ,     sequence_no
     ,     ROW_NUMBER () OVER ( PARTITION BY building_id
                               ORDER BY         sequence_no
                       )         AS r_num
     FROM    s_test
     WHERE     invalid     = 'N'
SELECT    b.building_id
,       b.invalid
,       r.sub_building_id
,       r.sequence_no
FROM             b_test     b
LEFT OUTER JOIN      got_r_num r ON r.building_id = b.building_id
WHERE     NVL ( r.r_num
           , 1
           )          = 1
ORDER BY b.building_id
;This is called a Top-N Query , because we're picking N items (N = 1 in this case) from the top of an ordered list. What makes one item the "top", and another one "lower"? That's determined by the analytic ORDER BY clause, in this case
ORDER BY      sequence_noThat means the row with the lowest sequence_no (for each building_id) will get r_num=1. If you want a random row from that building_id to be chosen as #1, then you can change the analytic ORDER BY clause to
ORDER BY      dbms_random.valueYou can ORDER BY anything you like, even a constant, but you must have an analytic ORDER BY clause. ROW_NUMBER requires an analytic ORDER BY clause.
The results would be like
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000               N     1                      90
2000               N     1                      94
3000               N     11                     100
Again, I don't see where the 100 comes from. The results I get are:
BUILDING_ID I SUB_BUILDING_ID SEQUENCE_NO
       1000 N               1          90
       2000 N               1          94
       3000 N              11
2)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
SELECT    b.building_id
,       b.invalid
,       s.sub_building_id
,       MIN (s.sequence_no) OVER ( PARTITION BY s.building_id)
                        AS seq_no
FROM             b_test b
LEFT OUTER JOIN      s_test s ON s.building_id = b.building_id
                            AND s.invalid      = 'N'
The results will be:
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000             N     1                       90
1000             N     2                       90
1000             N     3                       90
2000             N     1                       94
2000              N     2                       94
2000             N     3                       94
2000             N     4                       94
2000             N     5                       94
3000             N     10                       99
3000             N     11                       99
Again, I don't see where you get sequence_no = 99. The results I get are:
BUILDING_ID I SUB_BUILDING_ID     SEQ_NO
       1000 N               1         90
       1000 N               2         90
       1000 N               3         90
       2000 N               1         94
       2000 N               2         94
       2000 N               5         94
       2000 N               3         94
       2000 N               4         94
       3000 N              10
       3000 N              11Edited by: Frank Kulash on Nov 8, 2012 12:12 PM
Added explanation and results
Edited by: Frank Kulash on Nov 8, 2012 12:28 PM
It looks like you cahnged your sample data from
insert into s_test values(10,3000,'N',NULL);
insert into s_test values(11,3000,'N',NULL);to
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);The queries I posted are niow getting 99, like you requested.

Can a script randomly select an action within a specific set for use on multiple images?

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jpegOptions.quality = inQuality;
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OT

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I have a query or SQL I am writing where I need to select records in this fashion.
At most 2 records for each username, and those 2 records should be random.
there are many fields that I am bringing in via my SQL; but the username there are typically around 20 unique usernames.
The data itself without a random statement added to it returns approximately 2000 records.
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Someone mentioned to me that I could use a rank() statement; but I have no clue how to use that.
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my query just needs a slight modification:
SQL> select   deptno, ename
from   (select   deptno, ename, row_number () over (partition by deptno order by dbms_random.value) rn
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where   rn <= 2
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Random selection of materials

Hi Experts,
In a selection Screen i have material in select-options and a Parameter item count, now i have to select N materials randomly from the material range choosen in the selection screen and N is the number in the iten count field.
please tell me how to choose N numbers randomly, we can select upto n numbers from a table but how to select N random materials. the query written for N materials is
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please send me if u have any sample code regarding that. or let me know what to write for random selection
Regards,
Nikhil

DO n TIMES.
CALL FUNCTION 'QF05_RANDOM_INTEGER'
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ENDDO.

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To learn more about LV, I suggest you read the LabVIEW user manual. Also, try searching this site and google for LabVIEW tutorials. Here and here are a couple you can start with. You can also contact your local NI office and join one of their courses.
In addition, I suggest you read the LabVIEW style guide.
Try to take over the world!

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