How to get rank within the row in SQL

Question

I have an a key orderid and 4 other columns with orderdate&time in (16/12/2011 16:15:24 format) within a table.
the orderid has an average of 1million rows every week hence could not do this in excel for a 15 day period .
ORderid.........: mail........................................ : telephone ............................:online ........................................ store.......................... Agency
A3456...........15/12/2011 16:15:24 ............... 16/12/2011 14:12:01.............16/12/2011 16:14:00..........17/12/2011 11:22:55 ............12/12/2011 22:20:30
B678
C555
i want to create a new table which ranks each row according to the max orderdate and time say in another table
i want to capture the rank
KEY.......Mail............Tel............online.........store..........Agency
A3456.....4 ...............3...............2...............1............... 5
Is there any way either within the same table or in other table i wiould be able to get the rank based on the rows in SQL.
thnks
Edited by: UOOLK on 29-Dec-2011 06:46

Answer 1

Something like this I think:
create new_order_table as
  select order_id
        ,rank() over (order by mail desc) mail
        ,rank() over (order by telephone desc) telephone
        ,rank() over (order by online desc) online
        ,rank() over (order by store desc) store
        ,rank() over (order by agency desc) agency
    from old_order_table;Assuming you want the most recent date to be ranked number 1. If you want number 1 to be the oldest then remove all the 'desc's from the order by clauses.