How to group result set to count values in several (2) attributes?

Question

Hi there,
the (simplified) query at the bottom returns the following result set:
OBJ_ID Attr 1 Attr2
22674886 HAK44221 GEB132542
22674886 HAK44221 GEB92751
22674886     HAK44222 GEB92744
22674886     HAK17113 null
However, we need the number of different Attr 1 and Attr2 counted, which should result in the this:
OBJ_ID Attr 1 Attr2
22674886 3 3
We trried using "group by grouping sets", "group by" and also took a glance at "cube" but didn't manage to get the desired result, mainly due to the fact, that Attr2 may contain null values.
We managed to find a solution using a GTT or a view. Can anybody give a hint how to solve that without using temporary tables?
Best regards
Pat
SELECT
o.obj_id,
o2.obj_name as Attr1,
g.ckw_nis_nummer as Attr2
FROM objekte o
JOIN eigenschaftsdaten d0
ON (o.obj_id = d0.obj_id AND d0.eig_id = 2525755)
LEFT JOIN eigenschaftsdaten d8
ON (d0.egd_wert=substr(d8.egd_wert,1,instr(d8.egd_wert, ' ')-1) and d8.eig_id=2525976)
LEFT JOIN objekte o2
ON o2.obj_id=d8.obj_id
LEFT join gebaeude g
ON o2.obj_id=g.parent_house_service

Answer 1

Hi,
That looks like COUNT (DISTINCT ...):
SELECT       o.obj_id
,       COUNT (DISTINCT o.obj_name)          AS attr1
,       COUNT (DISTINCT g.ckw_nis_nummer)     AS attr2
FROM        objekte o
JOIN        eigenschaftsdaten     d0     ON   o.obj_id      = d0.obj_id
                           AND  d0.eig_id       = 2525755
LEFT JOIN eigenschaftsdaten      d8     ON   d0.egd_wert = SUBSTR ( d8.egd_wert
                                                         , 1
                                          , INSTR (d8.egd_wert, ' ') - 1
                         and d8.eig_id=2525976)
LEFT JOIN objekte          o2     ON  o2.obj_id      = d8.obj_id
LEFT JOIN gebaeude           g     ON  o2.obj_id      = g.parent_house_service
Depending on your data and your requirements, you may need to join some of the tables separatemly, do a GROUP BY to get attr2, and then join those results to the other tables.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data. WSimplify the problem as much as possible. For exam[ple, if your real problem involves 5 tables, but the part you don't understand can be shown with only 1 or 2 tables, then post sample data and results for those 1 or 2 tables only.
Point out where the query above is getting the wrong results, and explain, using specific examples, how you get those results from the sample data in those places.
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