How to make current visitors visible to each other

I am running a non-public website on my OSX-server for a group. We would like to see who (of the registered users) is logged in to the website.
Can't find any information about how to do this. Any ideas?

Good Questions.
1) not yet. The bpel suitcase is designed to be able to support multiple BPEL process projects but for now we only support 1 per suitcase. The work around it to have more intelligent ant build script that wrap 2 bpel suitecase ant scripts.
2) in the bpel.xml, you can define a wsdlLocation and a wsdlRuntimeLocation. The first one is needed at design time and the second on is needed at runtime. The first one need to only have the interface definition (no bindings).
Sounds like an interesting BPEL process. Good luck!
Edwin

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How to make the library visible IN AN EXTERNAL disk?

Hello.
Searched this forum (found about 25 identical questions and answers "how to make the library visible").
I turned mine and it is constantly visible now.
Before installing Lion made a bootable image.
When I connect the external HD, I see it in the Finder side bar, click on users>myname and the library folder doesn't show up.
Tried the 3 ways to make it visible but they all bring back and show the Lion's library on my MBP, not the one in the external HD.
Any ideas?
(BTW, I am just an "amateur user", not too heavy, so just, please take in consideration that if you explain to me slowly I will understand quicly)...
Thanks in advance.
Saul

Thank you Baltwo.
Don't I know you from CCC? (If judging from your answer I do, always hit the nail in the head)...
Yes, I guess I used the wrong terminology. Anyway, I did a bootable disk/image/clone, however it's called, with CCC (Carbon Copy Cloner), which BTW I am using for at least 3 years and saved several times my behind.
So, if I understood you right, you mean booting from my external HD and make the library visible (I don't remember if the clone was made after installing Lion or still while in Snow L, but will check).
I'll try and update here if it worked.
Thanks again and have a good evening.
Saul

Can you explain me clearly how to make company code visible in cost center

can you explain me clearly how to make company code visible in cost center master data using tcode kmlv

Hi,
There is no way to activate the company code field. If your Controlling Area and Company Code have one to one Assignment, then Company code is defaulted from the Controlling Area. However, if multiple Company Codes are assigned to one Controlling Area, then Company Code becomes a mandatory field in the Cost Center master data
Also, in case you have multiple company codes assigned to one controlling area, please check the setting of the Controlling Area in Configuration and see if have selected "Cross Company Code Cost Accounting" . Also, check if you have assigned all the company codes to the controlling area
Regards
Mahendra

Classes are not visible to each other in a same package

Hi,
I have a question. How to make all classes in a same package visible to each other? For example, I have two classes below, T1.java and T2.java:
Below is T1.java
package thesis;
public class T1 {
     public T1(){}
     public void func1(){
          System.out.println("This is in T1 class");
Below is T2.java
package thesis;
public class T2 {
     public T2(){}
     public void func2(){
          System.out.println("This is in T2");
     public static void main(String[] args){
          T1 t1 = new T1();
          t1.func1();
          T2 t2 = new T2();
          t2.func2();
I create a directory named thesis and put T1.java and T2.java under this folder. But when I try to compile T2.java, it give me error message, seems that T2.java cannot recognize T1.class.
So, can anyone solve this problem for me. Thanks in advance.
jmling

Make sure your classpath env variable is set correctly!
to compile these classes you should have something like:
C: > javac thesis\T2.java
if your classpath is set up correctly (default is CLASSPATH=.) then the above command should work.
If your still having problems, try:
C: > javac thesis\*.java
or compile T1.java first.
Anthony

3 iphones in household.All use same apple ID.But all contacts get mixed between phones and facetime calls come in from other contacts.Ho can we change this so our phone information isn't visible to each other?

3 iphones in household.All use same apple ID.But all contacts get mixed between phones and facetime calls come in from other contacts.How can we change this so our phone information isn't visible to each other?

Use separate Apple IDs for each family member and use Family Sharing features of those things (if any) that you do want to share. https://www.apple.com/ios/whats-new/family-sharing/

How can we get help/advice amoungst each other? I have questions

How can we get help/advice amoungst each other? I have questions which might not be bug related and thought it would be nice if we could bounce questions off each other.
Example:
Why is my Reflow sample behaving like this?
Should I have some kind of settings set so things don't get all weird?
I didn't set any breakpoints yet, but things are going weird.
Image attached! Any insights?
Thanks.

You can post questions here too. If they are design questions if people know the answer they can respond too.
For this particular issue, it does look like a design problem. From the screen shots, I'm guessing that the light gray box is using negative top margin to overlap the darker dray box. I think for this change the dark gray box to use height:auto and add a padding-bottom to it for the current space below the text. That way when the text starts to push down there will be a constant amout of space from the bottom of the text to the bottom of the dark gray box and that will push the light gray box down as well.

How to make a tabstrip visible and invisible again?

Hi
I have a GUI with Fields, Texts, Checkboxes, Radio buttons, a Button and of
course a tabstrip with 7 tabs.
Before I want to show some data in the tabs of the tabstrip, I have to fill the fields, check a radio button and checkboxes. After filled all entries needed, I will start
the preparation of the data with clicking on the button.
Before the click on the button the tabstrip has to be invisible. After the preparation
of the data I will make the tabstrip with its tabs visible.
All this is in the same dynpro (e.g. 0100). I don't build it together with to dynpros.
I tried with LOOP AT SCREEN ... ENDLOOP, but the tabstrip does not appear.
The only attribute accessable is "activetab".
How to make that happen?
Thanks for your help
Frowin

Hi
Suppose you have 3 screen:
- 1 main screen (100)
- 2 subscreen    (101, 102)
In the subscreen 101 you need to design your tabstrip (so you need to move your tabstrip from main screen), the subscreen 102 has to be empty.
In the PBO of screen 100:
PROCESS PBO.
MODULE SET_SUBSCREEN.
CALL SUBSCREEN SUBAREA INCLUDING V_REPID V_SCREEN.
In the module SET_SUBSCREEN, you insert the code you need to choose the right subscreen:
IF _SHOW = 'X'.
V_SCREEN = '0101'.
ELSE.
V_SCREEN = '0102'.
ENDIF.
The flag _SHOW is setted in PAI after pressing the button:
MODULE USER_COMMAND.
    CASE OK_CODE.
       WHEN 'SHOW'. _SHOW = 'X'.
Max
Edited by: max bianchi on Jan 9, 2008 5:03 PM

How to make current value to default to all controls at once

Choosing "Data Operation" -> "Make Current Value Default" to multiple controls requires a lot of clicking. Is it possible to do this with one click?
Solved!
Go to Solution.

Yes. If you select no controls, it says "Make current values default", and it does all the controls at once. If you have a control selected, then it does only the selected controls.
Reinitialize current values to default works the same way. Select nothing, it does all the controls at once.
Bob Schor

How to make all columns visible in an interactive report by default

Hello All,
I have an interactive report with the first column is visible and the rest are hidden by default. Is there any way that i can make them all visible by default so the users do not have to go into actions to display them in report?
Thank you
Sezer

Login as developer > run the interactive report > actions > select all columns you want
Now got to actions > save > default > primary > apply
http://docs.oracle.com/cd/E23903_01/doc/doc.41/e21674/ir_using.htm#CHDFDFJA

How to make Transperant container visible , invisble by code

Dear experts ,
I want make transaperant container visible or invisible based some boolean value .
I have gone thr' class CL_WD_UIELEMENT and CL_WD_TRANSPARENT_CONTAINER. I have found method SET_VISIBLE .
Let suppose name of my transperant container TC_COSTCENTER .Please let me know what code I have to write . Where should I write ?
I am writing it code in WD_INIT as this process is based on value that I get on boolean value which tell decide visibility of Transperant container.
Waiting for reply . Urgetly .
Points will be given surely .
Cheers
Parry

Hi Parry,
The dynamic programming way is follows:
you need to first get a reference to the root element 'ROOTUIELEMENTCONTAINER' from the view reference available within the wddomodifyview method. the variable returned is of type cl_w_uielement_container. you can use the method get_root_element( ) of the interface if_wd_view for this purpose.
next get a reference to the transparent container by using the method get_child of the class cl_wd_uielement_container( using the variable returned from the prevoius call) and cast it to a variable of the class cl_wd_transparent_container. to this method you need to pass the id of your transparent container.
Once you have the reference you can use the method set_visible( ) to make the container visible or invisible at runtime.
However you need to be careful about the placement of this code within the wddomodifyview method because it would get executed every time. Thus the best way is to store the reference to view in a component controller the first time and later on use this attribute anywhere within your component.
Regards,
Shweta

For WRT1900AC, how do the 4 antennae work with each other?

I am curious how the 4 antennae work with each other. Does a wifi client need to communicate with all 4 antennae? Or just 1 (or 2)? I am curious, as I would like to move 1 or 2 of the antennae via proper cable to expand the coverage area.

bigdave240 wrote:
spec on that cable is 10.8dB per 100 feet. I would think that the router would still have a problem with that. Not sure how long the OP was going to make it but with the beaming technology i would think it would throw it off balance.
My maximum is 60ft when using LMR400 for standard wireless applications. I have done that many many times.
These days they typically integrate the higher gain antenna right into the bridge housing or mount the outdoor bridge right next to the antenna.
Please remember to Kudo those that help you.
Linksys
Communities Technical Support

Confusion about how object interact and are aware of each other

I have this java applet
Two of the classes it contains are the main class with the init method and a UI class that is code for the interface.
the main class instantiates the UI class anonymously (i think you call it that) i.e it does not put it into a named reference it just creates it by calling new without assigning it to anything.
When I click on a button from the UI class I want to call a method in the main class...but how so?
At first I tried to make the function i want to call in the main class static so I could easily call it from the UI class...but then it began to get complex...so i just sent a reference of the main class to the UI class via its constructer.
Now i want the main class to update a JTable in the UI class, but how? It does not have any reference to the UI class.
What is really the standard method of operation for this sort of thing when objects have to be calling methods of each other. How do I make them aware of each other.

the best way to do it is like this:
public class Main {
//this is the main class
private static class MyUIFrame extends JFrame {
    //create the class. It is useable within Main this way
    //static means it doesn't implicitly 'know' about the Main class. You can also
    //remove this and call Main.this to use Main's methods
}Edited by: tjacobs01 on Apr 11, 2009 2:28 AM

How can I have threads communicate with each other?

I'm working on a project that requires a group of classes communicating with each other. I decided on using a server and carrying out communication that way. However, my app only has communication between the client and server. I need the clients to be able to communicate with each other. Does anyone know how I can do this or point me to a good tutorial?

Sorry, here's a bone stock example of my server and client:
<SERVER>
package testserver;
import java.io.*;
import java.net.*;
import java.util.*;
public class TestServer
static int portOpen;
public static void main(String[] args)
portOpen=4000;
try
ServerSocket portListener = new ServerSocket(portOpen);
TestServer userThreads = new TestServer();
while (1==1)
Socket userConnection=portListener.accept();
userThreads.new PortConnection(userConnection);
catch (Exception e)
System.out.println("The server encountered a serious error. Server shut down.");
e.printStackTrace();
System.exit(0);
class PortConnection extends Thread
//Declare variables to handle connections.
Socket ourConnection;
BufferedReader serverInput;
PrintWriter serverOutput;
PortConnection(Socket userConnection)
try
ourConnection=userConnection;
serverInput=new BufferedReader(new InputStreamReader(userConnection.getInputStream()));
serverOutput=new PrintWriter(userConnection.getOutputStream(),true);
start();
catch (Exception e)
System.out.println("An error occurred when a user attempted a connection.");
public void run()
serverOutput.println("Welcome to the Server.");
try
serverOutput.close();
serverInput.close();
ourConnection.close();
catch (Exception e)
</SERVER>
<CLIENT>
package testclient;
import java.io.*;
import java.util.*;
import java.net.*;
public class TestClient {
static BufferedReader userInput;
static Socket quizServer;
static BufferedReader serverInput;
static PrintWriter serverOutput;
static String serverData;
public static void main(String[] args) {
userInput = new BufferedReader(new InputStreamReader(System.in));
try {
quizServer=new Socket("localhost",4000);
catch (Exception e) {}
try
serverInput=new BufferedReader(new InputStreamReader(quizServer.getInputStream()));
serverOutput=new PrintWriter(quizServer.getOutputStream(),true);
catch (Exception e) {}
try {
serverData=serverInput.readLine();
catch (Exception e) {}
System.out.println(serverData);
</CLIENT>

2 Gateways Sharing One Subnet - How to route traffic in and see each other?

Hello,
First, thanks for your feedback in advance.
I am rolling over from CheckPoint Security Gateways to Fortinet Gateways so I have set up one of each within my datacenter subnet as I wanted to keep the same subnet 192.168.10.0/24 and just roll over from CheckPoint to Fortinet.
My current production datacenter gateway (checkpoint) resides on 192.168.10.1/24 with it's own External IP. 100+ ip-sec vpn tunnels communicate through this gateway and happily talk to several servers on the datacenter side (ex. 192.168.10.20, 192.168.10.22,
etc)
Since I am preparing to roll over from CheckPoint to Fortinet, I've placed the new gateway in the same datacenter at 192.168.10.2/24, with its own external IP. I've also dropped in a test server at 192.168.10.121 with the gateway pointing to the new Checkpoint.
It happily gets out to the internet via the new gateway, 192.168.10.2.
I can get out to the world via each gateway when I am behind my datacenter and I configure the gateways on each server. And, they can all see each other and communicate within the 192.168.10.X network.
However, I cannot go from the a Checkpoint tunnel network (ex: 192.168.50.X) go through the CheckPoint datacenter gateway, 192.168.10.1 (via its tunnel) and hit my Fortinet Test server at 192.168.10.121 (fortinet test server gateway set to 192.168.10.2).
I have the IP statically set in the CheckPoint's DNS server at 192.168.10.20 to 192.168.10.121, but from the 192.168.50.X or any CheckPoint subnet, I can't ping or connect to it.
Vice-versa, I can go from a fortinet subnet (192.168.195.X) and hit my test server 192.168.10.121. However, I cannot go from a Fortinet tunnel network 192.168.195.X, go through my new Fortinet datacenter gateway, 192.168.10.2 (via its tunnel), and
hit any of my CheckPoint-side servers, 192.168.10.20, 192.168.10.22, etc.
Specifically, all of my scanners at the 100+ sites scan and send via an smtp server within my datacenter (192.168.10.56). When I deploy the new gateway, the scanner at the office cannot access this IP address to send the email.
Is there a way to sync two AD/DNS servers within my Datacenter but with different gateways? In theory, I'd like the request to come in from the outside (whether a checkpoint network or the new fortinet) it will look into its respective AD/DNS and
point it to the 192.168.10.56 smtp server.
It does not have to be AD/DNS, but that was the first idea that popped in my head. I am definitely open to the most efficient and stable method as I have to roll over 100 sites.
Thank you again!

Hi Strike First,
One issue is that we have over 100 remote sites that we are converting from CheckPoint to Fortinet. And, we do not have the man power to do a single night cutover as these are offices in remote locations.
I am a little confused on the layout you are proposing:
Set up fortinet as the backend firewall, point all internal gateways to this backend firewall, then have this firewall NAT through the current CheckPoint firewall?
Thank you very much for your guidance.

How to make the session to wait until other session get closed successfully

Hi ,
In my program , I am calling sql loader and after that I am opening a session and inside that I am calling stored procedure which validates the data.
above calling of sql loader and stored procedure is done inside the shell script i.e .prog file which is registerd as host concurrent program.
Here i am facing the problem like when two files are processed with same content then second file content's are not erroring out as duplicate though there is a duplicate validation exist inside the procedure. IF I call dbms_lock.sleep(60) then it is working and sencond file are records are error out with duplicate error message. but this is working only for small data files.
Please suggest me how to make the session to come out successfully then only i can open other sesssion .
Thanks
Raghav

user5853450 wrote:
Hi ,
In my program , I am calling sql loader and after that I am opening a session and inside that I am calling stored procedure which validates the data.
above calling of sql loader and stored procedure is done inside the shell script i.e .prog file which is registerd as host concurrent program.
Here i am facing the problem like when two files are processed with same content then second file content's are not erroring out as duplicate though there is a duplicate validation exist inside the procedure. IF I call dbms_lock.sleep(60) then it is working and sencond file are records are error out with duplicate error message. but this is working only for small data files.
Please suggest me how to make the session to come out successfully then only i can open other sesssion .
Thanks
RaghavFor starters you could use external tables rather than SQL*Loader and then you could keep all the control on the database side of things rather than relying on an external utility. The external tables will give you all the functionality of SQL*Loader but all you to just read the data using SQL select statements instead and cut out all the shell script dependency.
Alternatively you could also look at Job Chaining...
http://download.oracle.com/docs/cd/B19306_01/server.102/b14214/chapter1.htm#FEATURENO05574

How to make current visitors visible to each other

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