How to set up a shift register to unsigned 16?

How do you set a shift register to an unsigned 16?
It defaults to double but I want it a U16.
Ron
Attachments:
unsigned_init.GIF ‏14 KB

You'll either need to initialize the shift register by connecting a U16 constant to the left register outside the loop, or place a U16 Convert function from the Numeric>Conversion palette after the Increment function.
The default numeric data type is Double, so unless you specify what you want, that is what the Increment function will produce.
Ed
Ed Dickens - Certified LabVIEW Architect - DISTek Integration, Inc. - NI Certified Alliance Partner
Using the Abort button to stop your VI is like using a tree to stop your car. It works, but there may be consequences.

Similar Messages

How do i read the Shift register value of a vi which is written in the teststand sequence from labview exe

Dear All..
My Qusetion is ... I have a VI in which I can writ the data to shift register and I can read( Differenent cases). I am Running the VI in write mode to write SAY '100' in the shiftreg( VI will be In teststand Sequence) . And I am reading the VI in read mode using Labview. I am getting the data in labview.
When i conver my Reading Vi which is having that Read/Write vi in to EXE even then the test stand is writing the data to VI is Unable to reflect in labview.
Please Help me out with some solution.
Thanks
bhargav

I'm confused by your question:
Are you trying to transfer data from an Exe to TestStand and vice versa?
Or are you changing existing, working VIs into EXEs and then wondering why they won't behave the same?
Can you clarify some what your goal is?
There may be a better way to do what you want.
Thanks,
jigg
CTA, CLA
teststandhelp.com
~Will work for kudos and/or BBQ~

How can impliment a binary shift register in LabVIEW.

Respected Sir,
I am doing a project at VSSC,ISRO,TVM.For my
project i want to implement a binary shift register and this is
reuired to shift a Pseudo Random Noise. Can you help me to design a
binary shift register.

Hi proff,
do you mean shifting the bit content of a number by 'binary shift register'?
If so, there are several options. LabView provides many functions do achieve your goal:
Remember you can use boolean operation (AND, OR, XOR) also on numbers. Logical shifts can be made faster by using 'Add' or 'Quotient/Remainder' (at least in Assembler :-)...
Message Edited by GerdW on 03-14-2007 02:41 PM
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome
Attachments:
binaryshift.png ‏1 KB

Problem in using the shift Register

I have a problem regarding shift register when i was using it in my application.
During the runing of the application i found that sometime shift register not pass the value to the case structure. at that time result is not displayed.
i have attached the application in which that problem occur and the process regarding the execution, how bug produce and how to check where the shift register stop. please find the attachment and reply on the same.
Attachments:
Shift Register Checking Application.zip ‏173 KB

I'm sorry but I don't understand your program. I only see one shift register in Result Display.vi.
What I do see is a lot of odd constuctions of while loops that only run once in your Main.VI. Also, a heavy reliance on global and local variables that I suspect are leading to race conditions.
Have you tried using the debugging tools such as probes and highlight execution to see our your application is behaving?
I'd also be concerned about how you have "Lock Front Panel Until Event Completes" in the cases of your event structure. And those event call other subVI's that may take a while to run and rely on user interaction with the front panel. I also don't understand why when I hit "OK", the subVI front panel remains open. It just makes running your application that much more confusing.

How to quickly clear an array used in a shift register?

Hello all,
I'm sure this is a quick one, but I'm missing the concept.
I have an array of boolean in a shift register. I have a case where I need to basically 'reset' the array rather than append to it....what is the best way to do this?
Thank you,
cayenne
Solved!
Go to Solution.

stevem181 wrote:
Of course, it is possible that my benchmark program is flawed.
Yup, disable debugging and you will see that the inner FOR loop is folded in both cases and the time drops to about zero.
Testing with debugging enabled is potentially unfair, because the reshaping will have more debugging code because there are more potential places to probe a wire, for example. All that said, I don't really know what's more efficient. That would require much more sophisticated testing. My point was just a reminder that there are always many ways to do things.
(This is under LabVIEW 2012. Constant folding and dead code elimination of course differ between compiler versions)
Granted, I typically don't use any of these two versions: I also omit the diagram constant, set the tunnel to "use default if unwired" and keep in unwired in the "clear" case. Less diagram clutter and quicker coding.
Here's how it would look like.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
Folding.png ‏13 KB
UseDefault.png ‏3 KB

How to use shift register in this structure?

Dear All,
In order to use less variety of graph, I want to use shift register to manage and send data to graph.
But there is not only event structure in my vi, for some reason(because I want to use only one button to control running and stop, and this must do through variety of button, I can't put this loop into the event structure) I must use other while loops, I don't know how to use shift register in this structure.
Please tell me anything helpful.
Thank you!
Attachments:
shift register.vi ‏26 KB

hi there
there are a lot of solutions. my favorite one is the usage of a so called "FGV" (functional global variable). this allows you to strore, manipulate and transport data through your app with a minimum of wires. see attachment.. (other users may have other favorite solutions...)
Best regards
chris
CL(A)Dly bending G-Force with LabVIEW
famous last words: "oh my god, it is full of stars!"
Attachments:
Shift Register 7.1.zip ‏20 KB

How to use Shift Register?

Hi
Today I spend hours to ficure out how to use a shift register with labview.
I am going to calculate the acceleration of the wheels of an RC-car.
I want to use the simple function to calculate the acceleration.
a=(v1 -v0)/time
From this it follows that I need two speed (ms) values. I was thinking about including a shiftregister that I made before (attached) into the SpeedAngle.vi
But that doesn't work.
Is there maybe an other way to store two following values of the calculated speed? So that I can use it for further calculations.
Thank you!
Attached the two program files.
Bye
Attachments:
ShiftRegister1.vi ‏23 KB
SpeedAngleAdvancedEDIT.vi ‏187 KB

Hi
Thank you very much. Now it works. Attached you will find the program. Now I need to adjust the car with the program. Hope this also works.
One more question. Why isn't it possible to use a Numeric Control twice?
Because I wanted to use the Numeric Control that I use for the time constant (time) also for the calculation of the acceleration.
That doesn't work. Than I placed a Numeric Indicator to display the value of the time constant. But it just displayed the default value.
Bye
Attachments:
SpeedAngleAdvancedEDIT.vi ‏214 KB

Angle increments using shift key. How to set it up?

How to set up the angle increments (stops) to be used with the shift key? I need to set it up to 30 degrees increments.

The Shift key only constrains to 90° and 45° (based on the Constrain Angle in Prefs) and I don’t think you can change that.
At least I have been using Illie for several generations of donkeys and have never hit on (nor needed) a method involving Shift like you are asking for.
I have always found it easier to use the specific tools for Rotating, Scaling etc. rather than using the Selection tool and bounding boxes (as I assume you are doing). Maybe I’m old-fashioned and maybe it’s just a personal quirk, but hitting R or S keys seems to me to be a more convenient way of working.

How to set dom fidelity to false on an already registered schema

How to set dom fidelity to false on an already registered schema
Thanks
Message was edited by:
uraees

I guess that you will have to annotate the schema via updating schema or inserting the "xdb annotation" to deactivate the DOM fidelity. Reasoning from the most difficult situation that objects (XMLType objects created via registering the schema) are linked to the schema, this is probably not a supported way to do it.
Schema evolution is supported though, this would be the supported way to do it...
Do you have more info (including the database version in use)?

Whether its really bad to set uninitialized shift register

Hello Everyone!
Just two short and probably dummy questions, hoping u would pls answer it and thx very much!
1. Is it really not good to set a shift register without initialization? What will be the result? Since I read fr many books and they all said it is better to initialize shift register whenever u set one.
2. Is there any case that we need the uninitialized shift register?
Best regards!
Solved!
Go to Solution.

sophiey wrote:
Since I read fr many books and they all said it is better to initialize shift register whenever u set one.
What kind of books are you reading???
The decision to initialize or not, depends on the desired functionality. There is no global "better" at all. It depends what you want to do.
Uninitialized shift registers (or globally initialized feedback nodes) provide the core functionality of action engines. One of the most useful programming tools. Get familiar with it and your skills will increase dramatically!
LabVIEW Champion . Do more with less code and in less time .

How to program shift register to read only when a new user is detected from user?

Hi,
I'm currently developing a program for position control in labview. The program is quite simple, whereby user will input the distance that he wants the table to be in the labview program, and labview will send signal to move a motor that will turn a ball screw to move a table horizontally to the targetted position. The criteria is that the profile of the motor depends on the distance it needs to move, whether a two-phase (acceleration and deceleration) or three-phase (acceleration, constant velocity, deceleration) to reach the target position.
The problem occurs when the user wants to enter a new position (second input) for the table, as the input by user is position the table needs to be but the input required to determine which profile the motor follows depends on the distance that the table will move to get to the targetted position. Therefore, I would need a function to store the input by user temporarily, and recall it only when a new input from user is detected. By this, I would be able to use the difference of the input (input [n+1] - input[n]) and feed it to determine which profile the motor follows and the input by user can be kept as the position he wants the table to travel to (to compare with encoder).
I thought of using shift registers to do this, but I am not able to make it to perform the deduction ([n+1] - [n]) only when it detects a new input. When i try using shift register, it travels to the targetted position, and one it reaches it will travel back to the original position. For example, when a user input 90, it means the table needs to move to point 90. As the shift register is initialized to 0, it will move to point 90 (90-0 = 90) but upon reaching 90, the shift register sends a signal of 90 (90-90 = 0) and the table returns to it's initial position.
Is there any way that I can delay the reading of shift register only when a new input is detected or is there another way for me to achieve what i want?
I've tried searching the discussion forum and ni website but couldn't find similar problems. Thanks for your help in advance.
Solved!
Go to Solution.

Hi,
I've managed to get what I needed by using a shift register + event structure as suggested by Adnan. However, I face another problem after implementing SR+event. I've attached two files, first the original program and second the updated program using SR + event. (it's only the jpg file as I've forgotten to save the labview program, will upload the program by tomorrow.
In the original program, I have an elapsed time that is able to run continuously when I run the program. In the updated program, my elapsed time don't seem to run continuously when I run the program (as shown by elapsed time indicator). I need the elapsed time to run continuously as a input to calculate my motor profile.
I suppose this is caused by the introduction of the event structure, will adding a case structure to wrap the event structure solve the problem or is there another way to get pass this. Appreciate if someone could drop me a pointer or two.
Thanks
Attachments:
Mar 16 - continuous elapsed time.png ‏12 KB
Mar 16 - elapsed time not continuous after introducing shift register + event structure.png ‏17 KB

How to avoid the double memory assignment for an array which I connected to the shift register?

Hi,
I need to read a big block of data into an array. When I stop the program and then restart, I hope the program to use the previously load arrary instead of reloading it. So I put the initiat Data loading in a for loop (N =1) and connect the array to a shift Register. The problem here is it assigns memory twice, for the initiator data loading and shift register. Is there any way to limit the memory assaignment to 1 since I only need one copy.
Thanks.

JWJ wrote:
Since my original file is more than 2M and really comlicated, I just make a simple demo file to show my purpose.
Your current code is way too confusing, so I assume that the full code makes more sense. The program is unusable because the main FOR loop gets locked in an inner loop that consumes all CPU doing nothing.
I think that branching the main array into the (1) case structure and (2) inner while loop costs you an extra allocation. Here's a more reasonable way to do things. It elimiates the buffer allocation going into the case structure.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
DemoMOD.vi ‏11 KB

Is there a way to save state of shift register for initializing next time vi is started?

Hello all,
I've a quick question. I have right now....a numeric constant...starts with "1" intially when starting the vi.
I use this as a shift register on my main while loop....as the counter to use when the user clicks various items on my vi. This tracks the order the user wants things to happen later.
It has now occured to me..that the user might not have selected all possible options, before quitting the vi....and might need to restart it...and begin to select other options...needing to keep place form when he left off last.
Of course, with how I have it set up no...when the vi is started...the counter is reset to "1". All the objects on the screen, are in the state it was when it was stopped...objects selected prior to quitting are still selected in the proper order...but if the user starts to select anything unselected..rather than starting at the next count..it starts at 1.
Is there any way, upon quitting..to set the initialization counter to whatever number was last in the shift register..so that when the vi is started again...it will start up where it left off?
Thank you in advance,
cayenne

I want to clarify. I'm assuming you have a config window or something that you open and close, but you don't actually stop the program? However, if this is your main window and you are stoppping the program then restarting, in reality you should have the program actually exit. The user should never have to press the run arrow in an executable to keep it consistent with other windows applications. It's (generally) confusing to an end user if they click the "x" and their program stays open. Then they have to click an arrow to make it start again.
CLA, LabVIEW Versions 2010-2013

Using a shift register to detect input...

Hi guys,
I'm creating a LabVIEW VI that needs to be able to detect when a user changes an input. I read a previous post that suggested using clusters and shift registers to compare previous data.
My question is how do I use shift registers? I've created a shift register on a for loop, but I'm not sure when to compare the "previous" data to the "new" data. Do I need to add an element to the left side and compare it there? Is the right side the output? I'm just not sure how it works. An uploaded example would be nice. Thanks.
-Mike

Shift registers are very powerful but difficult to use for the first time.
The shift register you just created has two "arrows", one on either side of the structure. The arrow to the left is the value from the previous (i:th) iteration and the arrow to the right you have to feed with the (i+1)th value.
Now, if you want to compare values and look for a change you can compare your old value (the one coming out from the left) with the new value in your for loop. The feed your new value to the right arrow so that it becomes the old value for the next iteration.
If you have many parameters to compare, clusters are very useful since they make things very compact. If you are comparing clusters, do not forget to change the setting on the comparison to compare aggregates (r
ight click on it and select that option).
Also, in most cases you need to set the initial (start) value for your shift register. This is done by feeding the left arrow with the default value from the outside of your loop.
I attached a simple example, CompareSettings.vi, that shows how it works. Hope this helps. /Mikael"
Attachments:
comparesettings.vi ‏32 KB

How to set alarm

in my project iam measuring temperature,if the value goes above or below certain values alarm is indicated in a file.But this alarm should be shown in a file ,if the alarm set and clear occure more than 3 times in 5 seconds .If the alarm set or clear is less than 3 times in 5 seconds it is not treated as alarm.please help me how to do this.

Hi,
You can keep track of the number of alarms by using a shift register adding 1 everytime the alarm goes off. By using the tick count you can monitor the seconds elapsed.
I have created an example that shows how this could be done. Press the Alarm? boolean botton 3 times within 5 seconds and the program stops and generate an alarm. Otherwise the program just stops executing after 5 secs
Let me know if this doesnt solve you problem.
Regards
A Meister
NIDK
Attachments:
3 Alarms in 5 secs.vi ‏29 KB

How to set up a shift register to unsigned 16?

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