I'm trying to make i(to the power of n) over n.quickanswer=MANY duke dollar

Question

I will pay many duke dollars for a quick answer to this.
i(to the power of)n
the full equation is r=---
n
heres what i did:
class Project
     public static void main(String[] arguments) {
          int P = 0;
          int r = 0;
          int n = 0;
          int t = 0;
          int i = 0     
          int interest = i public static double exp(n) / n;
          system.out.print("The Interest rate is" + interest);
          int rate = 1 + r public static double exp(1/n) h;//the effective rate
          system.out.println("The effective rate is" + rate);
     int A = P (1 + i public static double exp(n) /n) public static double exp(n*t);
The program isn't finished i have to get this far without errors

Answer 1

one last thing. could you just go over this briefly and quickly?
class Project { 
     public static void main(String[] arguments) {
          int P = 0;
          int r = 0;
          int n = 0;
          int t = 0;
          int i = 0;     
          //these values are put in by you, the user.
          int interest = Math.pow(i, n) / n;
system.out.print("The Interest rate is" + interest);
          int rate = Math.pow((1 + r), 1/n) ;//the effective rate
system.out.println("The effective rate is" + rate);
          int A = P * Math.pow( (1 + Math.pow(i, n) / n), n * t); system.out.print("The total holdings (A) is" + A);
          int e = Math.pow(1 + (1 / n), n);     system.out.print("The return (e) is" + e);
          int time = P Math.pow(1 + r, t);
system.out.print("The time needed to double?");
system.out.print("The time needed for this principal is" + time);