I unzipped an email zip file in Winzip and its a PDF. Now, I can't get it intoo Adobe to get it into Adobe to see the PDF.
how can I see this PDF on my iphone 5s?
Thanks
Can't copy or move unzipped PDF file.
Can't see option to export unzipped PDF from Winzip app to Adobe app on iPhone 5s.
Mike
GMT
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Cannot extract Zip file with Winzip after zipping with java.util.zip
Hi all,
I write a class for zip and unzip the text files together which can be zip and unzip successfully with Java platform. However, I cannot extract the zip file with Winzip or even WinRAR after zipping with Java platform.
Please help to comment, thanks~
Below is the code:
=====================================================================
package myapp.util;
import java.io.* ;
import java.util.TreeMap ;
import java.util.zip.* ;
import myapp.exception.UserException ;
public class CompressionUtil {
public CompressionUtil() {
super() ;
public void createZip(String zipName, String fileName)
throws ZipException, FileNotFoundException, IOException, UserException {
FileOutputStream fos = null ;
BufferedOutputStream bos = null ;
ZipOutputStream zos = null ;
File file = null ;
try {
file = new File(zipName) ; //new zip file
if (file.isDirectory()) //check if it is a directory
throw new UserException("Invalid zip file ["+zipName+"]") ;
if (file.exists() && !file.canWrite()) //check if it is readonly
throw new UserException("Zip file is ReadOnly ["+zipName+"]") ;
if (file.exists()) //overwrite the existing file
file.delete();
file.createNewFile();
//instantiate the ZipOutputStream
fos = new FileOutputStream(file) ;
bos = new BufferedOutputStream(fos) ;
zos = new ZipOutputStream(bos) ;
this.writeZipFileEntry(zos, fileName); //call to write the file into the zip
zos.finish() ;
catch (ZipException ze) {
throw ze ;
catch (FileNotFoundException fnfe) {
throw fnfe ;
catch (IOException ioe) {
throw ioe ;
catch (UserException ue) {
throw ue ;
finally {
//close all the stream and file
if (fos != null)
fos.close() ;
if (bos != null)
bos.close();
if (zos != null)
zos.close();
if (file != null)
file = null ;
}//end of try-catch-finally
private void writeZipFileEntry(ZipOutputStream zos, String fileName)
throws ZipException, FileNotFoundException, IOException, UserException {
BufferedInputStream bis = null ;
File file = null ;
ZipEntry zentry = null ;
byte[] bArray = null ;
try {
file = new File(fileName) ; //instantiate the file
if (!file.exists()) //check if the file is not exist
throw new UserException("No such file ["+fileName+"]") ;
if (file.isDirectory()) //check if the file is a directory
throw new UserException("Invalid file ["+fileName+"]") ;
//instantiate the BufferedInputStream
bis = new BufferedInputStream(new FileInputStream(file)) ;
//Get the content of the file and put into the byte[]
int size = (int) file.length();
if (size == -1)
throw new UserException("Cannot determine the file size [" +fileName + "]");
bArray = new byte[(int) size];
int rb = 0;
int chunk = 0;
while (((int) size - rb) > 0) {
chunk = bis.read(bArray, rb, (int) size - rb);
if (chunk == -1)
break;
rb += chunk;
}//end of while (((int)size - rb) > 0)
//instantiate the CRC32
CRC32 crc = new CRC32() ;
crc.update(bArray, 0, size);
//instantiate the ZipEntry
zentry = new ZipEntry(fileName) ;
zentry.setMethod(ZipEntry.STORED) ;
zentry.setSize(size);
zentry.setCrc(crc.getValue());
//write all the info to the ZipOutputStream
zos.putNextEntry(zentry);
zos.write(bArray, 0, size);
zos.closeEntry();
catch (ZipException ze) {
throw ze ;
catch (FileNotFoundException fnfe) {
throw fnfe ;
catch (IOException ioe) {
throw ioe ;
catch (UserException ue) {
throw ue ;
finally {
//close all the stream and file
if (bis != null)
bis.close();
if (file != null)
file = null ;
}//end of try-catch-finally
}Tried~
The problem is still here~ >___<
Anyway, thanks for information sharing~
The message is:
Cannot open file: it does not appear to be a valid archive.
If you downloaded this file, try downloading the file again.
The problem may be here:
if (fos != null)
fos.close() ;
if (bos != null)
bos.close();
if (zos != null)
zos.close();
if (file != null)
file = null ;
The fos is closed before bos so the last buffer is not
saved.
zos.close() is enough. -
Want To create Zip file using java,And Unzip without Java Program
I want to create a zip text file using java, I know Using ZipOutputStream , we can create a zip file, , But i want to open that zip file without java program. suppose i use ZipOutputStream , then zip file is created But for unZip also difftrent program require. We cant open that zip file without writing diff java program.
Actually i have one text file of big size want to create zip file using java , and unzip simply without java program.Its Possible??
Here is one answer But I want to open that file normal way(
For Exp. using winzip we can create a zip file and also open simply)
http://forum.java.sun.com/thread.jspa?threadID=5182691&tstart=0Thanks for your Reply,
I m creating a zip file using this program, Zip file Created successfully But when im trying to open .zip file i m getting error like "Canot open a zip file, it does not appear to be valid Archive"
import java.io.*;
import java.util.zip.*;
public class ZipFileCreation
public static void main (String argv[])
try {
FileOutputStream fos = new FileOutputStream ( "c:/a.zip" );
ZipOutputStream zip = new ZipOutputStream ( fos );
zip.setLevel( 9 );
zip.setMethod( ZipOutputStream.DEFLATED );
// get the element file we are going to add, using slashes in name.
String elementName = "c:/kalpesh/GetSigRoleInfo092702828.txt";
File elementFile = new File ( elementName );
// create the entry
ZipEntry entry = new ZipEntry( elementName );
entry.setTime( elementFile.lastModified() );
// read contents of file we are going to put in the zip
int fileLength = (int)elementFile.length();
System.out.println("fileLength = " +fileLength);
FileInputStream fis = new FileInputStream ( elementFile );
byte[] wholeFile = new byte [fileLength];
int bytesRead = fis.read( wholeFile , 0 /* offset */ , fileLength );
// checking bytesRead not shown.
fis.close();
// no need to setCRC, or setSize as they are computed automatically.
zip.putNextEntry( entry );
// write the contents into the zip element
zip.write( wholeFile , 0, fileLength );
zip.closeEntry(); System.out.println("Completed");
// close the entire zip
catch(Exception e) {
e.printStackTrace();
} -
Hello.... can anyone tell me why when I email myself an epub file....it arrives in my inbox as a Zip file...and iBooks cannot open it. Any suggestions would be appreciated...thanks
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Create Zip File In Windows and Extract Zip File In Linux
I had created a zip file (together with directory) under Windows as follow (Code are picked from [http://www.exampledepot.com/egs/java.util.zip/CreateZip.html|http://www.exampledepot.com/egs/java.util.zip/CreateZip.html] ) :
package sandbox;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
* @author yan-cheng.cheok
public class Main {
* @param args the command line arguments
public static void main(String[] args) {
// These are the files to include in the ZIP file
String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"};
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// Create the ZIP file
String outFilename = "outfile.zip";
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename));
// Compress the files
for (int i=0; i<filenames.length; i++) {
FileInputStream in = new FileInputStream(filenames);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filenames[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
// Complete the entry
out.closeEntry();
in.close();
// Complete the ZIP file
out.close();
} catch (IOException e) {
e.printStackTrace();
The newly created zip file can be extracted without problem under Windows, by using [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html]
However, I realize if I extract the newly created zip file under Linux, using modified version of [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html] . The original version doesn't check for directory using zipEntry.isDirectory()).public static boolean extractZipFile(File zipFilePath, boolean overwrite) {
InputStream inputStream = null;
ZipInputStream zipInputStream = null;
boolean status = true;
try {
inputStream = new FileInputStream(zipFilePath);
zipInputStream = new ZipInputStream(inputStream);
final byte[] data = new byte[1024];
while (true) {
ZipEntry zipEntry = null;
FileOutputStream outputStream = null;
try {
zipEntry = zipInputStream.getNextEntry();
if (zipEntry == null) break;
final String destination = Utils.getUserDataDirectory() + zipEntry.getName();
if (overwrite == false) {
if (Utils.isFileOrDirectoryExist(destination)) continue;
if (zipEntry.isDirectory())
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(destination);
else
final File file = new File(destination);
// Ensure directory is there before we write the file.
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(file.getParentFile());
int size = zipInputStream.read(data);
if (size > 0) {
outputStream = new FileOutputStream(destination);
do {
outputStream.write(data, 0, size);
size = zipInputStream.read(data);
} while(size >= 0);
catch (IOException exp) {
log.error(null, exp);
status = false;
break;
finally {
if (outputStream != null) {
try {
outputStream.close();
catch (IOException exp) {
log.error(null, exp);
break;
if (zipInputStream != null) {
try {
zipInputStream.closeEntry();
catch (IOException exp) {
log.error(null, exp);
break;
} // while(true)
catch (IOException exp) {
log.error(null, exp);
status = false;
finally {
if (zipInputStream != null) {
try {
zipInputStream.close();
} catch (IOException ex) {
log.error(null, ex);
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException ex) {
log.error(null, ex);
return status;
*"MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory.*
I try to solve the problem by changing the zip file creation code to
+String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"};+
But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)
p/s To be honest, I do a cross post at [http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux|http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux] Just want to get more opinion on this.
Edited by: yccheok on Apr 26, 2010 11:41 AMYour solution lies in the File.separator constant; this constant will contain the path separator that is used by the operating system. No need to hardcode one, Java already has it.
edit: when it comes to paths by the way, I have the bad habit of always using the front slash ( / ). This will also work under Windows and has the added benefit of not needing to be escaped. -
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Supply pertinent information for quicker answers
The more information you supply about your situation, the better equipped other community members will be to answer. Consider including the following in your question:
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