Identify document elements, mark as XML?

Hi all,
Currently working on a Web-to-print project using InDesign Server CS5 and JavaScript.
What I'd like to do is enable the following to happen:
A user uploads an .indd document (OK with this!).
A JS script loops through the document and identifies all the elements of the document (text areas, images, etc).
The user is then prompted to select which elements of the document they would like to mark as 'editable'.
The elements that the user has selected as editable are tagged in the .indd as XML elements.
The .indd is saved and closed.
I'm relatively new to InDesign scripting, and I'm hoping this isn't something too unusual that I'm trying to achieve! Does anyone have any advice/ideas as to how this could be achieved?
Many thanks

Well, yes, I think so (I don't have the XML syntax memorized...) but...that's not typically how you would want to tag your XML elements.
I mean, generally you'd want something like:
<rect count="1">...</rect>
<rect count="2">...</rect>
<text count="3">...</text>
if you wanted counts. But you wouldn't create new tags for every object:
<tag1>...my rectangel data</tag1>
<tag2>...rect2 data</tag2>
<tag3>...text data...</tag3>
It's certainly going to make it hard to parse your XML with standards tools. Instead use an attribute. Or why even make them unique like that? I'm not sure t's The XML Way?
Anyhow, sure looks like you've found your footing.

Similar Messages

Identify individual elements in repeated elements in an XML document

Hello,
I'd like to identify individual elements in repeated elements in an XML document.
For example a table 'dataXML' which has a column 'sample' (XMLType). If I have an XML document such as,
<ELEMENT>
<PO>
<PONO>100</PONO>
<PONO>200</PONO>
</PO>
</ELEMENT>
I can use //PONO[1] to identify the first "PONO" element (with value 100) and //PONO[2] to identify the second "PONO" element in the document.
If I write this query:
select L.sample.extract('ELEMENT/PO/PONO/text()')).getStringVal()"SAMP"
from dataXML L
I'll receive this result:
SAMP
100200 (the first row)
And if I write this query:
select L.sample.extract('ELEMENT/PO/PONO[1]/text()')).getStringVal()"SAMP"
from dataXML L
I'll receive this result:
SAMP
100 (the first row)
But I'd like the following result:
SAMP
100 (the first row)
200 (the second row).
Could you help me, please?
Thank you very much.
Melissa Lemos

you have to use something like this.
select extractvalue(xmltype_column, '/Name/@attributename')
from table_name
For more details see
XMLDB Developers Guide (Oracle 9i)
Chapter - XPATH and namespace Primer
Table C2 - Location Path Examples Using Abbreviated Syntax.
Page Number 907/1044
Hope this helps.

Problem in digitally signing a particular element of an XML Document

hi all!!
I was trying to sign a particular element of an XML document using JSR105 (XML Digital Signatures) API.
For which i used +#xpointer(id('idvalue'))+ and +#idvalue+ as the URI for the reference i create as below :
Reference ref = fac.newReference("#xpointer(id('123')) ", fac.newDigestMethod(DigestMethod.SHA1, null), Collections.singletonList(fac.newTransform(Transform.ENVELOPED,(TransformParameterSpec) null)), null, null);
NOTE: Here 123 is the value of the attribute 'id' of the element i wish to sign in the input XML document.
But when i try to digest and sign the the above created reference, i get the following exception (which is strange! atleast for me!)
Exception in thread "main" javax.xml.crypto.dsig.XMLSignatureException: javax.xml.crypto.URIReferenceException: Can't resolve ID: '123' in ''
at com.ibm.xml.crypto.dsig.dom.ReferenceImpl.calculateDigestValue(ReferenceImpl.java:327)
at com.ibm.xml.crypto.dsig.dom.ReferenceImpl.sign(ReferenceImpl.java:237)
at com.ibm.xml.crypto.dsig.dom.XMLSignatureImpl.sign(XMLSignatureImpl.java:158)
at sent.Generate.main(Generate.java:103)
Caused by: javax.xml.crypto.URIReferenceException: Can't resolve ID: '123' in ''
at com.ibm.xml.crypto.dsig.dom.URIDereferencerImpl.dereference(URIDereferencerImpl.java:193)
at com.ibm.xml.crypto.dsig.dom.ReferenceImpl.calculateDigestValue(ReferenceImpl.java:285)
+... 3 more+
javax.xml.crypto.URIReferenceException: Can't resolve ID: '123' in ''
at com.ibm.xml.crypto.dsig.dom.URIDereferencerImpl.dereference(URIDereferencerImpl.java:193)
at com.ibm.xml.crypto.dsig.dom.ReferenceImpl.calculateDigestValue(ReferenceImpl.java:285)
at com.ibm.xml.crypto.dsig.dom.ReferenceImpl.sign(ReferenceImpl.java:237)
at com.ibm.xml.crypto.dsig.dom.XMLSignatureImpl.sign(XMLSignatureImpl.java:158)
at sent.Generate.main(Generate.java:103)
I've given the whole Java code i used to generate the signature and the XML i used below for you to get a clear picture of what i tried...
Any suggestions are very much welcome..
thanks..
ragu
Generate.java
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.security.InvalidAlgorithmParameterException;
import java.security.KeyException;
import java.security.KeyPair;
import java.security.KeyPairGenerator;
import java.security.NoSuchAlgorithmException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import javax.xml.crypto.MarshalException;
import javax.xml.crypto.dsig.CanonicalizationMethod;
import javax.xml.crypto.dsig.DigestMethod;
import javax.xml.crypto.dsig.Reference;
import javax.xml.crypto.dsig.SignatureMethod;
import javax.xml.crypto.dsig.SignedInfo;
import javax.xml.crypto.dsig.Transform;
import javax.xml.crypto.dsig.XMLSignature;
import javax.xml.crypto.dsig.XMLSignatureException;
import javax.xml.crypto.dsig.XMLSignatureFactory;
import javax.xml.crypto.dsig.dom.DOMSignContext;
import javax.xml.crypto.dsig.keyinfo.KeyInfo;
import javax.xml.crypto.dsig.keyinfo.KeyInfoFactory;
import javax.xml.crypto.dsig.keyinfo.KeyValue;
import javax.xml.crypto.dsig.spec.C14NMethodParameterSpec;
import javax.xml.crypto.dsig.spec.TransformParameterSpec;
import javax.xml.crypto.dsig.spec.XPathFilterParameterSpec;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.xml.sax.SAXException;
public class Generate {
      * @param args
      * @throws NoSuchAlgorithmException
      * @throws InvalidAlgorithmParameterException
      * @throws KeyException
      * @throws ParserConfigurationException
      * @throws IOException
      * @throws SAXException
      * @throws FileNotFoundException
      * @throws XMLSignatureException
      * @throws MarshalException
      * @throws TransformerException
     public static void main(String[] args) throws NoSuchAlgorithmException,
               InvalidAlgorithmParameterException, KeyException,
               FileNotFoundException, SAXException, IOException,
               ParserConfigurationException, MarshalException,
               XMLSignatureException, TransformerException {
          java.security.Security
                    .addProvider(new com.ibm.xml.crypto.IBMXMLCryptoProvider());
          XMLSignatureFactory fac = XMLSignatureFactory.getInstance("DOM",
                    new com.ibm.xml.crypto.IBMXMLCryptoProvider());
          //reference generation
          //its here where I point the URI to the element i want to digest
          Reference ref = fac.newReference("#xpointer(id('123'))", fac.newDigestMethod(DigestMethod.SHA1, null), Collections.singletonList(fac.newTransform(Transform.ENVELOPED,(TransformParameterSpec) null)), null, null);
          //signedinfo element generation
          SignedInfo si = fac
                    .newSignedInfo(fac.newCanonicalizationMethod(
                              CanonicalizationMethod.INCLUSIVE,
                              (C14NMethodParameterSpec) null), fac
                              .newSignatureMethod(SignatureMethod.RSA_SHA1, null),
                              Collections.singletonList(ref));
          KeyInfoFactory kif = fac.getKeyInfoFactory();
          //Create a DSA KeyPair
          KeyPairGenerator kpg = KeyPairGenerator.getInstance("RSA");
          kpg.initialize(512);
          KeyPair kp = kpg.generateKeyPair();
          KeyValue kv = kif.newKeyValue(kp.getPublic());
          // Create a KeyInfo and add the KeyValue to it
          KeyInfo ki = kif.newKeyInfo(Collections.singletonList(kv));
          // Instantiate the document to be signed
          DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
          dbf.setNamespaceAware(true);
          Document doc = dbf.newDocumentBuilder().parse(
                    new FileInputStream(new File("shippedPedigree.xml")));
          // Create a DOMSignContext and specify the DSA PrivateKey and
          // location of the resulting XMLSignature's parent element
          DOMSignContext dsc = new DOMSignContext(kp.getPrivate(), doc
                    .getDocumentElement());
          //Create the XMLSignature (but don't sign it yet)
          XMLSignature signature = fac.newXMLSignature(si, ki);
          // Marshal, generate (and sign) the enveloped signature
          signature.sign(dsc);
          //writing the signed document back to the file
          OutputStream os;
          os = new FileOutputStream(new File("shippedpedigree.xml"));
          TransformerFactory tf = TransformerFactory.newInstance();
          Transformer trans = tf.newTransformer();
          trans.transform(new DOMSource(doc), new StreamResult(os));
the "shippedPedigree.xml" i used to sign:
<?xml version="1.0" encoding="UTF-8"?>
<ped:pedigree xmlns:ped="urn:epcGlobal:Pedigree:xsd:1" xmlns:ds="http://www.w3.org/2000/09/xmldsig#">
<ped:shippedPedigree id="123">
<ped:documentInfo>
<ped:serialNumber>2233</ped:serialNumber>
<ped:version>ped:version</ped:version>
</ped:documentInfo>
<ped:signatureInfo>
<ped:signerInfo>
<ped:name>Joe Doe</ped:name>
<ped:title>Manager</ped:title>
<ped:telephone>800-521-6010</ped:telephone>
<ped:email>[email protected]</ped:email>
<ped:url>www.kittinginc.com</ped:url>
</ped:signerInfo>
<ped:signatureDate>2001-12-31T12:00:00</ped:signatureDate>
<ped:signatureMeaning>Certified</ped:signatureMeaning>
</ped:signatureInfo>
<ped:itemInfo>
     <ped:lot>123</ped:lot></ped:itemInfo>
</ped:shippedPedigree></ped:pedigree>
------------------------------------------------------------------------

Sabarisri N wrote:
Hi All,
my xml is like below.
<ns1:abcd>
<ns2:a>1</ns2:a>
<ns2:b>2</ns2:b>
</ns1:abcd>
If i try retrieving the value of the root element of this xml document,
Node myroot=doc.getDocumentElement();
String result=myroot.getNodeName();
My output is ns1:abcd .. i want only "abcd"...
The parser is returning the correct rootNodeName i.e ns1:abcd. rootNodeName always goes with the given input and returns the root element as is.
>
My xml will not always have same namespaces.. from the incoming xml i should first check, for the namespaces..Please give me some idea.
I guess.. I need some namespace evaluation to be set..
Refer below link it'll give idea of identifying XML-NAMESPACE-PREFIX
http://java.sun.com/developer/Books/xmljava/ch03.pdf
http://download.oracle.com/javaee/1.4/tutorial/doc/JAXPSAX9.html
Please help me in this regard.
Thanks,
Sabarisri. N

How to Add namespace to all elements in a xml document

Hi,
I am trying to read an xml file that does not have any namespace definitions. I have been able to create another schema in which i specify the namespace defination as shown below.
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://TargetNamespace.com/AckPaymentFile_PL" targetNamespace="http://TargetNamespace.com/AckPaymentFile_PL" xmlns:nxsd="http://xmlns.oracle.com/pcbpel/nxsd" nxsd:version="DTD" elementFormDefault="qualified" attributeFormDefault="unqualified">
<include schemaLocation="PM_XML_FILE_ACK_SCHEMA_NO_NAMESPACE.xsd"/>
</xs:schema>
Once i do it, i am able to see the namespace has been assigned to the root element. I am looking for a way to assign the namespace and prefix tag to all elements in the xml document. If i don't i am unable to access any part of the xml document, keep getting please verify if xpath is correct.
Thanks
Sridhar

Hello,
Once you've answered all the above.
If you can run xpath that supports functions against the xml, the expression:
count(//phone)Otherwise, without leaving SQL:
select count(*) from
xmltable('//phone' passing
-- Your XML goes here, could be a table column with type XMLTYPE.
xmltype('<person><phone>123-456-7890</phone><phone>098-765-4321</phone></person>')
columns phone varchar2(24 char) path '/phone'
;

Inserting an element into an XML document

I am simply looking insert a new element into an existing XML Document using JDOM. Here is my code so far:
public class UserDocumentWriter {
     private SAXBuilder builder;
     private Document document;
     private File file = new File("/path/to/file/users.xml");
     private Element rootElement;
     public UserDocumentWriter() {
          builder = new SAXBuilder();
          try {
               document = builder.build(file);
               rootElement = document.getRootElement();
          } catch (IOException ioe) {
               System.err.println("ERROR: Could not build the XML file.");
          } catch (JDOMException jde) {
               System.err.println("ERROR: " + file.toString() + " is not well-formed.");
     public void addContact(String address, String contact) {
          List contactList = null;
          Element contactListElement;
          Element newContactElement = new Element("contact");
          newContactElement.setText(contact);
          List rootsChildren = rootElement.getChildren();
          Iterator iterator = rootsChildren.iterator();
          while (iterator.hasNext()) {
               Element e = (Element) iterator.next();
               if (e.getAttributeValue("address").equals(address)) {
                    contactListElement = e.getChild("contactlist");
                    contactListElement.addContent(newContactElement);
                    writeDocument(document);
     public void writeDocument(Document doc) {
          try {
               XMLOutputter output = new XMLOutputter();
               OutputStream out = new FileOutputStream(file);
               output.output(doc, out);
          } catch (FileNotFoundException ntfe) {
               System.err.println("ERROR: Output file not found.");
          } catch (IOException ioe) {
               System.err.println("Could not output document changes.");
     }However, the problem is, the newly added element will always be appended to the end of the last line, resulting in the following:
<contactlist>
            <contact>[email protected]</contact><contact>[email protected]</contact></contactlist>Is there anyway in which I can have the newly added element create it's own line for the purpose of tidy XML? Alternatively is there a better methodology to do the above entirely?

Your question is not very clear.
Do you want to know How to insert an element into an XML document?
Answer: I can see you already know how to do it. You have added the element using addContent()
or do you want to know How to display the XML in a tidy format?
Answer: to view the XML in a properly formatted style you can you the Format class. A very basic way of viewing the XML would be:
   * Prints the Document to the specified file.
   * @param doc
   * @param filename
   * @param formatting
public static void printDocToFile(Document doc, String strFileName,
      boolean formatting)
    XMLOutputter xmlOut = null;
    if (!formatting)
      xmlOut = new XMLOutputter();
    } else
      Format prettyFormat = Format.getPrettyFormat();
      prettyFormat.setOmitEncoding(false);
      prettyFormat.setOmitDeclaration(false);
      xmlOut = new XMLOutputter(prettyFormat);
    try
      if (doc != null)
        FileWriter writer = new java.io.FileWriter(strFileName, true);
        xmlOut.output(doc, writer);
        writer.flush();
        writer.close();
      } else
        System.out.println("Document is null.");
    catch (Exception ex)
      System.out.println(ex);
}

How to Find Number of Given Element in a XML Document

Hello Experts,
I want to know the number of given element in a XML document. For example if we have an employees information as a XML document, can we have how many <phone> element in the XML document?
Thanks in advance.
Regards,
JP

Hello,
Once you've answered all the above.
If you can run xpath that supports functions against the xml, the expression:
count(//phone)Otherwise, without leaving SQL:
select count(*) from
xmltable('//phone' passing
-- Your XML goes here, could be a table column with type XMLTYPE.
xmltype('<person><phone>123-456-7890</phone><phone>098-765-4321</phone></person>')
columns phone varchar2(24 char) path '/phone'
;

Parse file without xml specification or document element

I have a large (600mb) log file that is in xml format but it does not have an xml specification and has no document element.
file looks like this:
<message>...</message>
<message>...</message>

<message>...</message>
<message>...</message>
I have written a class that overrides the SAX DefaultHandler but now want to be able to parse the document without having to add the xml spec and document element manually.
I've thought about writing a subclass of FileReader that adds the xml specification and document element before reading physical file but would also need to add closing document element at end of file.
Is there a simpler way?

Hi,
There is another way around the problem of adding a missing root node. This involves adding an extra DTD file and a xml file, like this one:
<?xml version='1.0' encoding='UTF-8' standalone="no"?>
<!DOCTYPE messageSet SYSTEM "logfile.dtd"
[<!ENTITY data SYSTEM "logfile.xml">]
>
<messageSet>
&data;
</messageSet>
This file "includes" the logfie.xml, as an external entity, with your messages as child nodes of element messageSet.
In your program you refer to this xml file when parsing the messages.

Use DOM to get the element value of XML document?

I can not to use the method getNodeValue to get the element value of XML document. How can I do for it?
For example, for element
<address>125 Smith Avenue</address>
how to get the value "125 Smith Avenue" by using DOM?
Thanks

Thanks for all of you.
The code indicates that I need to get the node by tag name. If I do not know the distribution of the elements and want to traverse all nodes. If the node contains value, I retrieve the value. How to implement the general case.
For example, my XML file represent a directory hierarchy and looks like
<root>
<usr>
<user>user1
<file>file1</file>
<file>file2</file>
</user>
<user>user2
<file>file1</file>
<file>file2</file>
<file>file3</file>
<file>file4</file>
</user>
</usr>
</root>

SSMS 2012:FOR XML PATH Using XPath Node Tests-Columnn name 'test()' contains an invalid XML identifier as required by FOR XML?

Hi all,
I am learning XPATH and XQUERY from the Book "Pro T-SQL 2008 Programmer's Guide" written by Michael Coles, (published by apress). I copied the Code Listing 12-8 FOR XML PATH Using XPath Node Tests (listed below) and executed it in my
SQL Server 2012 Management Studio:
--Coles12_8.sql // saved in C:/Documemnts/SQL Server Management Studio
-- Coles Listing 12-8 FOR XML PATH Using XPATH Node Tests
-- Retrieving Name and E-mail Addresses with FOR XML PATH in AdvantureWorks
-- 16 March 2015 0935 AM
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "test()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH;
I got the following error message:
Msg 6850, Level 16, State 1, Line 2
Column name 'test()' contains an invalid XML identifier as required by FOR XML; '('(0x0028) is the first character at fault.
I have no ideas why I got this error message. Please kindly help and advise me how to resolve this error.
Thanks in advance, Scott Chang

Hi Michelle, Thanks for your nice response.
I corrected the mistake and executed the revised code. It worked nicely.
I just have one question to ask you about the appearance of the xml output of my Co;les12_8.sql:
<row>
<?nameStyle 0?>
<Person ID="1" />
697-555-0142<Person><Name><First>Ken</First><Middle>J</Middle><Last>Sánchez</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="2" />
819-555-0175<Person><Name><First>Terri</First><Middle>Lee</Middle><Last>Duffy</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="3" />
212-555-0187<Person><Name><First>Roberto</First><Last>Tamburello</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="4" />
612-555-0100<Person><Name><First>Rob</First><Last>Walters</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="5" />
849-555-0139<Person><Name><First>Gail</First><Middle>A</Middle><Last>Erickson</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="6" />
122-555-0189<Person><Name><First>Jossef</First><Middle>H</Middle><Last>Goldberg</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="7" />
181-555-0156<Person><Name><First>Dylan</First><Middle>A</Middle><Last>Miller</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="8" />
815-555-0138<Person><Name><First>Diane</First><Middle>L</Middle><Last>Margheim</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="9" />
185-555-0186<Person><Name><First>Gigi</First><Middle>N</Middle><Last>Matthew</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="10" />
330-555-2568<Person><Name><First>Michael</First><Last>Raheem</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="11" />
719-555-0181<Person><Name><First>Ovidiu</First><Middle>V</Middle><Last>Cracium</Last></Name><Email>[email protected]</Email></Person></row>
<row>
I feel this xml output is not like the regular xml output. Do you know why it is diffrent from the regular xml xml output? Please comment on this matter.
Thanks,
Scott Chang
What do you mean by regular xml document? Are you referring to fact that its missing a root element? if yes it can be added as below
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "text()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH('ElementName'),ROOT('RootName');
replace ElementName and RootName with whatever name you need to set for element as well as the root element
Please Mark This As Answer if it solved your issue
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"Cut" an element out of XML?

Folks,
Please does anyone know a shortcut to "snip out" XML elements as serialized XML?
The scenario is: We're SAX parsing a potentially very large (I guess upto maybe 200 MB) XML document. The data ("features") therein will be edited by the user in a third party GIS application... and then I need to quickly detect which "feature" elements have changed.
I need to turn the modified features back into XML and send them back to the server, which updates the database. Currently the users have to manually mark which features have been modified and which have been deleted... a process which is subject to human error (and there have been some doozies, apparently).
So... I'm trying to knutt-out a practical way to detect: "Has this feature been modified (or deleted).
My thought was to calculate a hash (SHA1, MD5, or maybe just CRC32) of the serialized XML which represents the feature (both geometry and attributes) before and after... if they're different the feature has been modified. If the feature (identified by a unique id) is missing from the after shot then obviously it's been deleted.
So... My question is: does anybody know a cheats way to get the XML-string for an element from a SAX parser? Note that I can't use a DOM (even for one feature) because the largest existing feature has a tad over 500,000,000 points.
My best approach (the obvious one) so far is:
IMPORT XML
foreach feature
1. parse the feature-XML into a model
2. serialize the model to a StringBuffer
3. calculate the hash (or whatever) and store it against the featureId.
EXPORT XML
foreach feature
1. serialize the feature to StringBuffer
2. recalcuate the hash (or whatever)
3. compare the hash.
Does this sound reasonable to you? It sounds slow but simple to me... Got any better ideas?
Note that the third party editor has no "callback hooks" which allow me to handle the "feature modified" events, and whilste I can query and update it's internal database (dBase4 based) via the API, doing so is cumbersome.
I've also looked into timestamps, which appear impossible... atleast I can't imagine how it could be done, short of writing my own dBase driver (which I'm not up for, thanks anyway;-).
No ideas will be rejected... I'll try (almost) anything once.
Cheers all. Keith.
Edited by: corlettk on 16/04/2009 23:55 ~~ Clarity.
PS: It's already past my bedtime... I shall check this post again tomorrow evening (in about 18 hours).
Edited by: corlettk on 16/04/2009 23:56

corlettk wrote:
So... My question is: does anybody know a cheats way to get the XML-string for an element from a SAX parser? Well, obviously there isn't one. At least not when you phrase the question that way. Consider the case where the element in question is the root element: then you need to serialize the whole document.
But you could read up on XMLFilter, which is a useful but little-known tool which works with SAX parsing.

How to read elements in a xml file sent as a string

Hi,
I am new to BPEL and i am working on a requirement where i receive the XML message as a String from an AQ. And I am not able parse the xml to read the individual elements of it. Appreciate your help on this.
The (sample)input message from Q is which i am able to see in the BPEL console:
<BUGINFO_XML>
<XML_MESSAGE>
<?xml version="1.0"?>
<BUGINFO>
<SR_ID>3-29OU7OF</SR_ID>
<OBJECT_TYPE>UPDATE_PREBUG</OBJECT_TYPE>
<RESERVED_BUG_NUM>8221084</RESERVED_BUG_NUM>
<TYPE>Predefect Update</TYPE>
<AUDIENCE>INTERNAL</AUDIENCE>
<COMMENT>TEST activity by Sireesha</COMMENT>
</BUGINFO>
</XML_MESSAGE>
</BUGINFO_XML>
and the corresponding xsd file is:
<schema targetNamespace="http://xmlns.oracle.com/xdb/ORIONCC"
xmlns="http://www.w3.org/2001/XMLSchema"
xmlns:ORIONCC="http://xmlns.oracle.com/xdb/ORIONCC"
elementFormDefault="unqualified" attributeFormDefault="qualified">
<complexType name="BUGINFO_XML">
<sequence>
<element name="XML_MESSAGE" type="string" nillable="true" minOccurs="0"/>
</sequence>
</complexType>
<element name="BUGINFO_XML" type="ORIONCC:BUGINFO_XML" />
</schema>
i have created a variable(called VariableXML) of element type of the above xsd type({http://xmlns.oracle.com/xdb/ORIONCC}BUGINFO_XML) and using ora:parseEscapedXML method, i copied the input data to this variable and i can see the data copied fine to this variable, but after that i am not able to traverse to the individual element of it say i want the value of SR_ID which i am not able to get.
<VariableXML>
<BUGINFO_XML>
<SR_ID>3-29OU7OF</SR_ID>
<OBJECT_TYPE>UPDATE_PREBUG</OBJECT_TYPE>
<RESERVED_BUG_NUM>8221084</RESERVED_BUG_NUM>
<TYPE>Predefect Update</TYPE>
<AUDIENCE>INTERNAL</AUDIENCE>
<COMMENT>TEST activity by Sireesha</COMMENT>
</BUGINFO_XML>
</VariableXML>
When i see the structure of this variable in the Assign activity i can see only up to '/ns2:BUGINFO_XML/XML_MESSAGE' but not the individual elements.
Please let me know how can i parse this xml to read the elements of it.
I am using jdev 11.1.1.4 and weblogic 10.3
Thanks,
Sireesha
Edited by: user12217808 on Jul 27, 2012 7:10 AM

Thanks for replying Tarak,
I have taken the XML generated by VariableXML variable and generated a XSD out of it and that looks like below.
<?xml version="1.0" encoding="windows-1252" ?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://www.example.org"
targetNamespace="http://www.example.org"
elementFormDefault="qualified">
<xsd:element name="BUGINFO_XML">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="SR_ID" type="xsd:string"/>
<xsd:element name="OBJECT_TYPE" type="xsd:string"/>
<xsd:element name="RESERVED_BUG_NUM" type="xsd:integer"/>
<xsd:element name="TYPE" type="xsd:string"/>
<xsd:element name="AUDIENCE" type="xsd:string"/>
<xsd:element name="COMMENT" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
Then I have created a variable called VariableBugInfo of this element type ({http://www.example.org}BUGINFO_XML) and tried parsing it as below.
<assign name = 'Assign2'>
<copy>
<from expression="oraext:parseXML(bpws:getVariableData('VariableXML','/ns2:BUGINFO_XML'))"/>
<to variable="VariableBugInfo" query="/ns4:BUGINFO_XML"/>
</copy>
</assign>
then i got the below error in the bpel console when im testing my bpel process.
The following exception occurred while attempting to execute operation copy at line 118
<?xml-stylesheet href="chrome://global/locale/intl.css" type="text/css"?>
-<parsererror>
XML Parsing Error: junk after document element
Location: http://slce26vm164.us.oracle.com:7001/em/ai/sca/share/audit/nfdg/displayInstance.jsp?locatorobjkey=Farm_mosbpelmosbpelsoa_server1soa-infra&instanceid=bpel%3A70555
Line Number 7, Column 1:
<sourcetext>
<root class="javax.xml.xpath.XPathExpressionException">internal xpath error<stack><f>oracle.xml.xpath.JXPathExpression.evaluate#242</f><f>com.collaxa.cube.xml.xpath.BPELXPathUtil.evaluate#240</f><f>com.collaxa.cube.engine.ext.bpel.common.BPELWMPHelper.evalFromValue#339</f><f>com.collaxa.cube.engine.ext.bpel.v1.wmp.BPEL1AssignWMP.__executeStatements#137</f><f>com.collaxa.cube.engine.ext.bpel.common.wmp.BaseBPELActivityWMP.perform#158</f><f>com.collaxa.cube.engine.CubeEngine._performActivity#2463</f><f>com.collaxa.cube.engine.CubeEngine.performActivity#2334</f><f>com.collaxa.cube.engine.CubeEngine.handleWorkItem#1115</f><f>com.collaxa.cube.engine.dispatch.message.instance.PerformMessageHandler.handleLocal#73</f><f>com.collaxa.cube.engine.dispatch.DispatchHelper.handleLocalMessage#220</f><f>com.collaxa.cube.engine.dispatch.DispatchHelper.sendMemory#328</f><f>com.collaxa.cube.engine.CubeEngine.endRequest#4350</f><f>com.collaxa.cube.engine.CubeEngine.endRequest#4281</f><f>com.collaxa.cube.engine.CubeEngine.createAndInvoke#679</f><f>com.collaxa.cube.engine.delivery.DeliveryService.handleInvoke#654</f><f>com.collaxa.cube.engine.ejb.impl.CubeDeliveryBean.handleInvoke#293</f><f>...</f></stack></root>
^
</sourcetext>
</parsererror>
but when i tried a normal copy from VariableXML BUGINFO to VariableBugInfo as below, i am not getting any error but its not actually copying the contents to individual tags, because after this Assign i created a simple string variable(objTypeVar) and when i tried to copy TYPE element value to it, it says 'The result is empty for the XPath expression : "/ns4:BUGINFO_XML/ns4:TYPE".'
<assign name="Assign2">
<copy>
<from variable="VariableXML" query="/ns2:BUGINFO_XML"/>
<to variable="VariableBugInfo" query="/ns4:BUGINFO_XML"/>
</copy>
</assign>
<assign name="Assign3">
<copy>
<from variable="VariableBugInfo"
query="/ns4:BUGINFO_XML/ns4:TYPE"/>
<to variable="objTypeVar"/>
</copy>
</assign>
Result in console for VariableBugInfo for Assign2:
<VariableBugInfo>
<BUGINFO_XML>
<SR_ID>3-29OU7OF</SR_ID>
<OBJECT_TYPE>UPDATE_PREBUG</OBJECT_TYPE>
<RESERVED_BUG_NUM>8221084</RESERVED_BUG_NUM>
<TYPE>Predefect Update</TYPE>
<AUDIENCE>INTERNAL</AUDIENCE>
<COMMENT>TEST activity by Sireesha</COMMENT>
</BUGINFO_XML>
</VariableBugInfo>
For Assign 3:
Error in evaluate <from> expression at line "141". The result is empty for the XPath expression : "/ns4:BUGINFO_XML/ns4:TYPE".
I feel there is something i am missing in the XSD and the target namespace which is causing the issue. I am not sure what i should provide in the target namesapce in the new xsd which i created based on the value of VariableXML , so that it actually parses the xml and copies exact elements of it.
Please let me know if i am doing something wrong anywhere.
Thanks,
Sireesha

"The stylesheet does not contain a document element" error

Hi,
I'm using Hyperion Financial Management 11.1.1.3
I successfully created intercompany transactions but when I select the "auto match" to perform the matching process, the running task page ensure that the process is completed successfully. However, when I press "log" I found the following error:
Error Number:-2147467259
Error Description:The stylesheet does not contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document.
Error Source:msxml6.dll
Page On which Error Occurred:/hfm/Administration/ShowRunningTaskLog.asp
My environment is win server 2003 on a VM and EPM 11.1.1.3
Thank you and best regards,
Ahmed.

Hi taku,
Yes I've solved my issue.
Firstly, make sure that the entities and accounts used in the Intercompany Transaction are allowed for ICP in the metadata file by setting the attribute "IsICP=Y" to yes.
Then, after you press the "Match" button, wait until the process finished and don't open the log. Just close the running task page, after the status showed that it is completed, and open the "process IC transactions" page again you will find the square sign becomes green which means that the transactions are matched.
I followed the following example on Oracle by Example [http://www.oracle.com/technetwork/middleware/financial-management/tutorials/mictrans-094190.html?ssSourceSiteId=otncn]
It's about "Managing Intercompany Transactions in Financial Management".
I wish you can solve your issue soon.
Best wishes,
Ahmed.

How to update/change the value of elements in an xml file?

Hi Everyone,
Could any one of u tell me how to update the value of elements in an XML file, using java? The reason is i want to use an XML file as a data source (i.e. more or less like a database), without using any RDBMS, for simple applications such as to read a record and update the record. By the way, my XML file will have only one record, such as the current weather information, with fields such as temperature, humdity etc. for 1 city only.
Thanks in advance.

Here is a solution how to check a particular value or element name in an xml and update the changes e to an xml.
Sample.xml
<URLConstructor>
<application name="cp_outage">
<resource>hello</resource>
<value>val</value>
</application>
<application name="cp_outage">
<resource>hello</resource>
<value>val</value>
</application>
</URLConstructor>
XMLWriter.java
package com;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.jdom.Document;
import org.jdom.Element;
import org.jdom.JDOMException;
import org.jdom.input.DOMBuilder;
import org.jdom.output.XMLOutputter;
// used for printing
import org.apache.xml.serialize.XMLSerializer;
import org.jdom.output.XMLOutputter;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.util.Iterator;
import java.util.List;
class XMLWriter{
public void update(File fileName)
try {
          DOMBuilder domBuilder=new DOMBuilder();
          Document doc=domBuilder.build(fileName);
          Element element=doc.getRootElement();
          getChildren(element);
          writeToXML(doc,fileName);
          getChildren(element);
} catch (Exception e) {
e.printStackTrace();
     * @param doc
     private void writeToXML(Document document,File filePath)
               XMLOutputter xmloutputter = new XMLOutputter();
                    try
                         FileOutputStream fileOutputStream = new FileOutputStream(filePath);
                         xmloutputter.output(document, fileOutputStream);
                         fileOutputStream.close();
                    catch (FileNotFoundException e)
                         e.printStackTrace();
                    catch (IOException e)
                         e.printStackTrace();
     public void getChildren(Element element)
                    if(!element.hasChildren())
                         return;
                    List childrenList = element.getChildren();
                    Iterator itr=childrenList.iterator();
                    while(itr.hasNext())
                         Element childElement=(Element) itr.next();
                         if(childElement.hasChildren())
                                   getChildren(childElement);
//                                   System.out.println("Name "+childElement.getName());
//                                   System.out.println("Value "+childElement.getText());
                                   if(childElement.getText().equals("hello") || (childElement.getName().equals("resource")))
                                        updateInfo(childElement,"New_Resource","AddedText");
     * @param childElement
     * @param string
     * @param string2
     private void updateInfo(Element element, String elementName, String value)
          element.setName(elementName);
          element.setText(value);
static public void main(String[] args)
XMLWriter xmlWriter=new XMLWriter();
xmlWriter.update(new File("c:/sample.xml"));
After execution the file will be changed to
<URLConstructor>
<application name="cp_outage">
<New_Resource>AddedText</New_Resource>
<value>val</value>
</application>
<application name="cp_outage">
<New_Resource>AddedText</New_Resource>
<value>val</value>
</application>
</URLConstructor>
Regards,
Maheswar

No root element found in xml

I am facing a problem when i am trying to use TOAD. Its giving me an error like
NO ROOT ELEMENT FOUND IN XML. Can someone help me in corrcting this Error ?
Regards,
Chandra deep

NO ROOT ELEMENT FOUND IN XML. Can someone help me in
corrcting this Error ? That means the XML document is either missing the surrounding <element> ... </element> pair or has more than one pair at the base level of the document. Resolve that and you are done.
Now ... given that I am probably 4,000+ km away from you and can not see your screen, please look at your question and ask yourself whether you have given sufficient information for troubleshooting. <g>

How do I change alphabetical element listing in xml to nested xml using xslt?

Have an 'Bus Card Request' indd form exported to fillable form pdf (reader enabled etc). Have 'Bus Card Template' indd to receive the BC data from the returned filled pdf form.
The tags & structure are identical on both indd docs.
The xml exported from the pdf discards the structure (nesting) and provides all the elements in alphabetical order.
I am a novice learning how to make an xslt that will transform the alphabetical listing back to the nested structure.
I want to turn this:
<?xml version="1.0" encoding="UTF-8"?>
<fields xmlns:xfdf="http://ns.adobe.com/xfdf-transition/">
<Address>1234 Take Wing</Address>
<Cell_Number>619.321.6878</Cell_Number>
<City>San Diego</City>
<Clin_Sup_Lic_Number>SL00267</Clin_Sup_Lic_Number>
<Clinical_Supervisor_Name>Jarmal Hincks</Clinical_Supervisor_Name>
<ComboBox2 xfdf:original="Combo Box 2">sdyouthservices.org</ComboBox2>
<Date_Signed_Loc_Dir>9/29/2014a</Date_Signed_Loc_Dir>
<Date_Signed_Orig>9/29/2014</Date_Signed_Orig>
<Degree>MA</Degree>
<Email_Address>s.reeves</Email_Address>
<Extension>1234</Extension>
<Fax_Number>619.123.9876</Fax_Number>
<Intern_Number>XX20</Intern_Number>
<License_Number>YY20</License_Number>
<Location>Point Loma Campus</Location>
<Name>Steve Reeves</Name>
<Notes_and_Comments>Make it a super duper bus card</Notes_and_Comments>
<Program>Learning Curve</Program>
<State>CA</State>
<Telephone_Number>619.123.4567</Telephone_Number>
<TextField27 xfdf:original="Text Field 27">www.sdyouthservices.org</TextField27>
<Title>Superman</Title>
<Zip>99999</Zip>
</fields>
into this:
<BC_Order>
<Group_Name>
   <Name></Name>
   <Degree></Degree>
    <Title></Title>
   <Intern_Number></Intern_Number>
   <License_Number></License_Number>
</Group_Name>
<Group_Location>
   <Location></Location>
 <Program></Program>
 <Address></Address> 
<City></City>
<State></State>
<Zip></Zip>
</Group_Location>
<Group_Phone>
<Telephone_Number></Telephone_Number>
<Extension></Extension> 
<Fax_Number></Fax_Number>
<Cell_Number></Cell_Number>
</Group_Phone>
<Group_Email-WS>
<Email_Address></Email_Address>
<eMail_Host></eMail_Host> 
<Website></Website> 
<Clinical_Supervisor_Name></Clinical_Supervisor_Name>
<Clin_Sup_Lic_Number></Clin_Sup_Lic_Number>
</Group_Email-WS>
</BC_Order>
Is this xslt code on the right track?
(i've left out the usual header stuff)
<BC_Order>
<Group_Name>
<Name><xsl:value-of select="Name"/></Name>
<Degree><xsl:value-of select="Degree"/></Degree>
<Title><xsl:value-of select="Title"/></Title>
<Intern_Number><xsl:value-of select="Intern_Number"/></Intern_Number>
<License_Number><xsl:value-of select="License_Number"/></License_Number>
</Group_Name>
</BC_Order>
I'm just trying to figure out what the words are to make nesting occur in the resultant xml so it will match the nesting order in the Bus Card input template.
Thanks!
Paul

Hi Paul,
Is this xslt code on the right track?
Yes, no...
The root element in the XML from the form is "fields" without the quote marks. So the XSL needs the full path to the elements to include the "fields" root element. The select would therefore be "<xsl:value-of select="fields/Name" />"
Note that because I like seeing the XML with line breaks, the "<xsl:text>
</xsl:text>" precedes each line. Without that, one gets a long string. But it isn't really needed and there are other means of accomplishing it.
I think the below will do what you need.
Take care, Mike
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:text>
</xsl:text><BC_Order>
<xsl:text>
</xsl:text><Group_Name>
<xsl:text>
</xsl:text><Name><xsl:value-of select="fields/Name" /></Name>
<xsl:text>
</xsl:text><Degree><xsl:value-of select="fields/Degree" /></Degree>
<xsl:text>
</xsl:text><Title><xsl:value-of select="fields/Title" /></Title>
<xsl:text>
</xsl:text><Intern_Number><xsl:value-of select="fields/Intern_Number" /></Intern_Number>
<xsl:text>
</xsl:text><License_Number><xsl:value-of select="fields/License_Number" /></License_Number>
<xsl:text>
</xsl:text></Group_Name>
<xsl:text>
</xsl:text><Group_Location>
<xsl:text>
</xsl:text><Location><xsl:value-of select="fields/Location" /></Location>
<xsl:text>
</xsl:text><Program><xsl:value-of select="fields/Program" /></Program>
<xsl:text>
</xsl:text><Address><xsl:value-of select="fields/Address" /></Address>
<xsl:text>
</xsl:text><City><xsl:value-of select="fields/City" /></City>
<xsl:text>
</xsl:text><State><xsl:value-of select="fields/State" /></State>
<xsl:text>
</xsl:text><Zip><xsl:value-of select="fields/Zip" /></Zip>
<xsl:text>
</xsl:text></Group_Location>
<xsl:text>
</xsl:text><Group_Phone>
<xsl:text>
</xsl:text><Telephone_Number><xsl:value-of select="fields/Telephone_Number" /></Telephone_Number>
<xsl:text>
</xsl:text><Extension><xsl:value-of select="fields/Extension" /></Extension>
<xsl:text>
</xsl:text><Fax_Number><xsl:value-of select="fields/Fax_Number" /></Fax_Number>
<xsl:text>
</xsl:text><Cell_Number><xsl:value-of select="fields/Cell_Number" /></Cell_Number>
<xsl:text>
</xsl:text></Group_Phone>
<xsl:text>
</xsl:text><Group_Email-WS>
<xsl:text>
</xsl:text><Email_Address><xsl:value-of select="fields/Email_Address" /></Email_Address>
<xsl:text>
</xsl:text><eMail_Host><xsl:value-of select="fields/ComboBox2" /></eMail_Host>
<xsl:text>
</xsl:text><Website><xsl:value-of select="fields/TextField27" /></Website>
<xsl:text>
</xsl:text><Clinical_Supervisor_Name><xsl:value-of select="fields/Clinical_Supervisor_Name" /></Clinical_Supervisor_Name>
<xsl:text>
</xsl:text><Clin_Sup_Lic_Number><xsl:value-of select="fields/Clin_Sup_Lic_Number" /></Clin_Sup_Lic_Number>
<xsl:text>
</xsl:text></Group_Email-WS>
<xsl:text>
</xsl:text></BC_Order>
</xsl:template>
</xsl:stylesheet>

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