Ignoring extra characters...

Question

Hi,
I'm creating a method where when you input a number in the String it ignores the extra characters.
For example...if i enter "-4.414E-80EEE", i should get "-4.414E-80", but i get "-41480.0".
Here's my code:
   public double convertDouble1 (String value)
       for(int i = 0; i < value.length(); i++)
           while (true) {
               try {
                   int number = Integer.parseInt(value);
                   break;
                catch (NumberFormatException ignore) {
                    value = value.replaceAll("[^0-9]"," ");
        return Double.parseDouble(value);
    }Anyone know where i'm going wrong?

Answer 1

LevelSix wrote:
For example...if i enter "-4.414E-80EEE", i should get "-4.414E-80", but i get "-41480.0".
Here's my code:
   public double convertDouble1 (String value)
for(int i = 0; i < value.length(); i++)
while (true) {
try {
int number = Integer.parseInt(value);
break;
catch (NumberFormatException ignore) {
value = value.replaceAll("[^0-9]"," ");
return Double.parseDouble(value);
>
Then I said:
Come on dude, think about this for a second.
look at that replaceAll() call, what is it doing.
hint: print out value each timeCounting from 0 to 9.No it is not. It is replacing every character that is not 0,1, 2, 3,4,5,6,7,8 or 9 with a space.
Can you explain to me why that's wrong?1) I don't think that is what you really want to do.
what about the decimal point?
what about the E separating the mantissa from the exponent?
What about the minus sign?
2) The while loop never ends.
How did you ever get the results you claimed from the code you posted.
When I ran it i just ended up with an inifinte loop.
3) For some you run the never ending while loop multiple times, once for each character in the string.
4) If you had printed of value each time as I suggested you would have seen what was going on.
Edited by: johndjr on Apr 14, 2009 2:16 PM
forgot about the minus sign (probably a bunch of other stuff as well)