Illustrator Bevel, help me understand

Hi all,
Coming from photoshop background and are having some real fun trying to work out the 3D/Extrude & Bevel command in Illustrator CS3.
Now I have a filled circle and simply want to get a highlights and shadows type edge on it, something like I would achieve with the bevel and emboss style command in Photoshop CS3.
Could someone please explain how to best do this sort of thing in Illustrator.
Any help would be great

Here are some screenshots showing in particular the lighting effects that can be added to have multiple light sources which can be placed i different orbital positions to vary the effect.
This one below is create by place a duplicate on top of the above 3D effect Circle and giving the duplicate a straight forward gradient fill and lowering the opacity. I removed the 3D effect from the duplicate Circle.

Similar Messages

Will an Illustrator class help me understand Photoshop?

Hi there,
I realize I may have put the cart before the horse a bit, but I recently bought a copy of Photoshop, in hopes of learning how to use it to explore digital art and graphic creation.
I know there are a ton of tutorials online, but I was considering taking a couple of inexpensive courses at community college too. The school offers courses in Beginners Photoshop, but the next one is not until March.
They do have a course on Illustrator though, that begins next week.
I am wondering if it would be worthwhile to take that course, and if I could feasibly translate anything I learn in that class into Photoshop. I figured at the least it would give me more of a feel for the Adobe programs in general, since I can't imagine their interfaces would be too terribly different.
Thanks

All Adobe programs have similiarites and I firmly believe that learning one will help you learn another. Not only that, but Photoshop and Illustrator work well together, so it could be very useful for you to know both.

Saving as DWG in Illustrator CS2 - help!!!

I'm trying to save a file as a .dwg or .dxf in Illustrator CS2. Everytime I save, it creates two files, a .bmp or .jpg and the .dwg or .dxf
Does this always happen, the two file situation? Because then the files can't be separated from each other if you intend to open them. I need to send these to part of our parent corporation, and it was my understanding that it shouldn't be two documents. I'd never saved as a .dwg or .dxf before, so this is new to me, I'm not sure what is considered "normal."
Can someone help me understand what's going on here?

It's normal in case your Illustrator file contains rasterized objects or objects which are rasterized during the export process.
You can choose which raster format to use in the Auto CAD export options (in Illustrator 14 it's .png or .jpg). Any raster object in the Illustrator file is separately exported to the same folder the .dwg file is exported to. When you reopen that .dwg in Illustrator the raster files come in as linked files.
Just send them the whole folder including the .dwg and the raster files.

Error Posting IDOC: need help in understanding the following error

Hi ALL
Can you please, help me understand the following error encountered while the message was trying to post a IDOC.
where SAP_050 is the RFC destination created to post IDOCs
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
- 
- <SAP:Error xmlns:SAP="http://sap.com/xi/XI/Message/30" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" SOAP:mustUnderstand="">
<SAP:Category>XIAdapter</SAP:Category>
<SAP:Code area="IDOC_ADAPTER">ATTRIBUTE_IDOC_RUNTIME</SAP:Code>
<SAP:P1>FM NLS_GET_LANGU_CP_TAB: Could not determine code page with SAP_050 Operation successfully executed FM NLS_GET_LANGU_CP_TAB</SAP:P1>
<SAP:P2 />
<SAP:P3 />
<SAP:P4 />
<SAP:AdditionalText />
<SAP:ApplicationFaultMessage namespace="" />
<SAP:Stack>Error: FM NLS_GET_LANGU_CP_TAB: Could not determine code page with SAP_050 Operation successfully executed FM NLS_GET_LANGU_CP_TAB</SAP:Stack>
<SAP:Retry>M</SAP:Retry>
</SAP:Error>
Your help is greatly appreciated.............Thank you!

Hi Patrick,
Check the authorizations assigned to the user which you used in the RFC destinations, If there is no enough authorizations then it is not possible to post the idocs.
Also Refer this Note 747322
Regards,
Prakash

E-Rows = NULL and A-Rows=42M? Need help in understanding why.

Hi,
Oracle Standard Edition 11.2.0.3.0 CPU Oct 2012 running on Windows 2008 R2 x64. I am using Oracle 10g syntax for WITH clause as the query will also run on Oracle 10gR2. I do not have a Oracle 10gR2 environment at hand to comment if this behaves the same.
Following query is beyond me. It takes around 2 minutes to return the "computed" result set of 66 rows.
SQL> WITH dat AS
2          (SELECT 723677 vid,
3                  243668 fid,
4                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
5                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
6             FROM DUAL
7           UNION ALL
8           SELECT 721850,
9                  243668,
10                  TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
11                  TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
12             FROM DUAL
13           UNION ALL
14           SELECT 723738,
15                  243668,
16                  TO_DATE ('16.03.2013', 'dd.mm.yyyy'),
17                  TO_DATE (' 04.04.2013', 'dd.mm.yyyy')
18             FROM DUAL)
19      SELECT /*+ GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
20        FROM dat
21 CONNECT BY LEVEL <= maxdt - mindt + 1
22 order by fid, vid, dtshow;
66 rows selected.
SQL>
SQL> SELECT * FROM TABLE (DBMS_XPLAN.display_cursor (NULL, NULL, 'ALLSTATS LAST'));
PLAN_TABLE_OUTPUT
SQL_ID 9c4vma4mds6zk, child number 0
WITH dat AS         (SELECT 723677 vid,                 243668 fid,
            TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt            FROM DUAL
UNION ALL          SELECT 721850,                 243668,
   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),                 TO_DATE ('
22.03.2013', 'dd.mm.yyyy')            FROM DUAL          UNION ALL
    SELECT 723738,                 243668,                 TO_DATE
('16.03.2013', 'dd.mm.yyyy'),                 TO_DATE (' 04.04.2013',
'dd.mm.yyyy')            FROM DUAL)     SELECT /*+
GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
    FROM dat CONNECT BY LEVEL <= maxdt - mindt + 1 order by fid, vid,
dtshow
Plan hash value: 1865145249
| Id | Operation                              | Name | Starts | E-Rows | A-Rows |   A-Time   | OMem | 1Mem | Used-Mem |
|   0 | SELECT STATEMENT                       |      |      1 |        |     66 |00:01:54.64 |       |       |          |
|   1 | SORT UNIQUE                           |      |      1 |      3 |     66 |00:01:54.64 | 6144 | 6144 | 6144 (0)|
|   2 |   CONNECT BY WITHOUT FILTERING (UNIQUE)|      |      1 |        |     42M|00:01:04.00 |       |       |          |
|   3 |    VIEW                                |      |      1 |      3 |      3 |00:00:00.01 |       |       |          |
|   4 |     UNION-ALL                          |      |      1 |        |      3 |00:00:00.01 |       |       |          |
|   5 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   6 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   7 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
--------------------------------------------------------------------------------------------------------------------------If I take out one of the UNION queries, the query returns in under 1 second.
SQL> WITH dat AS
2          (SELECT 723677 vid,
3                  243668 fid,
4                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
5                  TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
6             FROM DUAL
7           UNION ALL
8           SELECT 721850,
9                  243668,
10                  TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
11                  TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
12             FROM DUAL)
13      SELECT /*+ GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
14        FROM dat
15 CONNECT BY LEVEL <= maxdt - mindt + 1
16 order by fid, vid, dtshow;
46 rows selected.
SQL>
SQL> SELECT * FROM TABLE (DBMS_XPLAN.display_cursor (NULL, NULL, 'ALLSTATS LAST'));
PLAN_TABLE_OUTPUT
SQL_ID 1d2f62uy0521p, child number 0
WITH dat AS         (SELECT 723677 vid,                 243668 fid,
            TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt            FROM DUAL
UNION ALL          SELECT 721850,                 243668,
   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),                 TO_DATE ('
22.03.2013', 'dd.mm.yyyy')            FROM DUAL)     SELECT /*+
GATHER_PLAN_STATISTICS */ DISTINCT vid, fid, mindt - 1 + LEVEL dtshow
    FROM dat CONNECT BY LEVEL <= maxdt - mindt + 1 order by fid, vid,
dtshow
Plan hash value: 2232696677
| Id | Operation                              | Name | Starts | E-Rows | A-Rows |   A-Time   | OMem | 1Mem | Used-Mem |
|   0 | SELECT STATEMENT                       |      |      1 |        |     46 |00:00:00.01 |       |       |          |
|   1 | SORT UNIQUE                           |      |      1 |      2 |     46 |00:00:00.01 | 4096 | 4096 | 4096 (0)|
|   2 |   CONNECT BY WITHOUT FILTERING (UNIQUE)|      |      1 |        |     90 |00:00:00.01 |       |       |          |
|   3 |    VIEW                                |      |      1 |      2 |      2 |00:00:00.01 |       |       |          |
|   4 |     UNION-ALL                          |      |      1 |        |      2 |00:00:00.01 |       |       |          |
|   5 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
|   6 |      FAST DUAL                         |      |      1 |      1 |      1 |00:00:00.01 |       |       |          |
26 rows selected.What I cannot understand is why the E-Rows is NULL for "CONNECT BY WITHOUT FILTERING (UNIQUE)" step and A-Rows shoots up to 42M for first case. The behaviour is the same for any number of UNION queries above two.
Can anyone please help me understand this and aid in tuning this accordingly? Also, I would be happy to know if there are better ways to generate the missing date range.
Regards,
Satish

May be, this?
WITH dat AS
            (SELECT 723677 vid,
                    243668 fid,
                    TO_DATE ('06.03.2013', 'dd.mm.yyyy') mindt,
                    TO_DATE ('06.03.2013', 'dd.mm.yyyy') maxdt
               FROM DUAL
             UNION ALL
             SELECT 721850,
                    243668,
                   TO_DATE ('06.02.2013', 'dd.mm.yyyy'),
                   TO_DATE (' 22.03.2013', 'dd.mm.yyyy')
              FROM DUAL
            UNION ALL
            SELECT 723738,
                   243668,
                   TO_DATE ('16.03.2013', 'dd.mm.yyyy'),
                   TO_DATE (' 04.04.2013', 'dd.mm.yyyy')
              FROM DUAL)
       SELECT vid, fid, mindt - 1 + LEVEL dtshow
         FROM dat
CONNECT BY LEVEL <= maxdt - mindt + 1
      and prior vid = vid
      and prior fid = fid
      and prior sys_guid() is not null
order by fid, vid, dtshow;
66 rows selected.
Elapsed: 00:00:00.03

Can you help me understand the use of the word POSITION in TR and CFM?

Hi,
I am trying to have a view of typical BI reports in TR and TM/CFM so through my research I came to the following link:.
http://help.sap.com/saphelp_nw2004s/helpdata/en/62/08193c38f98e1ce10000000a11405a/frameset.htm
My problem on this link and other postings on this site seem to be the same. Can you help me understand the use of the word POSITIONS in these context:
1. Our client has asked for financial transaction reports in BW, such as position of Borrowings, Investments and Hedge Operations (TM data).
2. I have a requirement on, some reports related to Money Market (Fixed Term Deposits, Deposits at Notice) something on FSCM-Treasury and Risk Manager. These reports will be similar to that of Loans, i.e. Position statement, flow statement, etc.
3. The set of position values for a single position or a limited amount of positions can be reported by transactions TPM12 and TPM13 in R3.
4. 0CFM_C10 (Financial Positions Cube)
Do you have some simple report outputs to help clarify how the word POSITION is used in such environments?
Thanks
Edited by: AmandaBaah on Feb 15, 2010 4:39 PM

If I future buy 10 shares in company at £1 per share - at the end of the day my potential value is £10
The next day the shares drop tp £0.9 per share - I have a negative position - my shares are only worth £9
I haven;t bought them yet - but I have a negative position - ie if things stayed as they are - I am going to realise (ie end up with) a loss
Now you can use this for loans and foreign exchange banks as well...

Need help in understanding why so many gets and I/O

Hi there,
I have a sql file somewhat similar in structure to below:
delete from table emp;-- changed to Truncate table emp;
delete from table dept;--changed to Truncate table dept;
insert into emp values() select a,b,c from temp_emp,temp_dept where temp_emp.id=temp_dept.emp_id
update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);
commit --only at the end
the above file takes about 9-10 hrs to complete its operation. and
the values from v$sql for the statement
update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);
are as below:
SHARABLE_MEM PERSISTENT_MEM RUNTIME_MEM SORTS LOADED_VERSIONS OPEN_VERSIONS USERS_OPENING FETCHES EXECUTIONS PX_SERVERS_EXECUTIONS END_OF_FETCH_COUNT USERS_EXECUTING LOADS FIRST_LOAD_TIME INVALIDATIONS PARSE_CALLS DISK_READS DIRECT_WRITES BUFFER_GETS APPLICATION_WAIT_TIME CONCURRENCY_WAIT_TIME CLUSTER_WAIT_TIME USER_IO_WAIT_TIME PLSQL_EXEC_TIME JAVA_EXEC_TIME ROWS_PROCESSED COMMAND_TYPE OPTIMIZER_MODE OPTIMIZER_COST OPTIMIZER_ENV OPTIMIZER_ENV_HASH_VALUE PARSING_USER_ID PARSING_SCHEMA_ID PARSING_SCHEMA_NAME KEPT_VERSIONS ADDRESS TYPE_CHK_HEAP HASH_VALUE OLD_HASH_VALUE PLAN_HASH_VALUE CHILD_NUMBER SERVICE SERVICE_HASH MODULE MODULE_HASH ACTION ACTION_HASH SERIALIZABLE_ABORTS OUTLINE_CATEGORY CPU_TIME ELAPSED_TIME OUTLINE_SID CHILD_ADDRESS SQLTYPE REMOTE OBJECT_STATUS LITERAL_HASH_VALUE LAST_LOAD_TIME IS_OBSOLETE CHILD_LATCH SQL_PROFILE PROGRAM_ID PROGRAM_LINE# EXACT_MATCHING_SIGNATURE FORCE_MATCHING_SIGNATURE LAST_ACTIVE_TIME BIND_DATA TYPECHECK_MEM
18965 8760 7880 0 1 0 0 0 2 0 2 0 2 2011-05-10/21:16:44 1 2 163270378 0 164295929 0 509739 0 3215857850 0 0 20142 6 ALL_ROWS 656 E289FB89A4E49800CE001000AEF9E3E2CFFA331056414155519421105555551545555558591555449665851D5511058555155511152552455580588055A1454A8E0950402000002000000000010000100050000002002080007D000000000002C06566001010000080830F400000E032330000000001404A8E09504646262040262320030020003020A000A5A000 4279923421 50 50 APPS 0 00000003CBE5EF50 00 1866523305 816672812 1937724149 0 SYS$USERS 0 01@</my.sql -2038272289 -265190056 0 9468268067 10420092918 00000003E8593000 6 N VALID 0 2011-05-11/10:23:45 N 5 0 0 1.57848E+19 1.57848E+19 5/12/2011 4:39 0
1) how do i re-write this legacy script? and what should be done to improve performance?
2) Should i use PL/sql to re-write it?
3) Also help in understanding why a simple update statement is doing so many buffer gets and reading , Is this Read consistency Trap as i'm not committing anywhere in between or it is actually doing so much of work.
(assume dept table has cols emp_name and emp_id also)

update emp set emp_name=(select emp_name from dept where emp.id=dept.emp_id);I guess that these are masked table names ? Nobody would have emp_name in a dept table.
Can you re-format the output, using "code" tags ( [ or { }
Hemant K Chitale
Edited by: Hemant K Chitale on May 12, 2011 12:44 PM

Why is my page set up drop down different from your illustration in help for printing background

''duplicate - https://support.mozilla.com/en-US/questions/830795''
The page set up drop down menu looks nothing like the illustration in help. It does not include a box to check for "print background. How do I print background

first, does it sound like I set it up correctly from what I wrote?
Yes, all sounds correct.
Second, I heard that adding a b/g AX to the network will slow everything down to b/g speeds but I have also read that simply using B/G AX's to add speakers by joining the network will not slow down the N network....which is it?
The b/g AX devices will not slow down the network unless they are actively streaming AirTunes. Even then, audio streaming does not require a great deal of bandwidth, so for the most part, the effect would be negligible. Don't worry about it.
Is my network slowed down to b/g speeds because of my speaker set up or not?
The speed on your network will depend on a number of factors..are you downloading something while copying something else? Are you simply browsing? How far is the computer from the closest wireless access point?
You can check your current available bandwidth on your local network by doing the following:
Hold down the option key on your Mac while you click on the fan shaped AirPort icon at the top of the screen. Look for the Transmit Rate number.
"g" wireless = 54 Mbps
What do you see?
Oh, and by the way, I don't know if this matters, but while the time capsule serves as the main base station, it is in bridge mode because it is plugged into a 2wire gateway router.
If the Time Capsule is in bridge mode, it cannot act as the main base station. If you want, you could think of it that way if you are using the wireless on the Time Capsule as your preferred network, but the Time Capsule is not the "main" router.
Message was edited by: Bob Timmons

Duplicate partitions, need help to understand and fix.

So I was looking for a USB that I plugged in and went into /media/usbhd-sdb4/miles and realized all its contents was from my home directory.
So I created a random file in my home directory to see if it would also update /media/usbhd-sdb4/miles , and it did.
Can someone help me understand what is happening?
Also if I can fuse sdb4 and sdb2 as one, and partition it as my home directory without losing its contents?
Below is some information that I think would be helpful.
Thank you.
[miles]> cd /media/usbhd-sdb4/
[usbhd-sdb4]> ls -l
total 20
drwx------ 2 root root 16384 May 28 14:16 lost+found
drwx------ 76 miles users 4096 Oct 15 00:42 miles
[usbhd-sdb4]> cd miles
[miles]> pwd
/media/usbhd-sdb4/miles
[miles]>
lsblk
NAME MAJ:MIN RM SIZE RO TYPE MOUNTPOINT
sda 8:0 0 465.8G 0 disk
├─sda1 8:1 0 19.5G 0 part
└─sda2 8:2 0 446.2G 0 part
sdb 8:16 0 465.8G 0 disk
├─sdb1 8:17 0 102M 0 part /media/usbhd-sdb1
├─sdb2 8:18 0 258.9M 0 part [SWAP]
├─sdb3 8:19 0 14.7G 0 part /
└─sdb4 8:20 0 450.8G 0 part /media/usbhd-sdb4
sr0 11:0 1 1024M 0 rom

Check your udev rules...

Need help for understanding the behaviour of these 2 queries....

Hi,
I need your help for understanding the behaviour of following two queries.
The requirement is to repeat the values of the column in a table random no of times.
Eg. A table xyz is like -
create table xyz as
select 'A' || rownum my_col
from all_objects
where rownum < 6;
my_col
A1
A2
A3
A4
A5
I want to repeat each of these values (A1, A2,...A5) multiple times - randomly decide. I have written the following query..
with x as (select my_col, trunc(dbms_random.value(1,6)) repeat from xyz),
y as (select level lvl from dual connect by level < 6)
select my_col, lvl
from x, y
where lvl <= repeat
order by my_col, lvl
It gives output like
my_col lvl
A1     1
A1     3
A1     5
A2     1
A2     3
A2     5
A3     1
A3     3
A3     5
A4     1
A4     3
A4     5
A5     1
A5     3
A5     5
Here in the output, I am not getting rows like
A1     2
A1     4
A2     2
A2     4
Also, it has generated the same set of records for all the values (A1, A2,...,A5).
Now, if I store the randomly-decided value in the table like ---
create table xyz as
select 'A' || rownum my_col, trunc(dbms_random.value(1,6)) repeat
from all_objects
where rownum < 6;
my_col repeat
A1     4
A2     1
A3     5
A4     2
A5     2
And then run the query,
with x as (select my_col, repeat from xyz),
y as (select level lvl from dual connect by level < 6)
select my_col, lvl
from x, y
where lvl <= repeat
order by my_col, lvl
I will get the output, exactly what I want ---
my_col ....lvl
A1     1
A1     2
A1     3
A1     4
A2     1
A3     1
A3     2
A3     3
A3     4
A3     5
A4     1
A4     2
A5     1
A5     2
Why the first approach do not generate such output?
How can I get such a result without storing the repeat values?

If I've understood your requirement, the below will achieve it:
SQL> create table test(test varchar2(10));
Table created.
SQL> insert into test values('&test');
Enter value for test: bob
old   1: insert into test values('&test')
new   1: insert into test values('bob')
1 row created.
SQL> insert into test values('&test');
Enter value for test: terry
old   1: insert into test values('&test')
new   1: insert into test values('terry')
1 row created.
SQL> insert into test values('&test');
Enter value for test: steve
old   1: insert into test values('&test')
new   1: insert into test values('steve')
1 row created.
SQL> insert into test values('&test');
Enter value for test: roger
old   1: insert into test values('&test')
new   1: insert into test values('roger')
1 row created.
SQL> commit;
Commit complete.
SQL> select lpad(test,(ceil(dbms_random.value*10))*length(test),test) from test;
LPAD(TEST,(CEIL(DBMS_RANDOM.VALUE*10))*LENGTH(TEST),TEST)
bobbobbobbobbobbobbobbobbobbob
terryterry
stevestevesteve
rogerrogerrogerrogerrogerrogerrogerrogerrogerYou can alter the value of 10 in the SQL if you want the potential for a higher number of names.
Andy

Need help in understanding FA acquisition via Internal Order

Hi Gurus
I need your help in understanding the FA acquisition via Internal Order. The process we are following is that we create AUC using the AUC asset class and enter that AUC number in the settlement rule while creating IO. Once IO budget is approved, we release the IO. Once GR is completed, we do the Invoice receipt for the PO, followed by settlement of IO against the AUC. Afterwards, we create fixed asset in AS01 and enter this asset number in the settlement rule for the AUC in AIAB and settle the AUC to Fixed asset for the costs.
My question is that during all this process, I don't see the PO information in the AUC record. When I display AUC, under the Enviornment tab, I see the Purchase order link but when I click it, there is nothing in there. The reason could be that we are creating AUC seperatly and not from within the IO where it says create AUC. I am not sure what is the best way for the whole process.
I would be thankful if you can guide me.
Thanks,
Shalu

Hi
Can someone please help me with this issue?
Thanks,
Shalu

Need help in understanding the error ORA-01843: not a valid month - ECX_ACT

Hello All,
We need help in understanding the Transaction Monitor -> Processing Message (error "ORA-01843: not a valid month - ECX_ACTIONS.GET_CONVERTED_DATE").
And how to enable the log for Transaction Monitor -> Processing Logfile.
Actually we are trying to import the Purchase Order XML (OAG) into eBusiness Suite via BPEL Process Manager using the Oracle Applications Adapter. The process is working fine with expected payload until it reaches the XML Gateway Transaction Monitor, where we are getting this error.
thanks
muthu.

Hello All,
We need help in understanding the Transaction Monitor -> Processing Message (error "ORA-01843: not a valid month - ECX_ACTIONS.GET_CONVERTED_DATE").
And how to enable the log for Transaction Monitor -> Processing Logfile.
Actually we are trying to import the Purchase Order XML (OAG) into eBusiness Suite via BPEL Process Manager using the Oracle Applications Adapter. The process is working fine with expected payload until it reaches the XML Gateway Transaction Monitor, where we are getting this error.
thanks
muthu.

HT3529 Can someone help me understand why my iMessage no longer works on my iPad

Can someone help me understand why my iMessage no longer works on my iPad

iOS: Troubleshooting Messages
iOS: Troubleshooting FaceTime and iMessage activation

I try to sync my nano and get: the ipod cant be synced because there is not enough free space to hold all of the items in the items library (need 100MB) - I have a new computer?? can you help me understand this message: what to do?

I try to sync my nano and get: the ipod cant be synced because there is not enough free space to hold all of the items in the items library (need 100MB) - I have a new computer?? can you help me understand this message: what to do?

Hello pryan1012,
What this message means is that you have more music in your itunes library than there is free space in your ipod.
I had this same issue at one time. This is what helped me put my music on the ipod. I used manually manage.
Learn how to sync muisc here.
Hope this helps.
~Julian

Lightroom 5.2 won't open after "successfully installed" - can anybody please help me understand why?

Hi everyone
I've bought and downloaded Adobe Lightroom 5 for a new iMac 27" intel core 5 3,4 GHz. The machine is only three days old and no more updates are to be found when searching for it. However; after the message that "lightroom 5 has successfully been installed" I don't get to open the program. So I never get to the point where I can register the serial number / registration key for purchased product.
I've followed the instructions that comes with Lightroom 5, but no luck. Also tried to uninstall and reinstall.
No secret that I'm total incompetent when it comes to understanding of computers and software....
Hope someone can help me understand what I'm doing wrong, and sugest some good solutions :-)
Thx

I think you may need to uninstall and then start over. There is no installer on the Mac for Lightroom so select it in Applications and send it to the trash. I suggest you download again from a different source. You can use the link below to download the free trial and then validate the software after installation with your product serial number. Ensure you choose your language version and MAC platform from the dropdown list at the top of the page.
After you click download it starts by downloading or updating (replace) the Adobe Download Assistant. You then browse the products and select Photoshop Lightroom 5 to start the installation.
https://www.adobe.com/cfusion/tdrc/index.cfm?product=photoshop_lightroom&promoid&promoid=D TEML

Illustrator Bevel, help me understand

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