Inline Query Sum
hi
i am using 2 inline queries, from both queries am getting values in outer query
i need to find out the sum of amount total.
here is the query
select customer_name,branch, round((revenue)/100000,2) revenue,round(((sum(revenue)- sum(ap_amount))/100000),2) margin, (sum(revenue)- sum(ap_amount))/sum(revenue) as "Margin %" from
(select 'AP' Mod,
fvv.description branch,
glc.segment4 ap_won,
sum(aida.amount) ap_amount
FROM
apps.ap_invoice_distributions_all aida,
apps.ap_invoices_all aia,
apps.fnd_flex_values_vl fvv,
apps.gl_code_combinations glc,
apps.po_vendors pv
WHERE aia.invoice_id = aida.invoice_id
AND aida.dist_code_combination_id = glc.code_combination_id
AND pv.vendor_id = aia.vendor_id
AND aida.set_of_books_id = pv.set_of_books_id
AND aia.set_of_books_id = aida.set_of_books_id
AND aia.set_of_books_id = 2
AND glc.segment4 != '0000000'
AND aia.org_id = aida.org_id
AND aia.org_id = 92
AND aida.posted_flag = 'Y'
AND glc.segment2 = fvv.flex_value
AND fvv.flex_value_set_id = 1008015
AND aida.accounting_date between '01-jun-2010' and '10-jun-2010'
AND aia.invoice_amount != 0
and glc.SEGMENT1=16
group by
fvv.description,
glc.segment4
order by 2)a,
(SELECT
'AR' Mod,
rc.CUSTOMER_NAME customer_name,
rct.interface_header_attribute1 ar_won,
sum(rctl.extended_AMOUNT) revenue,
fvv.description branch1
FROM apps.ra_customer_trx_lines_all rctl,
apps.RA_CUST_TRX_LINE_GL_DIST_ALL rctg,
apps.fnd_flex_values_vl fvv,
apps.ra_customer_trx_all rct,
apps.ra_customers rc,
apps.RA_CUST_TRX_TYPES_ALL rctt,
apps.gl_code_combinations gcc
WHERE rctl.customer_trx_id = rct.customer_trx_id
and rct.BILL_TO_CUSTOMER_ID=rc.CUSTOMER_ID
and rct.CUSTOMER_TRX_ID=rctg.CUSTOMER_TRX_ID
and rctl.CUSTOMER_TRX_LINE_ID=rctg.CUSTOMER_TRX_LINE_ID
and rctt.CUST_TRX_TYPE_ID = rct.CUST_TRX_TYPE_ID
and gcc.CODE_COMBINATION_ID=rctg.CODE_COMBINATION_ID
AND gcc.segment2 = fvv.flex_value
AND fvv.flex_value_set_id = 1008015
and gcc.SEGMENT3 like '5%'
and rctg.ACCOUNT_CLASS='REV'
and rctl.line_type = 'LINE'
and rct.complete_flag='Y'
and rctg.gl_date between '01-jun-2010' and '10-jun-2010'
and rct.ORG_ID=92
group by fvv.description,rct.interface_header_attribute1,rc.CUSTOMER_NAME
order by 2)b
where a.ap_won=b.ar_won
and a.branch = b.branch1
group by branch,revenue,customer_name
order by 2 I need to revenue total,
can you let me know, how to calculate that.
Thanks,
Like this:
select customer_name,branch, round((revenue)/100000,2) revenue,
round(((sum(revenue)- sum(ap_amount))/100000),2) margin,
(sum(revenue)- sum(ap_amount))/sum(revenue) as "Margin %",
SUM(revenue) OVER() tot_Rev from
(select 'AP' Mod,
fvv.description branch,
glc.segment4 ap_won,
sum(aida.amount) ap_amount
FROM
apps.ap_invoice_distributions_all aida,
apps.ap_invoices_all aia,
apps.fnd_flex_values_vl fvv,
apps.gl_code_combinations glc,
apps.po_vendors pv
WHERE aia.invoice_id = aida.invoice_id
AND aida.dist_code_combination_id = glc.code_combination_id
AND pv.vendor_id = aia.vendor_id
AND aida.set_of_books_id = pv.set_of_books_id
AND aia.set_of_books_id = aida.set_of_books_id
AND aia.set_of_books_id = 2
AND glc.segment4 != '0000000'
AND aia.org_id = aida.org_id
AND aia.org_id = 92
AND aida.posted_flag = 'Y'
AND glc.segment2 = fvv.flex_value
AND fvv.flex_value_set_id = 1008015
AND aida.accounting_date between '01-jun-2010' and '10-jun-2010'
AND aia.invoice_amount != 0
and glc.SEGMENT1=16
group by
fvv.description,
glc.segment4
order by 2)a,
(SELECT
'AR' Mod,
rc.CUSTOMER_NAME customer_name,
rct.interface_header_attribute1 ar_won,
sum(rctl.extended_AMOUNT) revenue,
fvv.description branch1
FROM apps.ra_customer_trx_lines_all rctl,
apps.RA_CUST_TRX_LINE_GL_DIST_ALL rctg,
apps.fnd_flex_values_vl fvv,
apps.ra_customer_trx_all rct,
apps.ra_customers rc,
apps.RA_CUST_TRX_TYPES_ALL rctt,
apps.gl_code_combinations gcc
WHERE rctl.customer_trx_id = rct.customer_trx_id
and rct.BILL_TO_CUSTOMER_ID=rc.CUSTOMER_ID
and rct.CUSTOMER_TRX_ID=rctg.CUSTOMER_TRX_ID
and rctl.CUSTOMER_TRX_LINE_ID=rctg.CUSTOMER_TRX_LINE_ID
and rctt.CUST_TRX_TYPE_ID = rct.CUST_TRX_TYPE_ID
and gcc.CODE_COMBINATION_ID=rctg.CODE_COMBINATION_ID
AND gcc.segment2 = fvv.flex_value
AND fvv.flex_value_set_id = 1008015
and gcc.SEGMENT3 like '5%'
and rctg.ACCOUNT_CLASS='REV'
and rctl.line_type = 'LINE'
and rct.complete_flag='Y'
and rctg.gl_date between '01-jun-2010' and '10-jun-2010'
and rct.ORG_ID=92
group by fvv.description,rct.interface_header_attribute1,rc.CUSTOMER_NAME
order by 2)b
where a.ap_won=b.ar_won
and a.branch = b.branch1
group by branch,revenue,customer_name
order by 2
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Getting "ORA-00979: not a GROUP BY expression" error in Inline query
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satyaki>
satyaki>select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Prod
PL/SQL Release 10.2.0.1.0 - Production
CORE 10.2.0.1.0 Production
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
Elapsed: 00:00:00.02
satyaki>
satyaki>
satyaki>select e.empno,
2 e.ename,
3 AVG(e.SAL),
4 trunc(e.hiredate),
5 (
6 select sum(sal)
7 from emp
8 where hiredate = e.hiredate
9 ) salary
10 from emp e
11 group by e.DEPTNO,
12 e.EMPNO,
13 e.ENAME,
14 e.hiredate;
EMPNO ENAME AVG(E.SAL) TRUNC(E.H SALARY
7934 MILLER 1887.6 23-JAN-82 5583.6
7698 Glen 1848 23-JAN-82 5583.6
7788 SCOTT 598.95 19-APR-87 598.95
7900 JAMES 1379.4 03-DEC-81 6650.16
7521 WARD 226.88 22-FEB-81 226.88
7599 BILLY 4500 10-JUN-09 4500
2222 sp 1200 14-SEP-09 1200
7902 FORD 5270.76 03-DEC-81 6650.16
7566 Smith 1848 23-JAN-82 5583.6
7654 MARTIN 1815 28-SEP-81 1815
7839 KING 7260 17-NOV-81 7260
EMPNO ENAME AVG(E.SAL) TRUNC(E.H SALARY
7844 TURNER 2178 08-SEP-81 2178
7876 ADAMS 159.72 23-MAY-87 159.72
13 rows selected.
Elapsed: 00:00:00.03
satyaki>Regards.
Satyaki De. -
Hi all,
I think I'm being really stupid but I'm having SQL query issues.
I have a table with lots of lines of transactions which all refer to different stores, for example:
Store..............._Sales_............._Month_
Reading............200k..............April
Leeds...............50k................April
Manchester........70k................May
Reading............100k..............May
I need to come up with the average Sales for the combined months as a total. I.e. the average Store revenue for a given period is 200k+ 50k + 70k +100k / *3* (As there are only 3 unique stores) - hopefully this makes sense!
So essentially I am trying to do both a SUM query (and grouping by store) and then outputting the average of all stores together. Is this possible?
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This query returns 140 what seems to be the correct value:
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( select 'Reading' Store
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from dual
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from dataThere are multiple options:
1. You can get two IR's on one page (by using IFRAMEs - search for that word on the Forum)....
2. You create another region with the query above and position that just below the report
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Greetings,
Roel
http://roelhartman.blogspot.com/
http://www.bloggingaboutoracle.org/
http://www.logica.com/
You can award this reply to your question by marking it as either Helpful or Correct ;-) -
Hi all, hope in your help.
This is my table:
+----+--------+--------+
| id | field1 | field2 |
+----+--------+--------+
| 1 | A1 | 7 |
| 2 | B1 | 9 |
| 3 | C1 | 0 |
| 4 | D1 | 3 |
| 5 | A2 | 5 |
| 6 | B2 | 6 |
| 7 | C2 | 7 |
| 8 | D2 | 8 |
+----+--------+--------+I need this output:
+--------+--------------------+
| field1 | field2 |
+--------+--------------------+
| A2 | 19.230769230769200 |
+--------+--------------------+
| B2 | 23,076923076923100 |
+--------+--------------------+
| C2 | 26,923076923076900 |
+--------+--------------------+
| D2 | 30,769230769230800 |
+--------+--------------------+and tried this query
where calculate the value of single field1 (5,6,7,8) divided by the sum of field2 equal to A1, B2, C2 and D2 (26) :
A = 5/26 * 100 = 19
B = 6/26 * 100 = 23
C = 7/26 * 100 = 26
D = 8/26 * 100 = 30
SELECT
field1,
field2/Sum(field2)*100 as field2
FROM
`tbl_t`
WHERE
1
AND field1 IN ('A2', 'B2', 'C2', 'D2');
+--------+--------------------+
| field1 | field2 |
+--------+--------------------+
| A2 | 19.230769230769234 |
+--------+--------------------+But the ouput is not what I want, can you help me?
Thank you
Any help would be greatly appreciated.
Edited by: user13264840 on 25-mag-2013 10.33WITH data AS
( SELECT 1 id , 'A1' Field1 , 7 Field2 FROM dual
UNION ALL
SELECT 2 , 'B1' , 9 FROM dual
UNION ALL
SELECT 3 , 'C1' , 0 FROM dual
UNION ALL
SELECT 4 , 'D1' , 3 FROM dual
UNION ALL
SELECT 5 , 'A2' , 5 FROM dual
UNION ALL
SELECT 6 , 'B2' , 6 FROM dual
UNION ALL
SELECT 7 , 'C2' , 7 FROM dual
UNION ALL
SELECT 8 , 'D2' , 8 FROM dual
Group_data AS
(SELECT id ,
field1 ,
field2 ,
SUBSTR ( field1 , regexp_instr ( field1 , '[1234567890]' ) ) groupBy
FROM data
SELECT Field1 ,
ratio_to_report ( field2 ) over ( partition BY groupby ) * 100 "Field2"
FROM group_data; -
Hi!
I need to query the sum of a daily maximum value but I get an ORA-00936: missing expression with the following query. Why?
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Message was edited by:
Peter Gjelstrup -
Sql query : sum of feild between two conditional date
hi
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update emp
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select * from A a where a.x1 not in (select b.x1 from B b).
Is this possible using simple DBadapter by selecting "*perform an Operation on table*" by modifingt the Toplink in the jdeveloper.
any help in this highly appreciated.
Thanks and Regards,
Nagaraju .DHi,
You can use "perform an operation on table" and in the 8th Step replace the SQL statement by
select * from A a where a.x1 not in (select b.x1 from B b)
Regards,
Deepak Suri -
Sql Query : Sum , all the possible combination of rows in a table
SQL Server 2008 R2
Sample Table structure
create table TempTable
ID int identity,
value int
insert into TempTable values(6)
insert into TempTable values(7)
insert into TempTable values(8)
insert into TempTable values(9)
insert into TempTable values(10)
I actually want something like below,
that It returns rows such that, it has the sum of all the remaining rows , as shown below.
I will ignore the repeated rows.
6+7
6+8
6+9
6+10
6+7+8
6+7+9
6+7+10
6+8+9
6+8+10
6+9+10
6+7+8+9
6+7+8+9+10This makes no sense. What about NULLs? What about duplicate values? You have rows, so you have many combinations. We know that this set totals to 39, so there is no subset totals to half of any odd number. 19.5
in this case.
None of your examples are
even close!
6+7 = 13
the remaining rows 8+9+10 = 27, so you failed!
Want to try again?
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL
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