JDBC 2.0 help

Question

try
     Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver");
Connection con = DriverManager.getConnection("jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=Test;User=usr;Password=secret");
Statement stmt = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE);
String insertData = "Select * from users where UserID='123456'";
     ResultSet rs = stmt.executeQuery(insertData);
     rs.updateString("Name","Ashish");
     //rs.updateString("UserID","yyyasb3");
     rs.updateString("Dept","ACCT");
     rs.updateString("Aprv_Lvl","03");
     rs.updateString("Pwd","secret");
     rs.updateRow();
catch(Exception ex)
     out.println("The Exception is"+ex);
The above code gives me a SQL Exception: Invalid operation for the current cursor position

Answer 1

From the FIRST FEW sentences of the ResultSet API...
public interface ResultSet
A table of data representing a database result set, which is usually generated by executing a statement that queries the database.
A ResultSet object maintains a cursor pointing to its current row of data. Initially the cursor is positioned before the first row. The next method moves the cursor to the next row, and because it returns false when there are no more rows in the ResultSet object, it can be used in a while loop to iterate through the result set.