Login Applet Help

Question

Hello
I am trying to write a applet that allows me to login to a particular page on my site. I am new to java and have looked some books on the subject. I thought I would be able to manage it myself but I cant for the life of me do it.
Here is the code I have written:
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
<applet code="pass" width=300 height=80>
</applet>
public class pass extends Applet implements ActionListener{
     Label lbl1;
     Button btn1;
     TextField txa1;
     public void init(){
          lbl1= new Label("Please enter your password!");
          btn1= new Button("ok");
          txa1= new TextField("",20);
          add(txa1);
          add(btn1);
          add(lbl1);
          btn1.addActionListener(this);
     public void actionPerformed(ActionEvent ae){
          if(txa1 == 'will'){
          lbl1.setText("Password Accepted");
          //**GOTO A CORRECT URL
          else{
          lbl1.setText("Password Incorrect");
          //**GOTO REJECT URL
How can I get it to check the password entered? Also how the hell do get it to go to a URL???
Any help would be appreciated.
Regards
Jimmy

Answer 1

(1) Use the getText() method of TextField to get the data typed into the TextField. Returns a String
(2) Use the equals() method of class String to compare the String returned by the above with the password
(3) Use the Applet method getAppletContext() to return a reference to the browser.
(4) Use the AppletContext method showDocument() to redirect the browser to a new page.
public void actionPerformed(ActionEvent ae)
if(txa1.getText().equals("will"))
    lbl1.setText("Password Accepted");
    try
        URL url = new URL("http://www.thePageIwantToView.com");
        getAppletContext.showDocument(url);
    catch (MalformedUrlException muex)
       System.out.println(muex.toString());