Mapping every row to an idoc with same header

hi,
i have record:
recordset 1..1
Header 1..1
Row 0..unbounded
i want to map it to :
idoc 0...unbounded
Header 1..1
Row 1..1
i want every row in source will create an idoc. every idoc will have same header but different row.
can u please explain how do i do that?
thanks,
Tomer

Hi,
Map row node with IDOC node. It will create an IDOC per row.
Now map header node with header node. Between the header nodes you have to create a User defined function commonlly named CopyPerValue:
public Void copyPerValue (String[] a, String []b, ResultList result, Container container){
for (int i=0; i<a.length; i++){
result.addValue(b[0]);
You have to map row with a. And header with b.
Regards,
Carlos

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>
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<EDI_DC40>
<xsl:attribute name="SEGMENT">1</xsl:attribute>
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<RCVPRT>LS</RCVPRT>
</EDI_DC40>
<xsl:variable name="pid" select="substring(.,1,1)"/>
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Hi togehter,
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IR
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Hello
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<?xml version="1.0" encoding="UTF-8"?>
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<ns0:CostElementMT xmlns:ns0="http://se.com.sa/materials">
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            <OrgDescription> English Name<OrgDescription/>
            <Name>Arabic Name</Name>
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is this possible using the graphical mapping?

Hi Baheej,
If in your input "E1CSKTM" segment always occurs twice than u can go with the above UDF mentioned by Chirag and also u need to take care that field (LTEXT) also always occurs.If the field does not occur always than you need to check it using exists functions.
Andmoreover if the "E1CSKTM" segment does occur more than twice than u need to create a UDF where u need to pass the values alternatively.
Please check the above details and let us know if any furthur enhancements are to be made.
Thanks,
Bhargav
Note:Award Points if found useful.

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user9970447 wrote:
Hello Gurus ,
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